2 ques regarding hexadecimal numbers

[r i s h a b h s]

dear all, 1)how do i add hexadecimal numbers in vb (result too in hexadecimal numbers) 2) if there are 4 hexadecimal numbers say 0x40 0x80 0x1000 0x2000 and i have a number 0x10C2 (which is the hex sum of the top 3 numbers). now using such a number (which is the sum of any of the above hex numbers ) can i find which of the above numbers are included in the sum if it is ensured that a number is added only once. thnx in advance

[Richard Deeming]

1. In VB/VB.NET, hexadecimal numbers are prefixed with &H, not 0x. You use hex numbers in exactly the same way as decimal numbers, e.g. Dim i As Integer = &H40 + &H80. To print the result as a hex number, use i.ToString("X") in VB.NET, or Hex(i) in VB6.

2. The sum of the first three numbers is 10C0, not 10C2. You can use the And operator to find the numbers. For example:

   Dim number As Integer = &H10C0
   Dim sum As String
   Dim i As Integer
   i = 1

   Do While number > 0
   If 0 <> (number And i) Then
   If Len(sum) > 0 Then sum = sum & " + "
   sum = sum & Hex(i)
   number = number - i
   End If
   i = i * 2
   Loop

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"These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

[Richard Deeming]

rishabhs wrote: thanx for ur reply Richard! [rose] but the code u gave me doesn't returns all the numbers which r added to get the number &H10C0 plz. help me understand the logic of this job I fixed a typo in my previous post, which should give you the correct result. [You need sum = sum + Hex(**i**), not sum = sum + Hex(number). :-O] The code walks through each binary bit of the number, and tests to see if that bit is set, using the bitwise And operator. [0 <> (number And i)]. If the bit is set, it appends the hex representation of the bit to a string.

0x10C0 = 0001 0000 1100 0000

   = 0000 0000 0100 0000
   + 0000 0000 1000 0000
   + 0001 0000 0000 0000

   = 0x0040
   + 0x0080
   + 0x1000

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"These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

[r i s h a b h s]

thanx a lot :) :rose: