dither.c:16:9: error: too few arguments to function ‘fwrite’ ?can anyone help

mybm1

Quote:

#include
#include

int main(int argc, char *argv[])
{
srand(12345);
// srand((unsigned int)time(NULL));

float a = 5.0;
int i;
for (i=0;i<63530;i++) // condition for displaying number of the random number for here 63530
    printf("%f\\n", ((float)rand()/(float)(RAND\_MAX)) \* a); //rand return integer value from 0 to RAND\_MAX(system dependent) 
      FILE \*fout;
    //fout=fopen("random generated number","w");
     const char \*text=("write this text to file");
    fwrite(fout,((float)rand()/(float)(RAND\_MAX)) \* a,text);
return 0;

}

Jochen Arndt

See http://www.cplusplus.com/reference/cstdio/fwrite/[^] and check your passed parameters. You should have a look at the fprintf function which may be better for your purposes (writing to text file).

mybm1

even though I pass fwrite(fout,((float)rand()/(float)(RAND_MAX)) *a,text); it is generating the file.txt but null value on it..

mybm1

same problem no change :(

Jochen Arndt

You must read the documentation and understand the type and meaning of the different parameters. The fwrite function has four parameters but you are passing only three. Additionally, your parameters did not match the required types. The first parameter is a pointer to the binary data to be written. But you are passing the pointer to your FILE stream object. The second and third parameters specify the amount of data to be written and the last one is the FILE pointer. To write a binary floating point value you might use:

float f = ((float)rand()/(float)(RAND_MAX)) * a;
fwrite(&f, sizeof(float), 1, fout);

To write data to a text file use fprintf like printf passing the FILE pointer as first parameter.

mybm1

thank you finally I got it..