how to use delegate to call function and introduce function as content?

smallkubi

Thank you very much,it 's near my requirement. But one more requirement is that: static void fun1(int x, Action call) { call(); } take fun3(y,z) for example, call() is run fun3(y,z). but if i want to run fun3(x,z) ,how to realize it? you know ,i want to change y value in fun1 to call fun2(int y) or fun3(int y,int z),because my code use loop to change y value in fun1,to let fun2 or fun3 be a minimum value.

Richard Deeming

So something like this:

static void Main()
{
int x = 1;
int z = 3;
fun1(x, y => fun2(y));
fun1(x, y => fun3(y, z));
}

static void fun1(int x, Action<int> call)
{
call(x);
}

static void fun2(int y) { ... }
static void fun3(int y, int z) { ... }

"These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

smallkubi

Great Job!!! Thank you very much. And i have other question bothering me. I have to use chart control to plot 10 series including 1000 points per series in one chartarea. But after ploting, mouse move or zoom in or ContextMenuStrip operation is very slow and delay. I think maybe paint problem. When i ask before, i get the answer is point number is too big. But i found that if i plot 200 series with 1 point for example as follows, the operation is also slow. How can treat it? follows is for example: Series series1; for(int i=0;i<200;i++) { series1=new series(); series1.Points.Add(new DataPoint(i,i)); chart1.Series.Add(series1); }

Lost User

smallkubi wrote:

I think maybe paint problem.

Why?

smallkubi wrote:

When i ask before, i get the answer is point number is too big.

The more points you need to draw, the longer it takes. If there had been a useless delay in the chart-control, people would have noticed.

Bastard Programmer from Hell :suss: If you can't read my code, try converting it here[^][](X-Clacks-Overhead: GNU Terry Pratchett)

smallkubi

I mean Dalay is not that Chart generating process is slow, when i finished plot, i want to operate on Chart, like mouse moving, Scroll... is slow.

Lost User

Meaning it will have to recalculate which part it should show and repaint it. That takes time. Smaller charts with less points will be faster. If you find that the Chart-control is "too slow" for your needs, you may have to implement your own.

Bastard Programmer from Hell :suss: If you can't read my code, try converting it here[^][](X-Clacks-Overhead: GNU Terry Pratchett)

smallkubi

oh, do you know how to stop control auto refresh? i think if i can refresh it in mannual?

Lost User

Stop the user from scrolling, panning and/or zooming, and you don't need to refresh. If anything changes, a refresh would be required to get the updated data on screen.

Bastard Programmer from Hell :suss: If you can't read my code, try converting it here[^][](X-Clacks-Overhead: GNU Terry Pratchett)

smallkubi

Now i want to have the function of Zooming,scrolling... Anything changes, screen don't update automatically,I want to updated data on screen mannully, can it be possible?

Lost User

Sure; use the drawing functions to draw your chart. Means writing code to calculate the length of the axes, drawing each point, drawing some labels.

Bastard Programmer from Hell :suss: If you can't read my code, try converting it here[^][](X-Clacks-Overhead: GNU Terry Pratchett)

smallkubi

Hi, i have another question... If i want to use multi-thread to call fun1, how can i input the variable x, y,z? for example: static void Main() { int x = 1; int z = 3; Thread th=new Thread(fun1( ? )) //how can i do ? th.start(); // fun1(x, y => fun2(y)); // fun1(x, y => fun3(y, z)); } static void fun1(int x, Action call) { call(x); } static void fun2(int y) { ... } static void fun3(int y, int z) { ... }

Richard Deeming

Something like this:

Thread th = new Thread(() => fun1(x, y => fun3(y, z)));

Breaking it down:

Action<int> call = y => fun3(y, z);
ThreadStart start = () => fun1(x, call);
Thread th = new Thread(start);

"These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

smallkubi

Good Idea,i meet it. And if i have a button at main Thread , it can abort Thread "th". How to code button click function? And, if whether Thread th end or abort, i want to run" MessageBox.Show("Thread end")", how can i do it?

Richard Deeming

smallkubi wrote:

it can abort Thread "th"

Don't. How To Stop a Thread in .NET (and Why Thread.Abort is Evil)[^] If you're using .NET 4.5 or above, you'd probably have better luck using async and await. Asynchronous Programming with Async and Await (C# and Visual Basic)[^] Otherwise, use something like the BackgroundWorker component[^].

"These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

smallkubi

hi, If i use Func call= y=>fun3(y,z) , fun3 can be one output param function. But if my function need 2 or more output, how can i do it?

Richard Deeming

Sorry, I'm not following you. Do you mean you want multiple return values from your function? If so, you'll need to create a class or structure to contain them:

public struct Fun3ReturnValues
{
public int SomeValue { get; set; }
public string SomeOtherValue { get; set; }
}
...
public static Fun3ReturnValues Fun3(int y, int z)
{
return new Fun3ReturnValues
{
SomeValue = 42,
SomeOtherValue = "Hello",
};
}

Alternatively, you could use the Tuple class[^], but the meaning of the values wouldn't be as clear.

"These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer