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  4. how to use delegate to call function and introduce function as content?

how to use delegate to call function and introduce function as content?

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  • L Lost User

    Meaning it will have to recalculate which part it should show and repaint it. That takes time. Smaller charts with less points will be faster. If you find that the Chart-control is "too slow" for your needs, you may have to implement your own.

    Bastard Programmer from Hell :suss: If you can't read my code, try converting it here[^][](X-Clacks-Overhead: GNU Terry Pratchett)

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    smallkubi
    wrote on last edited by
    #14

    oh, do you know how to stop control auto refresh? i think if i can refresh it in mannual?

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    • S smallkubi

      oh, do you know how to stop control auto refresh? i think if i can refresh it in mannual?

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      L Offline
      Lost User
      wrote on last edited by
      #15

      Stop the user from scrolling, panning and/or zooming, and you don't need to refresh. If anything changes, a refresh would be required to get the updated data on screen.

      Bastard Programmer from Hell :suss: If you can't read my code, try converting it here[^][](X-Clacks-Overhead: GNU Terry Pratchett)

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      • L Lost User

        Stop the user from scrolling, panning and/or zooming, and you don't need to refresh. If anything changes, a refresh would be required to get the updated data on screen.

        Bastard Programmer from Hell :suss: If you can't read my code, try converting it here[^][](X-Clacks-Overhead: GNU Terry Pratchett)

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        S Offline
        smallkubi
        wrote on last edited by
        #16

        Now i want to have the function of Zooming,scrolling... Anything changes, screen don't update automatically,I want to updated data on screen mannully, can it be possible?

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        • S smallkubi

          Now i want to have the function of Zooming,scrolling... Anything changes, screen don't update automatically,I want to updated data on screen mannully, can it be possible?

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          Lost User
          wrote on last edited by
          #17

          Sure; use the drawing functions to draw your chart. Means writing code to calculate the length of the axes, drawing each point, drawing some labels.

          Bastard Programmer from Hell :suss: If you can't read my code, try converting it here[^][](X-Clacks-Overhead: GNU Terry Pratchett)

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          • Richard DeemingR Richard Deeming

            So something like this:

            static void Main()
            {
            int x = 1;
            int z = 3;
            fun1(x, y => fun2(y));
            fun1(x, y => fun3(y, z));
            }

            static void fun1(int x, Action<int> call)
            {
            call(x);
            }

            static void fun2(int y) { ... }
            static void fun3(int y, int z) { ... }


            "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

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            smallkubi
            wrote on last edited by
            #18

            Hi, i have another question... If i want to use multi-thread to call fun1, how can i input the variable x, y,z? for example: static void Main() { int x = 1; int z = 3; Thread th=new Thread(fun1( ? )) //how can i do ? th.start(); // fun1(x, y => fun2(y)); // fun1(x, y => fun3(y, z)); } static void fun1(int x, Action call) { call(x); } static void fun2(int y) { ... } static void fun3(int y, int z) { ... }

            Richard DeemingR 1 Reply Last reply
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            • S smallkubi

              Hi, i have another question... If i want to use multi-thread to call fun1, how can i input the variable x, y,z? for example: static void Main() { int x = 1; int z = 3; Thread th=new Thread(fun1( ? )) //how can i do ? th.start(); // fun1(x, y => fun2(y)); // fun1(x, y => fun3(y, z)); } static void fun1(int x, Action call) { call(x); } static void fun2(int y) { ... } static void fun3(int y, int z) { ... }

              Richard DeemingR Offline
              Richard DeemingR Offline
              Richard Deeming
              wrote on last edited by
              #19

              Something like this:

              Thread th = new Thread(() => fun1(x, y => fun3(y, z)));

              Breaking it down:

              Action<int> call = y => fun3(y, z);
              ThreadStart start = () => fun1(x, call);
              Thread th = new Thread(start);


              "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

              "These people looked deep within my soul and assigned me a number based on the order in which I joined" - Homer

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              • Richard DeemingR Richard Deeming

                Something like this:

                Thread th = new Thread(() => fun1(x, y => fun3(y, z)));

                Breaking it down:

                Action<int> call = y => fun3(y, z);
                ThreadStart start = () => fun1(x, call);
                Thread th = new Thread(start);


                "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

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                smallkubi
                wrote on last edited by
                #20

                Good Idea,i meet it. And if i have a button at main Thread , it can abort Thread "th". How to code button click function? And, if whether Thread th end or abort, i want to run" MessageBox.Show("Thread end")", how can i do it?

                Richard DeemingR 1 Reply Last reply
                0
                • S smallkubi

                  Good Idea,i meet it. And if i have a button at main Thread , it can abort Thread "th". How to code button click function? And, if whether Thread th end or abort, i want to run" MessageBox.Show("Thread end")", how can i do it?

                  Richard DeemingR Offline
                  Richard DeemingR Offline
                  Richard Deeming
                  wrote on last edited by
                  #21

                  smallkubi wrote:

                  it can abort Thread "th"

                  Don't. How To Stop a Thread in .NET (and Why Thread.Abort is Evil)[^] If you're using .NET 4.5 or above, you'd probably have better luck using async and await. Asynchronous Programming with Async and Await (C# and Visual Basic)[^] Otherwise, use something like the BackgroundWorker component[^].


                  "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

                  "These people looked deep within my soul and assigned me a number based on the order in which I joined" - Homer

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                  • Richard DeemingR Richard Deeming

                    Something like this:

                    Thread th = new Thread(() => fun1(x, y => fun3(y, z)));

                    Breaking it down:

                    Action<int> call = y => fun3(y, z);
                    ThreadStart start = () => fun1(x, call);
                    Thread th = new Thread(start);


                    "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

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                    smallkubi
                    wrote on last edited by
                    #22

                    hi, If i use Func call= y=>fun3(y,z) , fun3 can be one output param function. But if my function need 2 or more output, how can i do it?

                    Richard DeemingR 1 Reply Last reply
                    0
                    • S smallkubi

                      hi, If i use Func call= y=>fun3(y,z) , fun3 can be one output param function. But if my function need 2 or more output, how can i do it?

                      Richard DeemingR Offline
                      Richard DeemingR Offline
                      Richard Deeming
                      wrote on last edited by
                      #23

                      Sorry, I'm not following you. Do you mean you want multiple return values from your function? If so, you'll need to create a class or structure to contain them:

                      public struct Fun3ReturnValues
                      {
                      public int SomeValue { get; set; }
                      public string SomeOtherValue { get; set; }
                      }
                      ...
                      public static Fun3ReturnValues Fun3(int y, int z)
                      {
                      return new Fun3ReturnValues
                      {
                      SomeValue = 42,
                      SomeOtherValue = "Hello",
                      };
                      }

                      Alternatively, you could use the Tuple class[^], but the meaning of the values wouldn't be as clear.


                      "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

                      "These people looked deep within my soul and assigned me a number based on the order in which I joined" - Homer

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