XSL to get only elements which have no childs

MrKBA

Hi, I make my question after some research in web without any clear response to my problem. I have the following XML and I need to apply an XSL transformation to get only nodes which haven't child. Input :

Expected output :

Richard Deeming

Something like this should work:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="Root_Element">
<xsl:element name="{name()}">
<xsl:apply-templates select="*|@*"/>
</xsl:element>
</xsl:template>

<xsl:template match="\*">
    <xsl:choose>
        <xsl:when test="count(\*) = 0">
            <xsl:element name="{name()}">
                <xsl:apply-templates select="@\*"/>
            </xsl:element>
        </xsl:when>
        <xsl:otherwise>
            <xsl:apply-templates select="\*" />
        </xsl:otherwise>
    </xsl:choose>
</xsl:template>

<xsl:template match="@\*">
    <xsl:attribute name="{name()}">
        <xsl:value-of select="."/>
    </xsl:attribute>
</xsl:template>

</xsl:stylesheet>

"These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

MrKBA

Yes thank you it works but how can I keep the root element please ? I means the (

)

MrKBA

Yes great, thank you.