passing parameters to Cdialog

[Sascha Lefevre]

What kind of warning?

If the brain were so simple we could understand it, we would be so simple we couldn't. — Lyall Watson

[Lost User]

What is the definition of your RTMDialog constructor?

[ForNow]

progDebug.cpp(356): warning C4930: 'RTMDialog Abenddialog(LPARAM,CWnd *)': prototyped function not called (was a variable definition intended?)

Here is the source

RTMDialog Abenddialog(LPARAM mylparam, CWnd* pParent /*=NULL*/);

[ForNow]

class RTMDialog : public CDialog
{
DECLARE_DYNAMIC(RTMDialog)

public:
RTMDialog(LPARAM mylparam,CWnd* pParent = NULL); // standard constructor

[Sascha Lefevre]

This is a bit of a shot in the dark from me but I think you ran into the Most vexing parse - Wikipedia[^] This line:

RTMDialog Abenddialog(LPARAM mylparam, CWnd* pParent /*=NULL*/);

..has the signature of a function declaration but the name and arguments of your class constructor. I'm a bit confused about where it could be "located" as you've shown your class declaration with a proper constructor declaration and the proper (beginning) of the constructor implementation. Maybe it's just needless?

If the brain were so simple we could understand it, we would be so simple we couldn't. — Lyall Watson

[Rick York]

If this is truly "source" as in the .cpp file then I think the problem is the semicolon.

[Lost User]

That is a function declaration which takes two parameters and returns an RTMDialog object. Firstly, is that what you wanted, and secondly, what is this to do with your original question? Where exactly in your code is this declaration?

[Jochen Arndt]

Compiler Warning (level 1) C4930[^]:

C4930 can also occur when the compiler cannot distinguish between a function prototype declaration and a function call.

It looks like that is the case here and you wanted to create a dialog. Then it must be something like

RTMDialog Abenddialog(some_lparam, this);

[David Crow]

So where's the problem?

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[ForNow]

I had typo with the parameters thanks