array and pointer

[Anonygeeker]

I want to print elements of array a. My print fun is : void print(int *a){ int i; for(i=0;i<3;i++){ printf("%d\n",a[i]); } } which works fine. But if I give : void print(int *a[]){ int i; for(i=0;i<3;i++){ printf("%d\n",a[i]); } } (array a[] defined in main.) its not working.What makes the difference?

[Rick York]

The difference is in the prototypes : void print(int *a) vs void print(int *a[]) The first takes a pointer to integer. The second takes an array of pointers to integers. To make the second function work you have to dereference a pointer : printf( "%d\n", *a[i] );

[CPallini]

the equivalent of

void print(int *a)

with array notation is

void print(int a[])

[cao_aba3]

void print(int *a[]): It looks like a 2 dimensional array I think so. ;)

[Lost User]

No, it's a one-dimensional array of pointers.