In type conversion of 2 different classes can i convert both ways ?

Tarun Jha

i want to make a program that can convert from class a type to class b & vice versa.. i already made a program that does one type of conversion..

//define 2 classes polar & rectangle to represent points int the polar & rectanglular system.
#include
#include
using namespace std;

class Polar;

//====================================================
class Rectangle{
float length, bredth;
public:
Rectangle(){}
Rectangle(float ,float);

/\*
  operator Polar(){
    Polar temp;
    float a = atan(length/bredth), r = sqrt(x\*x + y\*y);
    temp.getAngle(a);
    temp.getRadius(r);

    return(temp);
}
\*/

int getLength(){return(length);}
int getBredth(){return(bredth);}
void putLength(float x){length = x;}
void putBredth(float y){bredth = y;}

void putData(){cout<<"Length : "<

as in the above code i have converted class Polar to class Rectangle, but i also want to have a conversion of class Rectangle to class Polar.

Thank you

Victor Nijegorodov

Tarun Jha wrote:

as in the above code i have converted class Polar to class Rectangle,

Did you test it? Does it work? I ask because I see neither the assignment operator

Rectangle& Rectangle::operator =(const Polar& polar)

nor the ctor to create Rectangle instance from the Polar one... :confused:

CPallini

#include #include using namespace std;

class Polar;

//====================================================
class Rectangle
{
float length, bredth;
public:
Rectangle(){}
Rectangle(float ,float);

operator Polar();

int getLength(){return(length);}
int getBredth(){return(bredth);}
void putLength(float x){length = x;}
void putBredth(float y){bredth = y;}

void putData(){cout<<"Length : "<rectangle->polar
Polar p1(radians, 25);
p1.putData();

Rectangle r1 = p1;
r1.putData();

Polar p2 = r1;
p2.putData();

return 0;
}

Tarun Jha

thank you :)

Tarun Jha

but i am not using any variables with reference to heap, so i thought it shouldn't be needed for ex:- new, *variable etc.

CPallini

You are welcome.