Managed c++ how to memcpy a handle reference
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how do you copy the bytes of a managed variable to another managed variable? memcpy doesn't work since my arguments are not the correct type for memcpy
#include "string.h" //Updated Solution
float^ f = gcnew (float);
unsigned int^ temp = gcnew(unsigned int);
*temp = 0;
*temp = _byte3;
*temp = (*temp << 8U) + _byte2;
*temp = (*temp << 8U) + _byte1;
*temp = (*temp << 8U) + _byte0// memcpy(f, temp,4U); //error
**//Updated solution :
pin\_ptr pinPtr\_FloatVal = &(\*f); pin\_ptr pinPtr\_UintVal = &(\*temp); memcpy\_s(pinPtr\_FloatVal , 4U, pinPtr\_UintVal , 4U); //4U i.e. 4 bytes** -
how do you copy the bytes of a managed variable to another managed variable? memcpy doesn't work since my arguments are not the correct type for memcpy
#include "string.h" //Updated Solution
float^ f = gcnew (float);
unsigned int^ temp = gcnew(unsigned int);
*temp = 0;
*temp = _byte3;
*temp = (*temp << 8U) + _byte2;
*temp = (*temp << 8U) + _byte1;
*temp = (*temp << 8U) + _byte0// memcpy(f, temp,4U); //error
**//Updated solution :
pin\_ptr pinPtr\_FloatVal = &(\*f); pin\_ptr pinPtr\_UintVal = &(\*temp); memcpy\_s(pinPtr\_FloatVal , 4U, pinPtr\_UintVal , 4U); //4U i.e. 4 bytes**[c++ cli - Memcpy of native array to managed array in C++ CLI - Stack Overflow](https://stackoverflow.com/questions/6944288/memcpy-of-native-array-to-managed-array-in-c-cli)
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[c++ cli - Memcpy of native array to managed array in C++ CLI - Stack Overflow](https://stackoverflow.com/questions/6944288/memcpy-of-native-array-to-managed-array-in-c-cli)
Hello, I am trying to memcpy two managed values. The link provided seem to be for unmanaged to managed? Could you show an example how to achieve this? Thanks!
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Hello, I am trying to memcpy two managed values. The link provided seem to be for unmanaged to managed? Could you show an example how to achieve this? Thanks!
Are you banned by Google? :confused: [memcpy in managed c /cli - Google Search](https://www.google.com/search?q=memcpy+in+managed+c%2B%2B%2Fcli&newwindow=1&rlz=1C1CHBF\_enDE886DE886&sxsrf=ALeKk033wPoCX2qWMAvCFyUkfnZmOYBonA%3A1622197366259&ei=dsSwYJ6vD6PAlAaA84PgAg&oq=memcpy+in+managed+c%2B%2B%2Fcli&gs\_lcp=Cgdnd3Mtd2l6EAMyCAghEBYQHRAeOgcIABBHELADOgcIABCwAxBDOgQIABBDOgIIADoHCAAQhwIQFDoGCAAQFhAeOggIABAWEAoQHjoFCCEQoAE6BwghEAoQoAFQkhJYn1xggF9oAXACeACAAZYBiAG6C5IBBDE4LjKYAQCgAQGqAQdnd3Mtd2l6yAEKwAEB&sclient=gws-wiz&ved=0ahUKEwiewpWOlOzwAhUjIMUKHYD5ACwQ4dUDCA4&uact=5)
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Hello, I am trying to memcpy two managed values. The link provided seem to be for unmanaged to managed? Could you show an example how to achieve this? Thanks!
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The link that Victor gave you shows how to get a pointer to a managed object in order to copy data into it. So all you need is two such pointers in order to copy managed to managed.
Thank you very much Richard for elaborating a bit on this! I have solved my problem !
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how do you copy the bytes of a managed variable to another managed variable? memcpy doesn't work since my arguments are not the correct type for memcpy
#include "string.h" //Updated Solution
float^ f = gcnew (float);
unsigned int^ temp = gcnew(unsigned int);
*temp = 0;
*temp = _byte3;
*temp = (*temp << 8U) + _byte2;
*temp = (*temp << 8U) + _byte1;
*temp = (*temp << 8U) + _byte0// memcpy(f, temp,4U); //error
**//Updated solution :
pin\_ptr pinPtr\_FloatVal = &(\*f); pin\_ptr pinPtr\_UintVal = &(\*temp); memcpy\_s(pinPtr\_FloatVal , 4U, pinPtr\_UintVal , 4U); //4U i.e. 4 bytes**//Assuming int is on 4 bytes typedef union u { int i; byte b[4]; } U; U x; x.b[0] = 0 // Put first byte here x.b[1] = 0 // second byte here, etc. // Then use x.i as an integer // Keep in mind that on Intel CPUs, integer values are represented in memory in reverse order. // This means that hex value 0x11223344 will be represented in memory as 0x44, 0x33, 0x22, 0x11 // This is called little-endian vs. big-endian representation. // There can be CPUs that uses the other convention. // Make a small test project and play around with some values etc.