Problem creating an array of "class"

[Roberto64_Ge]

i do not know how to quote a previous answer. Anyway you suggested me to use a pointer to an array of pointers so we did anagrafica **Arr_ = new anagrafica*[N]; But in this case compiler didn't let me access the method in this way : Arr_[i].setChiave(3); For that reason I asked for the correct syntax. Meanwhile I was waiting your reply I decided to try and so I went back to the first version temporarily and this is working, with respect to my first question " why I cannot see all the array elements?". With this I mean that, also with my first version, if I access Arr_[i] during the debug (within the relevant window "Control expression". I guess this is the correct translation from Italian) I see all the different instances of the class in each element of the array Arr_. I attach here the code of the first version. With this version running then I get a new malfunction that is that when I call the method for cifrating the true name and surname, from within this method I call the two methods to set the name and the surname, setNome and setCognome but this has no effects. If preferred I will attach the complete solution.

anagrafica* Arr_ = new anagrafica[N];

for (int i = 0; i < N; i++)
{
Arr_[i] = anagrafica("ciao", "miao", i*25);
}

for (int i=0; i>chiave;
file>>n;
file>>c;
Arr_[i].setChiave(chiave);
cod(Arr_[i],n,c,chiave);
}
for (int i=0; i

[Lost User]

Arr_[i].setChiave(3);

Sorry, I misread that. Arr_[i] is a pointer so you need to use the correct pointer dereferencing syntax:

Arr_[i]**->**setChiave(3);

[Roberto64_Ge]

Ok , so the syntax is not Arr_[i].setChiave(3) but

Arr_[i]->setChiave(3)

as per Greg Utas and your new indication. As I wrote I would say that also the version

anagrafica* Arr_ = new anagrafica[N];

for (int i = 0; i < N; i++)
{
Arr_[i] = anagrafica("ciao", "miao", i*25);
}

is working the same. Then I have the further problem of the two methods for setting cifrated name and surname tha have no effects. I see that there is some problem of synchronizations with the replies. But ok syntax has been clarified.

[Roberto64_Ge]

Ok i realized that. thank you very much. What about the other problem? Methods ....

[Roberto64_Ge]

Clarified the syntax problem I resume here. The code works also in this way ::

anagrafica* Arr_ = new anagrafica[N];

for (int i = 0; i < N; i++)
{
Arr_[i] = anagrafica("ciao", "miao", i*25);
}

for (int i=0; i>chiave;
file>>n;
file>>c;
Arr_[i].setChiave(chiave);
cod(Arr_[i],n,c,chiave);
}
for (int i=0; i

Because I can see all the Arr_ elements containing instances of the class. But two methods recalled from one other method do not heve effects.

[Lost User]

You have declared a number of methods in your header file but you have not added their implementation to the .cpp source. In my sample code above you can see the implementation for the setChiave method. You need to do the same for all the other methods declared in the class.

[Roberto64_Ge]

I attach the method file .cpp

#include "Anagrafica.h"
#include
#include

using namespace std;

anagrafica::anagrafica(string name,string surname, int key)
{
nome_cifrato=name;
cognome_cifrato=surname;
chiave_cifratura=key;
}

void anagrafica::setNome(string n_)
{
nome_cifrato=n_;
}
void anagrafica::setCognome(string c_)
{
cognome_cifrato=c_;
}

string anagrafica::getNome()
{
return nome_cifrato;
}
string anagrafica::getCognome()
{
return cognome_cifrato;
}

int anagrafica::getChiave()
{
return chiave_cifratura;
}

void anagrafica::setChiave(int c)
{
chiave_cifratura=c;
}

void anagrafica::stampa()
{
string nom = nome_cifrato;
string cog = cognome_cifrato;
cout<<" nome cifrato "<

I can't understand where is the

[Lost User]

I think this thread is getting confused (I certainly am). I suggest you start a new thread and post the actual code that you are now using, and explain what methods do not work.

[Greg Utas]

Those lines have no effect because the default in C++ is to pass an argument by value. That is, to make a copy of it. If you want to modify the data that is passed to the function, it must be passed by reference; another option is to pass a pointer to the argument. To pass by reference, you append a & to the argument's type. So, you need to change your two small functions like this:

void anagrafica::setNome(string**&** n_)
{
nome_cifrato=n_;
}

void anagrafica::setCognome(string**&** c_)
{
cognome_cifrato=c_;
}

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[Roberto64_Ge]

header

#include
#include
using namespace std;

class anagrafica
{
private:

string nome_cifrato;
string cognome_cifrato;
int chiave_cifratura;

public :

anagrafica(string ="", string ="", int=0); //costruttore

void setNome(string );

void setCognome(string );

string getNome();

string getCognome();

void codifica(string , string , int );

void decodifica();

void setChiave(int);

int getChiave();

void stampa();

};

methods

#include "Anagrafica.h"
#include #include using namespace std;

anagrafica::anagrafica(string name,string surname, int key)
{
nome_cifrato=name;
cognome_cifrato=surname;
chiave_cifratura=key;
}

void anagrafica::setNome(string n_)
{
nome_cifrato=n_;
}
void anagrafica::setCognome(string c_)
{
cognome_cifrato=c_;
}

string anagrafica::getNome()
{
return nome_cifrato;
}
string anagrafica::getCognome()
{
return cognome_cifrato;
}

int anagrafica::getChiave()
{
return chiave_cifratura;
}

void anagrafica::setChiave(int c)
{
chiave_cifratura=c;
}

void anagrafica::stampa()
{
string nom = nome_cifrato;
string cog = cognome_cifrato;
cout<<" nome cifrato "<setNome(nome_cifrato);
for (int i=0; isetCognome(cognome_cifrato);
}

void anagrafica::decodifica()
{

char car;
string nome_chiaro = "";
string cognome_chiaro = "";
for (int i=0;i

[Lost User]

You need to execute that code through the debugger to see exactly what is happening. I tried to reproduce it and it was passing blank parameters in to the method. I suspect that the problem is where you are reading values from the input file. [edit] That method is modifying both variables nome_cifrato and cognome_cifrato inline, and you then call setNome and setCognome. But you have already modified the names so you do not need to call the setter methods. I think you need to look more closely at the design of this application and remove some of the redundancies.

[Lost User]

That will not make any difference. I have just tested the code and those methods both do what they are supposed to. The issue is more complex due to the confused (and confusing) nature of this code.

[Roberto64_Ge]

Ok you are right saying that

Richard MacCutchan wrote:

That method is modifying both variables nome_cifrato and cognome_cifrato inline, and you then call setNome and setCognome. But you have already modified the names so you do not need to call the setter methods.

I didn't see it, I get confused writing the code, probably I inteded to use local variables to build cifrated name and surname. But problem was in this function within the main

void cod (anagrafica arr,string n, string c,int chiave)
{

arr.codifica(n,c,chiave);

}

that i re-arranged this way

void cod (anagrafica &arr,string n, string c,int chiave)
{

arr.codifica(n,c,chiave);

}

passing the address to "cod". And about this, I understood the reason (Greg Utas was right about the rules but didn't apply to the real problem because i did not need to change the strings passed to the methods but the instance of the class itself). But now there is another behaviour that confuses me : In a previous version the following method :

void anagrafica::stampa()
{
cout<<" nome cifrato "<

I had to modify in this new version :

void anagrafica::stampa()
{
string nom = nome_cifrato;
string cog = cognome_cifrato;
cout<<" nome cifrato "<

because in the first version it was just printing nothing. Now it prints correctly. I just tried without a real knowledge behind, only some kind of sensation but I don't understand why it didn't work before and why it works now.

Anyway thanks for all the efforts/suggestions. I am just starting with c++ in order to help my children in their school exercise.

[Lost User]

Roberto64_Ge wrote:

I am just starting with c++ in order to help my children in their school exercise.

Well, I am sorry to have to say this, but what you have created is not a good example of C++ code for them to follow. The two static methods cod and decod serve no purpose other than to call the actual methods of the anagrafica class. So they are totally redundant; you could call the codifica method direct from main. There are a number of other issues that look incorrect to me but I do not have time to teach you C++.

[Roberto64_Ge]

That was a request (strange to me too. Exercise : implement a function that calls the methods ..., not directly in the main. Could also be that it was some type of cut and paste from other exercises so some error in the exercise definition ). As I said I am starting too so I do what I can and for that reason I am writing here otherwise why should I do this (to ask a forum)? Then I think that everyone is doing something makes mistakes some for distraction (some I did here) and some for poor knowledge (and also here). But going straight to my last question is there an explanation? Regards

[Lost User]

I have no idea where that question came from or what it actually says. But I would assume that if you want an explanation then the place where you found it is the best place to ask. The forums here are more for help in diagnosing and fixing specific problems. There are other sites that offer well written tutorials, such as Learn C++ – Skill up with our free tutorials[^] and C++ Tutorial[^].