HHEELLPP!!!

[Sunnygirl]

hello @all, i want to have a string with n letters. my program provided these letters by coincidence. for example: i want to have a string with a length of 1000. i enter this in my dialog, that i want to have a string with 1000 letters. Now, these 1000 letters (e.g. from the letters ABCD) must be provided by coincidence. after that, the string should look (e.g.) like that: CString str="AAABBCDDDABBCDDACCDD...." how can i program a programm with this function? can anybody help me? thank you very much! sunny

[noksi]

Hi, I suggest you 2 solutions First: CString strMyWord = ""; int iSizeOfMyString = GetSizeFromDialog(); for (int i=0; i

[Terry ONolley]

If I understand you correctly, you want to allow the user to specify the length of the string and the string itself will be composed of a random assortment of the letters A-D. Assuming that the length of the string is passed to this function as nStringLength, you could try: CString GetString(int nStringLength) { char* buff; // holds chars as they are assigned int index = 0; // index for moving through buff char ch; // the current char CString csResult; // the resulting, finished string buff = malloc(nStringLength + 1); // allocate the memory for your string srand(1); // seed the random number generator while(index < nStringLength) // loop through as many times as required { ch = char((rand() % 4) + 65); // get a random number and get it's modulus 4 // (ie numbers from 0 to 3). Add 65 to it to arrive // at the ascii values corresponding to A,B,C & D buff[index] = ch; // add the new character to the string index++; // increment the index } buff[index] = '\0'; // Add the null terminator to the string csResult = buff; return csResult; } I'm going to live forever or die trying!