Passing in Function name to be called

[obelisk29]

Is there any way to have a function that accepts a function name as a parameter and is then able to call it? EXAMPLE: public void MyFunc(Function func) { func(); } Help is greatly appreciated.

[azusakt]

May be you can use Delegate and pass out delegate function.

[Nick Parker]

The following is a quick example of a delegate in C#.

using System;

namespace Test
{
	class Class1
	{
		delegate void Func(int i);

		static void Main(string[] args)
		{
			Func f = new Func(SomeMethod);
			f(4);
		}

		public static void SomeMethod(int i)
		{
			Console.WriteLine("Hello from SomeMethod. " +
					  i + " was passed in.");
			Console.Read();
		}
	}
}

-Nick Parker DeveloperNotes.com

[Corinna John]

Call the funcitzon "by name": public void MyFunc(Function func) { //get the type of the object containing the method Type type = this.GetType(); //get the method System.Reflection.MethodInfo methodInfo = type.GetMethod(func, BindingFlags.Default); String result; if(methodInfo == null){ result = TextConstants.MSG_MethodNotFound.Replace("Method not found"); }else{ //call the method result = methodInfo.Invoke(this, null).ToString(); } }