Referring to a 2D array through a 1D array

[Anonymous]

Probably a too simple answer but I suppose this would do the job public WaveSegment[] GetWaveSegment(int index){ WaveSegment[] ws=new WaveSegment[256]; for (int arrIdx=0;arrIdx,256;arrIdx++0{ ws[arrIdx]=WaveSegment[index,arrIdx]; } return ws; } Maybe you could also investigate the Array.Copy static method

[Heath Stewart]

Why not just use a jagged array, a.k.a. an array of arrays? When you get Segment[0] (note, all .NET languages use 0-based indexes, not 1-based indexes!) you get an array of 256 elements, whatever they are:

WaveSegment[] segments = new WaveSegment[17];
for (int i=0; iYou can then access them in several ways, including:

WaveSegment[] innerSegments = segments[0];

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[crushinghellhammer]

In this example, is WaveSegment[] a separate class that I perform the segmentation in? Or is it a function? I apologize for my ignorance, but I'm really new to all this.

[crushinghellhammer]

Heath, thanks again for your help. Sorry for the index gaffe. I was aware of that, but was obviously not paying attention while typing. Could you please explain the following code: WaveSegment[] segments = new WaveSegment[17]; and WaveSegment[] innerSegments = segments[0]; What is WaveSegment[] here? A class, a function or a jagged array? I'm new to all this, and apologize for the dumb questions.

[Heath Stewart]

I don't know - you used it in your code fragment so I thought I'd reuse it. Maybe I'm using wrong in your context, but the idea is the same. WaveSegment could be anything: a class, struct, enum, or even a delegate! All you're doing is making an array of an array of something (no, I didn't stutter! :)). The first line made an array of WaveSegment with 17 elements. In my code fragment, I then created a new array of 256 elements within each of those 17 elements. The second line above merely gets that 256-element array from the first array element from the array with 17 elements. See Arrays[^] in the C# Language Features reference on MSDN, or more specifically Jagged Arrays[^] for more information.

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[crushinghellhammer]

Heath, thanks for your detailed replies! Ok, here's what I've done, incorporating your suggestions and that of my anonymous helper. public class Segmentation { private static void Main() { Random R = new Random(); int[] inArray = new int[1280]; for(int i = 0; i < 1280; i++) inArray[i] = i; int[][] arrSegmentArray = new int[17][]; for(int i = 0; i < 17; i++) { arrSegmentArray[i] = new int[256]; Array.Copy(inArray, 64*i, arrSegmentArray[i], 0, 256); Console.WriteLine(arrSegmentArray[i].ToString()); Console.ReadLine(); } } } However, where I expect arrSegmentArray[i] to be printed as a 256 element array, all I see is System.Int32[]; What do I need to fix here?

[crushinghellhammer]

Heath, thanks for your detailed replies! Ok, here's what I've done, incorporating your suggestions and that of my anonymous helper. public class Segmentation { private static void Main() { Random R = new Random(); int[] inArray = new int[1280]; for(int i = 0; i < 1280; i++) inArray[i] = i; int[][] arrSegmentArray = new int[17][]; for(int i = 0; i < 17; i++) { arrSegmentArray[i] = new int[256]; Array.Copy(inArray, 64*i, arrSegmentArray[i], 0, 256); Console.WriteLine(arrSegmentArray[i].ToString()); Console.ReadLine(); } } } However, where I expect arrSegmentArray[i] to be printed as a 256 element array, all I see is System.Int32[]; What do I need to fix here? :(

[crushinghellhammer]

Solved it. Thanks for your help!

[Heath Stewart]

Glad you solved it, but just for future benefit, the line Console.WriteLine(arrSegmentArray[i].ToString()); is calling ToString on a Int32[] array. The default implementation of Array.ToString() (inherited from Object.ToString) is to simply print the namespace-qualified class name.

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[crushinghellhammer]

What I did was this: for (int i =0; i < 17; i++) { for (int j=0; j < 256; j++) { Console.Write(arrSegmentArray[i][j].ToString()+" "); } Console.WriteLine(); Console.ReadLine(); } Is that alright?

[Heath Stewart]

Sure, why not?! :) It just depends on your requirements and implementation.

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