sprintf

[styve]

Hi! Is there a command that works like sprintf, but it is like strcat? Because I will catenate (probably wrong spelling) some hex numbers to the same char value. Have a nice day, Stefan

[jan larsen]

You can just use sprintf like this:

char buffer[1024];
char * tmp;
tmp = buffer;
tmp += sprintf(tmp, "Line %d\r\n", 1);
tmp += sprintf(tmp, "Line %d\r\n", 2);
tmp += sprintf(tmp, "Line %d\r\n", 3);

Another, and better, solution is to use a strstream:

strstream out;
out<<"Line "<<1<

"After all it's just text at the end of the day. - Colin Davies

"For example, when a VB programmer comes to my house, they may say 'does your pool need cleaning, sir ?' " - Christian Graus

[Robert A T Kaldy]

If you use fixed number of hex numbers, use: sprintf("%c%x%x", 'c', 0x544, 0xbff) or if you use variable number: ostrstream os; os << 'c' << hex << 0x544 << 0xbff << .... and the char* string you obtain by os.str() Robert-Antonio "I launched Norton Commander and saw, drive C: on the left, drive C: on the right...Damn, why I need two drives C:???So I formatted one..."

[David Crow]

Here's a somewhat cheesy example:

char szBuffer[128];
for (int x = 0, num = 1; x < 10; x += 2)
{
sprintf(&szBuffer[x], "%02x", num);
num *= 2;
}

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A rich person is not the one who has the most, but the one that needs the least.

[Peter Weyzen]

or even another choice: CString S; for ( int x = 0, num = 1; x < 10, x += 2 ) {     S.AppendFormat( _T("%02x"), num );     num *= 2; } ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Peter Weyzen Staff Engineer [Santa Cruz Networks](http://www.santacruznetworks.com)