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Douglas Kirk 2022

@Douglas Kirk 2022
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  • Works in MYSQL 5.7, Syntax Error in MYSQL 8.0
    D Douglas Kirk 2022

    Thank you so much. Simply changed "rank" to "ranklist" and it has resolved the issue.

    Database database mysql game-dev sysadmin collaboration

  • Works in MYSQL 5.7, Syntax Error in MYSQL 8.0
    D Douglas Kirk 2022

    Hello My query to get a ranked leaderboard works on MYSQL 5.7 but gives me errors now that I upgraded to MYSQL 8.0

    mysql> SELECT username,score,level, FIND_IN_SET(score,(SELECT GROUP_CONCAT(score ORDER BY score ASC)FROM highscore WHERE game = 0 AND level = 4 AND user = 10 )) AS rank FROM highscore WHERE game = 0 AND level = 4 AND user = 1 ORDER BY rank LIMIT 10;

    ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'rank FROM highscore WHERE game = 0 AND level = 4 AND user = 1 ORDER BY rank LIMI' at line 1 Any ideas? Thank you Team!

    Database database mysql game-dev sysadmin collaboration
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