Thank you very much for your help. I have been working on this for about one week now. I really appreciate it. It works perfect now.

I tried and changed to the code snippet that you had, this is what I get. 34 24 3 32 33 50 I need it to print for example LOTTO PICKS 3 8 12 21 22 39 and cannot seem to fix it to do that

I have tried this, prints out but will not generate random numbers

#include <stdio.h>
#include <stdlib.h>
#include<time.h>

#define SIZE 6
#define MAX 53

void printArray(int N[], int T);
void fillArray(int N[], int T);

int main(void)
{
srand(time(NULL));

int PICKED[] = {0,0,0,0,0,0};

fillArray(PICKED, SIZE);
printArray(PICKED, SIZE);

return 0;
}

void fillArray(int N[], int T)
{
for(int P=0; P<SIZE; P++)
{
N[P] = rand() % 52+1;

for(int PASS=0; PASS<P; PASS++)
{
if(N[PASS] == N[P])
{
N[P] = (int) (rand()%52 +1);
P=-1;
}
}
}
}

void printArray(int N[], int T)
{
int PASS, P;

for(P=0; P<SIZE-1; P++)
{

    for(PASS = P + 1; PASS < SIZE; PASS++)
    {
    if(N\[P\]>N\[PASS\])
        {
   	        T = N\[PASS\];
	N\[P\] = N\[PASS\];
	N\[P\] = T;
        }
    }
}

printf("\\nLOTTO PICKS\\n\\n");
for(int P=0; P<SIZE; P++)
   printf("%d ", N\[P\]);

printf("\\n");

}

Can someone please help me with my bubblesort. It does not seem to sort and also prints 3 times.

#include <stdio.h>
#include <stdlib.h>
#include<time.h>

#define SIZE 6
#define MAX 53

void printArray(int N[], int T);
void fillArray(int N[], int T);

int main()
{
srand(time(NULL));

int PICKED[] = {0,0,0,0,0,0};

fillArray(PICKED, SIZE);
printArray(PICKED, SIZE);

return 0;
}

void fillArray(int N[], int T)
{
for(int P=0; P<T; P++)
{
N[P] = (int) (rand()% 52+1);

for(int y=0; y<P; y++)
{
if(N[y] == N[P])
{
N[P] = (int) (rand()%52 +1);
P=-1;
}
}
}
}

void printArray(int N[], int T)

{
	for(int P=0; P<SIZE-1; P++)

	{

		if(N\[P\]>N\[P+1\])

		{

			int T = N\[P+1\];

			N\[P+1\] = N\[P\];

			N\[P\] = T;

printf("\nLOTTO PICKS\n");
for(int P=0; P<SIZE; P++)

{
printf("%d ", N[P]);

printf("\n");

}}}}

Thanks again. I will make a notation in regards to the braces. I did make some other changes because the execute did not look like the sample given. But now works perfectly.

Thank you, That did fix the prob.

void Gen2Rand (int*r1p, int*r2p) 1. Error is undeclared identifier r2p 2. type error in argument 2 to 'Gen2Rand', found 'int' expected 'pointer to int' 3. possible usage of r1p and r2p before definition *r1p = r1; *r2p = r2; 1. Error is r1p and r2p is not a pointer. I met my instructor yesterday and he said that the prototypes were correct. So should I change the void Gen2Rand (int*r1, int*r2)

Can someone please look at this and tell me what I am doing wrong with my pointer.

#include #include #define SENT 4 //"Quit" menu choice

/* Function Prototypes */

void DisplayMenu (void);
int GetMenuChoice (void);
void Gen2Rand (int\*r1, int\*r2);
void DrillOneProb (int c, int r1, int r2);

/*============Mainline Procedures===============*/

int main (void)
{
int c; //Menu Choice (1-4)
int r1, //First Random Integer: 2-12 inclusive
r2; //Second Randon Integer: 2-12 inclusive

	  DisplayMenu();
	  c = GetMenuChoice();
while (c >= 1 && c < SENT)
	 { Gen2Rand (&r1, &r2);
  	  DrillOneProb (c, r1,r2);
	  DisplayMenu();
	  c = GetMenuChoice();
	  printf("Program Complete\\n");}
	  return (0);

}

/*===========CHILD FUNCTIONS===============*/

/* Display Title and Menu */

void DisplayMenu (void)

{
printf("MENU OF OPERATIONS\n");
printf("1. Addition.\n");
printf("2. Subtraction.\n");
printf("3. Multiplication.\n");
printf("4. Quit.\n\n");

}

/* Get Menu Choice */

int GetMenuChoice (void)

{
	int c;
	do{
		printf ("Enter the number of the operation to try (1-4):\\n");
		scanf ("%d", &c);
	if  (c<1 || c>SENT)
			printf("\\aInput value is out of range.\\n");
	while (c < 1 || c > SENT);
	return (c);

}

/* Generate and return 2 integers between 2-12 inclusive */

void Gen2Rand (int*r1p, int*r2p)

	int r1; //First random number
	int r2; //Second random number

	r1 = 2 + rand() % 11;
	r2 = 2 + rand() % 11;

    \*r1p = r1;
    \*r2p = r2;

return (0);

}

/* Display two random numbers and ask user what the answer would be after the chosen operation*/

void DrillOneProb (int c, int r1, int r2)

{
int CorAns, //Correct Answer
Reply; // Users Reply

switch (c)
{

		case 1:
	  	printf("+");
	   	CorAns = r1 + r2;
                break;


		case 2:
	   	printf("-");
	  	CorAns = r1 - r2;
	  	break;


		default:
	        printf("x");
	        CorAns = r1 \* r2;
	        break;

}

printf(" %d, ?", Reply);
scanf ("%d", &Reply);

if
(Reply == CorAns)

		   printf("Yes, that is correct. Good Job!");


	else
		{	printf("No, the correct answer is: %d", CorAns);
			printf("\\n\\n");
	    }

and what about the brace

I do not believe that has been in any of the chapters that we have read so far, but I will look again at the latest chapter because each assignment is associated with that chapter.

change to printf("\nWhat is %d", *r1); (I already changed this)I figured that out. kbury wrote: r1 = 2 + rand() % 11; change to *r1 = 2 + rand() % 11; (This defineately fixed this. The above steps, however just fix compiler errors...I don't know if the semantic will be correct.

switch (c)

{     (states that this is illegal type pointer to int in       switch expression.)

	case '1':
	  	printf("+");
	   	CorAns = r1 + r2;  (operands of + have illegal of 'pointer to int' and 'pointer to int')

	  break;

I am stuck with this section of my code so far: error codes: expected int and got pointer to int and operands of = illegaltype pointer to int and int

/* Display two random numbers and ask user what the answer would be after the chosen operation*/

void DrillOneProb (int*c, int*r1, int*r2)

{
int CorAns, //Correct Answer
Reply; // Users Reply

		{
		printf("\\nWhat is %d",r1);	1st error		                scanf("%d", r1);

		r1 = 2 + rand() % 11;           2nd error
		}

I am only trying to follow a flow chart given and it is very confusing. Thank you

Thanks, I just changed and it fixed that part.

I am trying to write a program as a math tutor. Can someone look at this code. I keep getting errors on int and pointer as well as telling me the switch case has illegal pointer. Thanks, any advice would be greatful.

#include #include #define SENT 4 //"Quit" menu choice

/* Function Prototypes */

void DisplayMenu (void);
void GetMenuChoice (void);
void Gen2Rand (int\*r1, int\*r2);
void DrillOneProb (int\*c, int\*r1, int\*r2);

/*============Mainline Procedures===============*/

int main (void)
{
int c; //Menu Choice (1-4)
int r1, //First Random Integer: 2-12 inclusive
r2; //Second Randon Integer: 2-12 inclusive

}

/*===========CHILD FUNCTIONS===============*/

/* Display Title and Menu */

void DisplayMenu (void)

{
	printf("MENU OF OPERATIONS\\n\\n");
	printf("1. Addition.\\n");
	printf("2. Subtraction.\\n");
	printf("3. Multiplication.\\n");
	printf("4. Quit.\\n\\n");

}

/* Get Menu Choice */

void GetMenuChoice (void)

{
	int c;
	printf ("Enter the number of the operation to try (1-4):\\n");
	scanf ("%d", &c);
	while
		 (c<1 || c>SENT)
			printf("\\aInput value is out of range.\\n");


}

/* Generate and return 2 integers between 2-12 inclusive */

void Gen2Rand (int *r1p, int *r2p)

{
	int c;
	c=0;

	if (c>=1 && c<SENT)

	int r1; // First random number
	int r2; //Second random number

	r1 = 2 + rand() %11;
	r2 = 2 + rand() %11;

   \*r1p = r1;
   \*r2p = r2;

   printf("Program complete\\n");

}

/* Display two random numbers and ask user what the answer would be after the chosen operation*/

void DrillOneProb (int *c, int *r1, int *r2)

{
int CorAns, //Correct Answer
Reply; // Users Reply

		{
		printf("\\nWhat is %d", & r1);

		r1 = 2 + rand() % 11;
		}


switch (c);
{
	case '1':  1 = +; break;
	CorAns = r1 + r2;

	case '2':  2 = -; break;
	CorAns = r1 - r2;

	case '3':  3 = x; break;
	CorAns = r1 x r2;

}

printf("%d ?  %d\\n", r2, Reply);

if
Reply = CorAns
{
printf("Yes, that is correct. Good Job!");
}

	else
		printf("No, the correct answer is: %d", CorAns);
		printf("\\n\\n");

return (c);

print\_menu(); //Print the menu option, and configure some needed things.


return (0); //The end of our simple game.

Thanks for your help. I tried to code it just like you had in the 1st answer, but my compiler would not compile it.

I am trying to stick to this flowchart given to me. Maybe I just do not understand it. In the flowchart it is only called where I have it in the code and after boxnum it is suppose to go back to col.

anyways I changed the code and now it does this. Do i need to change the if boxnum statement?

printf ("\n\nThe numbering layout will be:\n");

while (r <= rows)

	{

	r = r + 1;
	printf ("\\n \\n");

while (c <= cols)

c = c + 1;
printf (" %d |", boxnum);
boxnum = boxnum + 1;


if (boxnum <= 1);

printf(" %d | ", boxnum++);

}

unit\_height = rows \* mbxhgt;
unit\_width = cols \* mbxwid;

printf ("\\nOverall height of mailbox unit: %d", unit\_height);
printf ("\\nOverall width of mailbox unit: %d\\n", unit\_width);

return (0);
}

Mailbox Layout Program How many rows of mailboxes will there be?4 How many columns of mailboxes will there be?5 The numbering layout will be: 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | Overall height of mailbox unit: 24 Overall width of mailbox unit: 20

I am using the LCC Win 32 compiler and when I remove the semicolon away from if (boxnum <= 1); It does not print out the 6, 7, 8, 9 at all.

I guess a gluton for punishment. I am new at this and am trying to learn from a online class, which seems to make this more difficult than I had expected.