Thanks. It works.
K
Keanu L
@Keanu L
Posts
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how to get a object according the name of class -
how to get a object according the name of classhow to implement like this:
$classname = "dsa";$ob = new $classname();
i just have a var of the class name and how to new the class?
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how to get data when using header('location:'. $url) ? help mewhat about using :
$content = include '${url}';header("location:antoher url");