ok I did it : ReportDocument report = new ReportDocument(); report.Load(@"G:\Rp3Receipt.rpt",OpenReportMethod.OpenReportByTempCopy); ParameterFieldDefinitions parametersColl = report.DataDefinition.ParameterFields; ParameterFieldDefinition paramName1 = parametersColl["prmNameInReport1"]; ParameterFieldDefinition paramName2= parametersColl["prmNameInReport2"]; ParameterValues values = new ParameterValues(); ParameterDiscreteValue val = new ParameterDiscreteValue(); val.Value = paramValue1;// the value I want to give the parameter values.Add(val); paramName1.ApplyCurrentValues(values); //-----------second parameter values = new ParameterValues(); val = new ParameterDiscreteValue(); val.Value = paramValue2; values.Add(val); paramName2.ApplyCurrentValues(values); report.PrintOptions.PrinterName = @"\\...\HPLaserJ5"; report.PrintToPrinter(1,false,1,1);

In your original message you indicated that you were able to print to the printer; with a report that had no parameters. Your code is correct there; you assign the PrinterName property and then call the PrintToPrinter method. If there are parameters you need to pass and/or database connection information you need to set for your report to print, you simply must set those properties before you call the PrintToPrinter method. All of these methods and properties are within the ReportDocument object. So the code would be something like the following: public class Form1 : System.Windows.Forms.Form { ReportDocument m_PrintJob; public Form1() { try { m_PrintJob = new ReportDocument(); m_PrintJob.Load("C:/MyReport.rpt"); if (m_PrintJob.IsLoaded) { SetConnectionInfo("MyDBServer", "MyDBName", "MyUserName", "MyPassword"); SetParameterValue("ParameterName", 100); m_PrintJob.PrintToPrinter(1, false, 0, 0); } } catch (Exception e) { MessageBox.Show(e.Message); } } public void SetConnectionInfo(string szServer, string szDatabase, string szUser, string szPassword) { TableLogOnInfo crtableLogoninfo = new TableLogOnInfo(); Tables CrTables = m_PrintJob.Database.Tables; for (int iIndex = 0; iIndex < CrTables.Count; iIndex++) { crtableLogoninfo.ConnectionInfo.ServerName = szServer; crtableLogoninfo.ConnectionInfo.DatabaseName = szDatabase; crtableLogoninfo.ConnectionInfo.UserID = szUser; crtableLogoninfo.ConnectionInfo.Password = szPassword; Table CrTable = CrTables[iIndex]; CrTable.ApplyLogOnInfo(crtableLogoninfo); } } public void SetParameterValue(string szParamName, int iValue) { ParameterFieldDefinitions paramFlds = m_PrintJob.DataDefinition.ParameterFields; ParameterFieldDefinition paramFld = paramFlds[szParamName]; ParameterDiscreteValue discreteValue = new ParameterDiscreteValue(); ParameterValues paramValues = paramFld.CurrentValues; paramValues.Clear(); discreteValue.Value = iValue; paramValues.Add(discreteValue); paramFld.ApplyCurrentValues(paramValues); } } Ron Ward

thank you very much, it was very helpfull, sharon

No multiline property for a label. I think your ref is for a text box. Did you try putting a newline in the string to see what happens? label.Text = "Text" + Environment.NewLine + "More Text"; Not sure if that will work. Bill F

thank you very much , i'll try it later. sharon.

well, the cell-array doesn't seem to have 7 elements - thus cell[6] rises the Out-Of-Range-Exception. :wq

Look at the following link from MSDN Clickety

Ahhh, the beauty of programming via interfaces :) [contractual I think is the term] IEnumerable ie = myobject as IEnumerable if( ie != null ) { // myobject implements IEnumerable so do something with it IEnumerator = ie.GetEnumerator(); ... } HTH, James Simplicity Rules!

sharon wrote: I have a problem, i work with web pages, i want to fill labels in one webForm from the information of TextBox in another webForm , how can I do it? Usually you would store the data in a session variable if you are not calling the second form from the first and there would possibly be other pages interacted with between them. You could pass the values directly if you did call the second form from the first. Rocky Moore

thank you for your help. sharon :)