That sounds like a faster way to calculate, because of the smaller set of combinations. I'd like to try that another time, but I don't have the time to do that now before the deadline. Thanks for the tip, nice to see how there are multiple solutions to work it out.

Well, I don't know why it did not work the first time, but I tried to simplify the code and ended up with: printf("price of a: price of b: price of c: "); scanf("%d %d %d", &a, &b, &c); instead of that thing with while { ... } And this time, it did work. I do not really see the difference with the code I used before that did not work.. :p

Thank you so much! It works great. I had to change the code a bit to pass all testcases, but finally I made it :). However, I'd like to know how that piece of code between the While { ... } works, I don't really get it. done = 0, so while ( done == 0) is true. Then it runs the code and you can enter the values. But why does it need the done == 0 and why the != 1? I understand the done = 1, otherwise it will run the while statement again, right?

Thanks again, I make improve in the code, but it ain't working as supposed. I'm really wondering where the code is wrong, I get no output or a wrong output (e.g. 100 100 100 gives as output only 100 a, 0 b, 0 c.) I tried different things and I guess I'm almost there, but can't fix it. So please, help me with this code.

#include #include #include int main(int argc, char *argv[])
{
int a, b, c, x, y, z; /* x=numbers of a y= numbers of b z= numbers of c*/
printf("price of a:\n");
printf("price of b:\n");
printf("price of c:\n");
scanf("%d, %d, %d" ,&a, &b, &c);

for(x = 0; x <= 100; x++)
{
	for(y = 0; y <= (100 - x); ++y)
	{
		        z = 100 - x - y;
		        if(x\*a + y\*b + z\*c == 10000)
		        {
    		      printf("%d a, %d b, %d c",x ,y ,z);
		        }
	}
}

return 0;
}

Thank you guys. I can't compile and execute right now. Will this give me the output I want? If not, where did I go wrong?

#include #include #include int main(int argc, char *argv[])
{
int a, b, c, x, y, z; /* x=numbers of a y= numbers of b z= numbers of c*/
printf("price of a:\n");
printf("price of b:\n");
printf("price of c:\n");
scanf("%d, %d, %d" ,&a, &b, &c);

for(x = 1; x <= 100; x++)
{
	for(y = 1; y <= (100 - x); ++y)
	{
		z = 100 - x - y;
		if(x\*a + y\*b + z\*c == 100)
		{
    		printf("x %d, y %d, z %d",a ,b ,c);
		}
	}
}

return 0;
}

Thanks. I'm finally getting the hang of it. I'll try something tomorrow and I will let you peoples know if I succeed or not.

Hey guys, I have to write a small program in C, I'll explain what it has to do. You have product a, b and c The input is the prices of a, b and c in cents. You have to spend exactly 100 euros on the purchase of exactly 100 products. As output I need to get a list of all possible combinations. Lets give an example. Lets say the input is "88 99 102": then the output has to be exactly like this: 1 a, 62 b, 37 c 4 a, 48 b, 48 c 7 a, 34 b, 59 c 10 a, 20 b, 70 c 13 a, 6 b, 81 c I'm relatively new in progamming in C, so all help is appreciated, the deadline is short for this one.

int main(int argc, char *argv[]) {
int a, b, c, x, y, z /* x=numbers of a y= numbers of b z= numbers of c*/
printf("price of a:\n");
printf("price of b:\n");
printf("price of c:\n");
scanf("%d, %d, %d" ,&a, &b, &c);
while (x+y+z=100){
x*a+y*b+z*c=10000

As you can see, I tried writing some code, but im stuck right here...