Could someone pls explain the below question? Q1 : In line1 the second parameter is referece to integer constant. If so how is the value in 'x' changed to 4 Question:

#include

#include

using namespace std;

int mani(int (&arr)[10], const int& x)//Line1
{
for (int i = 0; i < 1; ++i)
arr[i] = arr[i] + x;
return x; //returns 4
}

int main(){
int arr[10] = {2, 3, 4, 5, 6, 7, 8, 9, 10, 11};
cout<

In the msdn page [^] it says "When a member of a class or struct is a property, field, method, event, or delegate, and that member either is a type or has a type as a parameter or return value, the accessibility of the member cannot be greater than the type. For example, you cannot have a public method M that returns a class C unless C is also public. Likewise, you cannot have a protected property of type A if A is declared as private. " But in this code

class AccessSpecifier
{
// private field:
private int wheels = 3;

   // protected internal property:
    protected internal int Wheels
    {
        get { return wheels; }
        set { wheels = value;  }
    }

}
class Derieved : AccessSpecifier
{
    public void fun()
    {
        Wheels = 90; //accessing private mem of base class
    }
}
class main
{
    public static void Main()
    {
        AccessSpecifier a = new AccessSpecifier();
        a.Wheels = 4;
        Console.WriteLine(a.Wheels); // gives 4 as output
        Derieved d = new Derieved();
        d.fun();
        Console.WriteLine(d.Wheels); //gives 90 as output
        d.Wheels = 99; //accessing private mem of a class in same assembly   :omg: 
        Console.WriteLine(d.Wheels);
        Console.ReadKey();
     
    }
}

How is this possible to access private members of a class jus becoz the property of the field is made protected internal ? And compiler is against the lines given in MSDN? Can u pls explain ?:confused:

Thanks :)

Thanks. :)

class CA{
private:
int m_Var;
public:
CA(int x=0): m_Var(x){cout<<"1";}
bool operator < (const CA &obj2) { cout<<"2"; return (m_Var < obj2.m_Var) ? true : false;}
};
int main(void) {
CA obj1=2;
if(obj1 < 3){cout << "In If block" << endl;}
}

the output of this code is 112In If block .. i can understand the reason behind the first 1 and "2In If block" .. i dont understand when the second 1 is being called? as per my understanding when (obj1<3) executes it may call obj1.operator<(3) But constructor is being called but whats makes it to call? kindly explain why the second 1 is being displayed?