C / C++ / MFC

Great! "When you don't know what you're doing it's best to do it quickly" - Jase #DuckDynasty

Here is what works, still not sure why I could not use m_hMenu similar way. Basically a copy of MFC code. HMENU hMenu = pSubMenu->GetSafeHmenu(); pSubSubMenu = pSubMenu->FromHandle(hMenu)->GetSubMenu(2); ASSERT(pSubSubMenu); Thanks for all the help I got, you guys are great! Cheers Vaclav

Nope, shouldn't have to do that. That should already be handled when you release the object.

No that isn't what that means. E1 appears on both side of the equals. It is referring to whether E1 is evaluated once for the lvalue side and once for the rvalue side. And it says no.

To get any kind of help, please post what are all things you've tried or where you stuck with code/logic. [Delegates]      [Virtual Desktop]      [Tray Me !] -Malli...! :rose:****

You're welcome. Driver development isn't exactly an easy topic to broach, though you're bound to find some examples around the net of "Hello World" type examples. There may even be some here at CP, I haven't looked. You wouldn't need terribly much functionality in the driver, so you may well find it considerably easier than it seems daunting. You could probably start with just two functions above the basic house-keeping stuff. One to read the value of the register(port) and another to write a value to it. You could then provide finer functionality in a user-mode DLL for specifics like opening the drawer etc - i.e use the ability to write a register from the DLL, setting the appropriate bit. Best of luck, hope it works out well for you. :)

ok sir.

It depends on what your control actually is (the one that you want to display some data on)... a dialog isn't a control, it's a window. A control would be, for example, an edit box.

Vaclav_Sal wrote: It was dissapointing that majority of replies managed to stay off the subject. It was disappointing that your original question was so confusing.

I used this in my dialog, After that try to hide the dialog, Dialog is hiding but the shadow is not hiding. I am using ShowWindow(SW_HIDE).

Dear Randor: I think you are right. It is different between touch and mouse. when left mouse button down, it will play sound. when I touch the panel, and leave fast, it will play or touch the panel, and then move my finger on panel, it will play sound, too. Thank for your help, Victor.

Driver development is too much different of what you are used to do in C/C++ development user mode, you don't have right the vocabulary to understand even if I reply. Buy and read Windows Internals by Mark Russinovich 1[^] and 2[^]. (These books are one of the best investment I ever made) It will not show you the code, but is the necessary bridge before starting to read book and resources about driver development. In a very high lever yes, Windows API you are using in user land call functions in the driver, but the mapping is not as simple as a "override" in C++.

Don't worry about performance: since you are using the serial port for communicating with the microcontroller then your application execution time is, in any case, dominated by the I/O operations. In any case MFC, at this level (that is simple GUI stuff), is about as efficient as the raw C WINAPI code. Veni, vidi, vici.

Happens...

OK, for some unknown reason , AKA MS naming convention - these fiters builds are not using dll extension , but ax. And apparently they are "self registering " too.

Try this link [Quickstart: Touch input (Windows Store apps using C#/VB/C++ and XAML)] []

Understand, you are correct. Thank you. Thanks for your time If you work with telemetry, please check this bulletin board: http://www.bkelly.ws/irig\_106/

Please verify that the Hook got installed properly. Once the hook is installed, you should be able to get the messages. When the mouse event is received, you can check the window handle. Using that window handle, identify the class type of the window. [Delegates]      [Virtual Desktop]      [Tray Me !] -Malli...! :rose:****

And those desired results are what? :confused: Have you stepped through it using the debugger? "One man's wage rise is another man's price increase." - Harold Wilson "Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons "You can easily judge the character of a man by how he treats those who can do nothing for him." - James D. Miles

camillo87 wrote: Could you please help, how can I solve this problem? You might also try this forum. "One man's wage rise is another man's price increase." - Harold Wilson "Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons "You can easily judge the character of a man by how he treats those who can do nothing for him." - James D. Miles