Remove the back slash in a TextBox

[Joshua Quick]

The issue is on line 3. If the first character in the string is a '\', which it likely will be with a path such as "\\Foo\Bar", then the index will be zero causing it to skip over your If condition. You should change it to >= 0, like this... If myStartPointer >= 0 Then

[Bob Zagars]

That would cause a problem if the back slash was at postion 0. This error happens even when the position is in the middle of the string. Example MYDOMAINNAME\myusername The results is from my code \myusername If I add one to the start position of the Mid() method I will get \yusername The code has nothing to do with the starting position it has to do with the removal of the back slash. Bob Zagars Senior Software Engineer

[Bob Zagars]

You are dead wrong. Here is the class String Indexof() method. "Reports the index of the first occurrence of the specified String in this instance." .... "Return Value The index position of value if that string is found, or -1 if it is not. If value is Empty, the return value is 0." I have not tested at the first position which might be position 0 or 1 but my problem is not related to this issue. Mine happens in the middle of the string. Bob Zagars Senior Software Engineer

[Joshua Quick]

Bob Zagars wrote:

You are dead wrong.

I'm not wrong. Your code does fail if a back slash is found at index 0. Try this string: "\\Foo".

[Bob Zagars]

Joshua Quick wrote:

I'm not wrong. Your code does fail if a back slash is found at index 0. Try this string: "\\Foo".

I am sorry but my code will never have "\\" in it only DOMAINNAME\username which I am getting off the problem, If you do not have an answer that will solve my problem stop replying. Bob Zagars Senior Software Engineer

[Joshua Quick]

Bob Zagars wrote:

That would cause a problem if the back slash was at postion 0. This error happens even when the position is in the middle of the string.

Your code has 2 bugs in it then. The first one I already mentioned. The second bug is with how you're extracting the substring. You are being confused by the Mid() function. Mid() is a function that was used in VB6 and only exists in VB.NET for compatibility reasons. Mid() expects 1 based indexes, which is the way indexing used to work in VB6. The .NET String class uses zero based indexes. This is why you are one character off. You should call String.Substring() instead.

[Bob Zagars]

Dim myStartPointer As Integer = Me.ebLoginName.Text().IndexOf("\") Dim myLength As Integer = Me.ebLoginName.TextLength() Dim myString As String = Me.ebLoginName.Text() If myStartPointer >= 0 Then Me.ebLoginName.Text() = myString.Substring(myStartPointer + 1) Me.mccDomain.Clear() End If Same problem can not get rid of back slash. myStartPointer is suppose to be the indexed location of the back slash. Input string MYDOMAINNAME\test Results \test Bob Zagars Senior Software Engineer

[Joshua Quick]

Bob Zagars wrote:

Dim myStartPointer As Integer = Me.ebLoginName.Text().IndexOf("\") Dim myLength As Integer = Me.ebLoginName.TextLength() Dim myString As String = Me.ebLoginName.Text() If myStartPointer >= 0 Then Me.ebLoginName.Text() = myString.Substring(myStartPointer + 1) Me.mccDomain.Clear() End If

I've just ran your above code with the string "MYDOMAIN\test". It worked for me. Either the input string is not what you expected or the problem lies elsewhere in your code. In either case, I recommend that you step through your code in the debugger and keep a sharp eye on your ebLoginName.Text property.

[Bob Zagars]

Joshua Quick wrote:

Dim myStartPointer As Integer = Me.ebLoginName.Text().IndexOf("\") Dim myLength As Integer = Me.ebLoginName.TextLength() Dim myString As String = Me.ebLoginName.Text() If myStartPointer >= 0 Then Me.ebLoginName.Text() = myString.Substring(myStartPointer + 1) Me.mccDomain.Clear() End If I've just ran your above code with the string "MYDOMAIN\test". It worked for me. Either the input string is not what you expected or the problem lies elsewhere in your code. In either case, I recommend that you step through your code in the debugger and keep a sharp eye on your ebLoginName.Text property.

Okay this tells me something because I thought I was crazy and could not understand how my results kept adding a back slash. I am using a class library from Janus Systems. It is their EditBox which has to be the problem. I will submit at their web site. Thanks for your help. Bob Zagars Senior Software Engineer

[CodyGen]

you can use the Replace method of the string. newstring = strbackslash.Replace("\","")

[Dave Kreskowiak]

Or just get the code right in the first place and forget about this little "patch". RageInTheMachine9532 "...a pungent, ghastly, stinky piece of cheese!" -- The Roaming Gnome