Skip to content
  • Categories
  • Recent
  • Tags
  • Popular
  • World
  • Users
  • Groups
Skins
  • Light
  • Cerulean
  • Cosmo
  • Flatly
  • Journal
  • Litera
  • Lumen
  • Lux
  • Materia
  • Minty
  • Morph
  • Pulse
  • Sandstone
  • Simplex
  • Sketchy
  • Spacelab
  • United
  • Yeti
  • Zephyr
  • Dark
  • Cyborg
  • Darkly
  • Quartz
  • Slate
  • Solar
  • Superhero
  • Vapor

  • Default (No Skin)
  • No Skin
Collapse
Code Project
  1. Home
  2. General Programming
  3. C / C++ / MFC
  4. Power of 2

Power of 2

Scheduled Pinned Locked Moved C / C++ / MFC
question
38 Posts 12 Posters 0 Views 1 Watching
  • Oldest to Newest
  • Newest to Oldest
  • Most Votes
Reply
  • Reply as topic
Log in to reply
This topic has been deleted. Only users with topic management privileges can see it.
  • R RichardS

    Hi All, Is there a fast way of checking to see if an int is a power of 2 (i.e. 2, 4, 8, 16, 1024)? I know the long way using a loop, but I was hoping for a simple way of doing this. regards, Rich "Programming today is a race between software engineers striving to build bigger and better idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far the Universe is winning." -- Rich Cook

    R Offline
    R Offline
    Russell
    wrote on last edited by
    #3

    if a number is a power of 2 than looking at the bits that composed that value must be all '0' but only one '1'. So, if int is a 32 bit value, you can look for 31 '0' and 1 '1'. But you need olso a loop! But it is quite fast. Let me know if here is a faster bit function to count the ones/zeros Bye

    Have a nice code day ;)

    R 1 Reply Last reply
    0
    • T toxcct

      :sigh:

      R Offline
      R Offline
      RichardS
      wrote on last edited by
      #4

      Thanks :) "Programming today is a race between software engineers striving to build bigger and better idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far the Universe is winning." -- Rich Cook

      1 Reply Last reply
      0
      • R Russell

        if a number is a power of 2 than looking at the bits that composed that value must be all '0' but only one '1'. So, if int is a 32 bit value, you can look for 31 '0' and 1 '1'. But you need olso a loop! But it is quite fast. Let me know if here is a faster bit function to count the ones/zeros Bye

        Have a nice code day ;)

        R Offline
        R Offline
        RichardS
        wrote on last edited by
        #5

        Yip, this was my way to begin with. regards, Rich "Programming today is a race between software engineers striving to build bigger and better idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far the Universe is winning." -- Rich Cook

        R 1 Reply Last reply
        0
        • T toxcct

          :sigh:

          C Offline
          C Offline
          Cedric Moonen
          wrote on last edited by
          #6

          I think you will have problems when comparinf the floats, due to the precision.

          T 1 Reply Last reply
          0
          • R RichardS

            Hi All, Is there a fast way of checking to see if an int is a power of 2 (i.e. 2, 4, 8, 16, 1024)? I know the long way using a loop, but I was hoping for a simple way of doing this. regards, Rich "Programming today is a race between software engineers striving to build bigger and better idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far the Universe is winning." -- Rich Cook

            D Offline
            D Offline
            Divyang Mithaiwala
            wrote on last edited by
            #7

            Hello RichardS, Try this one.

            double val = 0.0;
            val = log10(y) / log10(2.0);
            
            //Check that 'val' is pure int (Here you use ur own code is u optimize)
            int val2 = int(val);
            
            if (val == val2) 
                 // y is power of 2
            else
                 // y is not power of 2
            

            here 'y' is value u want to check for power of 2. Best of luck


            Divyang Mithaiwala System Engineer & Software Developer

            T D 2 Replies Last reply
            0
            • T toxcct

              :sigh:

              S Offline
              S Offline
              Stephen Hewitt
              wrote on last edited by
              #8

              2^3 = 8 but floor(sqrt(8)) != sqrt(8)? Steve

              1 Reply Last reply
              0
              • C Cedric Moonen

                I think you will have problems when comparinf the floats, due to the precision.

                T Offline
                T Offline
                toxcct
                wrote on last edited by
                #9

                true, but that was a starting point. it would be better to use double at least, but still remains the precision problem.

                1 Reply Last reply
                0
                • D Divyang Mithaiwala

                  Hello RichardS, Try this one.

                  double val = 0.0;
                  val = log10(y) / log10(2.0);
                  
                  //Check that 'val' is pure int (Here you use ur own code is u optimize)
                  int val2 = int(val);
                  
                  if (val == val2) 
                       // y is power of 2
                  else
                       // y is not power of 2
                  

                  here 'y' is value u want to check for power of 2. Best of luck


                  Divyang Mithaiwala System Engineer & Software Developer

                  T Offline
                  T Offline
                  toxcct
                  wrote on last edited by
                  #10

                  we are on a standard C++ forum, not managed/CLI...

                  D 1 Reply Last reply
                  0
                  • D Divyang Mithaiwala

                    Hello RichardS, Try this one.

                    double val = 0.0;
                    val = log10(y) / log10(2.0);
                    
                    //Check that 'val' is pure int (Here you use ur own code is u optimize)
                    int val2 = int(val);
                    
                    if (val == val2) 
                         // y is power of 2
                    else
                         // y is not power of 2
                    

                    here 'y' is value u want to check for power of 2. Best of luck


                    Divyang Mithaiwala System Engineer & Software Developer

                    D Offline
                    D Offline
                    Divyang Mithaiwala
                    wrote on last edited by
                    #11

                    Here logic is simple y = value that want to check x = find a value that is in power of 2 so,

                    2^x = y
                    log 2^x = log y
                    x log 2 = log y

                    x = log y /log 2


                    Divyang Mithaiwala System Engineer & Software Developer

                    1 Reply Last reply
                    0
                    • R RichardS

                      Hi All, Is there a fast way of checking to see if an int is a power of 2 (i.e. 2, 4, 8, 16, 1024)? I know the long way using a loop, but I was hoping for a simple way of doing this. regards, Rich "Programming today is a race between software engineers striving to build bigger and better idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far the Universe is winning." -- Rich Cook

                      B Offline
                      B Offline
                      BadKarma
                      wrote on last edited by
                      #12

                      Hi, you could use ::log to check if its a power of 2 math: y = 2^x -> x = log(y)/log(2) so you can use:

                      int y = 1024;
                      if(y == (int)(::pow(2.0, ::floor(::log((double)y)/::log(2.0)))))
                      {
                        //  true
                      }
                      else
                      {
                        // false
                      }
                      

                      but his is heavy processing, so it mith be slower that the for loop codito ergo sum

                      1 Reply Last reply
                      0
                      • R RichardS

                        Hi All, Is there a fast way of checking to see if an int is a power of 2 (i.e. 2, 4, 8, 16, 1024)? I know the long way using a loop, but I was hoping for a simple way of doing this. regards, Rich "Programming today is a race between software engineers striving to build bigger and better idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far the Universe is winning." -- Rich Cook

                        T Offline
                        T Offline
                        Taka Muraoka
                        wrote on last edited by
                        #13

                        Define "fast". If you're using 32-bit int's, there are only 32 possibilities so you can just check entries in a lookup table, making sure you do the most likely candidates first. BTW, all these suggestions to use sqrt() and log() are nuts - these functions are insanely slow!


                        The two most common elements in the universe are Hydrogen and stupidity. - Harlan Ellison Awasu 2.2 [^]: A free RSS/Atom feed reader with support for Code Project.

                        R 1 Reply Last reply
                        0
                        • R RichardS

                          Hi All, Is there a fast way of checking to see if an int is a power of 2 (i.e. 2, 4, 8, 16, 1024)? I know the long way using a loop, but I was hoping for a simple way of doing this. regards, Rich "Programming today is a race between software engineers striving to build bigger and better idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far the Universe is winning." -- Rich Cook

                          R Offline
                          R Offline
                          Ryan Binns
                          wrote on last edited by
                          #14

                          Crikey. I thought this was well known. Just do this:

                          if (x & (x-1))
                          {
                            // x is <edit>not</edit>a power of two
                          }
                          else
                          {
                            // x is <edit>not</edit> a power of two
                          }

                          sorry, got the two cases round the wrong way... :-O

                          Ryan

                          "Punctuality is only a virtue for those who aren't smart enough to think of good excuses for being late" John Nichol "Point Of Impact"

                          -- modified at 6:04 Monday 6th March, 2006

                          S N R 3 Replies Last reply
                          0
                          • R RichardS

                            Yip, this was my way to begin with. regards, Rich "Programming today is a race between software engineers striving to build bigger and better idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far the Universe is winning." -- Rich Cook

                            R Offline
                            R Offline
                            Russell
                            wrote on last edited by
                            #15

                            Read this function, it could be another start point! This function that I wrote last year find the bigger long, greater than the input value, that is a power of 2. And it is quite fast!:) unsigned long Next2Power(unsigned long x){ unsigned long y=1, x1=x; if(x==0) return 0; while(x1!=0){ x1>>=1; y<<=1; } y>>=1; if(y!=x) y<<=1; return y; }

                            Have a nice code day ;)

                            D 1 Reply Last reply
                            0
                            • R Ryan Binns

                              Crikey. I thought this was well known. Just do this:

                              if (x & (x-1))
                              {
                                // x is <edit>not</edit>a power of two
                              }
                              else
                              {
                                // x is <edit>not</edit> a power of two
                              }

                              sorry, got the two cases round the wrong way... :-O

                              Ryan

                              "Punctuality is only a virtue for those who aren't smart enough to think of good excuses for being late" John Nichol "Point Of Impact"

                              -- modified at 6:04 Monday 6th March, 2006

                              S Offline
                              S Offline
                              Stephen Hewitt
                              wrote on last edited by
                              #16

                              This is by far the best suggestion so far - I'd wager it's impossible to beat this technique. Steve

                              R 1 Reply Last reply
                              0
                              • T Taka Muraoka

                                Define "fast". If you're using 32-bit int's, there are only 32 possibilities so you can just check entries in a lookup table, making sure you do the most likely candidates first. BTW, all these suggestions to use sqrt() and log() are nuts - these functions are insanely slow!


                                The two most common elements in the universe are Hydrogen and stupidity. - Harlan Ellison Awasu 2.2 [^]: A free RSS/Atom feed reader with support for Code Project.

                                R Offline
                                R Offline
                                Ryan Binns
                                wrote on last edited by
                                #17

                                Taka Muraoka wrote:

                                BTW, all these suggestions to use sqrt() and log() are nuts - these functions are insanely slow!

                                Agreed!! It is quite simple. A single decrement and bitwise AND will do the job nicely

                                Ryan

                                "Punctuality is only a virtue for those who aren't smart enough to think of good excuses for being late" John Nichol "Point Of Impact"

                                1 Reply Last reply
                                0
                                • R Ryan Binns

                                  Crikey. I thought this was well known. Just do this:

                                  if (x & (x-1))
                                  {
                                    // x is <edit>not</edit>a power of two
                                  }
                                  else
                                  {
                                    // x is <edit>not</edit> a power of two
                                  }

                                  sorry, got the two cases round the wrong way... :-O

                                  Ryan

                                  "Punctuality is only a virtue for those who aren't smart enough to think of good excuses for being late" John Nichol "Point Of Impact"

                                  -- modified at 6:04 Monday 6th March, 2006

                                  N Offline
                                  N Offline
                                  Nibu babu thomas
                                  wrote on last edited by
                                  #18

                                  Great work! You've implemented Russel's idea!


                                  Nibu thomas Software Developer

                                  R 1 Reply Last reply
                                  0
                                  • S Stephen Hewitt

                                    This is by far the best suggestion so far - I'd wager it's impossible to beat this technique. Steve

                                    R Offline
                                    R Offline
                                    Ryan Binns
                                    wrote on last edited by
                                    #19

                                    And yet it got the lowest votes of all of them. Funny, isn't it :)

                                    Ryan

                                    "Punctuality is only a virtue for those who aren't smart enough to think of good excuses for being late" John Nichol "Point Of Impact"

                                    S 1 Reply Last reply
                                    0
                                    • N Nibu babu thomas

                                      Great work! You've implemented Russel's idea!


                                      Nibu thomas Software Developer

                                      R Offline
                                      R Offline
                                      Ryan Binns
                                      wrote on last edited by
                                      #20

                                      Actually, I've been using this for years doing embedded programming. Every clock cycle is precious ;)

                                      Ryan

                                      "Punctuality is only a virtue for those who aren't smart enough to think of good excuses for being late" John Nichol "Point Of Impact"

                                      N R 2 Replies Last reply
                                      0
                                      • R Ryan Binns

                                        And yet it got the lowest votes of all of them. Funny, isn't it :)

                                        Ryan

                                        "Punctuality is only a virtue for those who aren't smart enough to think of good excuses for being late" John Nichol "Point Of Impact"

                                        S Offline
                                        S Offline
                                        Stephen Hewitt
                                        wrote on last edited by
                                        #21

                                        I gave you a 5 - I would have left it at that but then I saw the low score and felt compelled to reply. Steve

                                        R 1 Reply Last reply
                                        0
                                        • R Ryan Binns

                                          Actually, I've been using this for years doing embedded programming. Every clock cycle is precious ;)

                                          Ryan

                                          "Punctuality is only a virtue for those who aren't smart enough to think of good excuses for being late" John Nichol "Point Of Impact"

                                          N Offline
                                          N Offline
                                          Nibu babu thomas
                                          wrote on last edited by
                                          #22

                                          Yeah, well said.


                                          Nibu thomas Software Developer

                                          1 Reply Last reply
                                          0
                                          Reply
                                          • Reply as topic
                                          Log in to reply
                                          • Oldest to Newest
                                          • Newest to Oldest
                                          • Most Votes


                                          • Login

                                          • Don't have an account? Register

                                          • Login or register to search.
                                          • First post
                                            Last post
                                          0
                                          • Categories
                                          • Recent
                                          • Tags
                                          • Popular
                                          • World
                                          • Users
                                          • Groups