Hardcore Maths Question
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leppie wrote:
I wonder if its some kind of series...
It appears to be every 2520.
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yes thats true there are many , but if you think it might take a day to get the solution , without any computer help, but its worth
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Judah Himango wrote:
It appears to be every 2520.
It is. Modifying the your code that I modified and posted, shows this to be true :)
I'd like to help but I am too lazy to Google it for you.
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Judah Himango wrote:
I kind of cheated though
well thats ok , and of course there are more numbers but the fun is when you deduce how to do it It's the journey, not the destination
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Provided I've understood the question correctly, I think I've solved it. I kind of cheated though; I wrote a C# program that solves this:
int start = 1; int divisor = 10; while (divisor >= 2) { if (start % divisor == divisor - 1) { divisor--; } else { start++; divisor = 10; } }
Soon as that loop exits, you've got your number, which happens to be 2519.
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yeah yeah :) Hey, I worked for it at least. :) *edit* oooh, misunderstood you there leppie. I though you were chiding me for solving it with code rather than brain. :) Yes, there are other numbers, it appears every 2520 iteration matches the criteria.
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Judah Himango wrote:
I kind of cheated.
He did say "find a number" :) So there are more than one of these. I wonder if its some kind of series...
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2701439 last 4 digits by deduction, rest trial and error guess with 3/9 rule. :)
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It's not a mexican is it ?
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Ok lets me be the first to ask a maths question Find a number which 1. divided by 10 gives a remainder 9 2. divided by 9 gives remainder 8 --- --- so on till divided by 2 gives a remainder 1 Any one ?
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Here's a wild guess: 123456789 ? [edit] ok I got the 9 bit :p [edit] -- modified at 18:37 Wednesday 26th July, 2006
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