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Hardcore Maths Question

Scheduled Pinned Locked Moved Algorithms
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  • R Raj Lal

    yes thats true there are many , but if you think it might take a day to get the solution , without any computer help, but its worth

    Omit Needless Words - Strunk, William, Jr.


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    wrote on last edited by
    #37

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    • P Paul Conrad

      Judah Himango wrote:

      It appears to be every 2520.

      It is. Modifying the your code that I modified and posted, shows this to be true :)


      I'd like to help but I am too lazy to Google it for you.

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      • R Raj Lal

        Judah Himango wrote:

        I kind of cheated though

        well thats ok , and of course there are more numbers but the fun is when you deduce how to do it It's the journey, not the destination

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        • J Judah Gabriel Himango

          Provided I've understood the question correctly, I think I've solved it. I kind of cheated though; I wrote a C# program that solves this:

                  int start = 1;
                  int divisor = 10;
                  while (divisor >= 2)
                  {
                      if (start % divisor == divisor - 1)
                      {
                          divisor--;
                      }
                      else
                      {
                          start++;
                          divisor = 10;
                      }
                  }
          

          Soon as that loop exits, you've got your number, which happens to be 2519.

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          • J Judah Gabriel Himango

            yeah yeah :) Hey, I worked for it at least. :) *edit* oooh, misunderstood you there leppie. I though you were chiding me for solving it with code rather than brain. :) Yes, there are other numbers, it appears every 2520 iteration matches the criteria.

            Tech, life, family, faith: Give me a visit. I'm currently blogging about: Messianic Instrumentals (with audio) The apostle Paul, modernly speaking: Epistles of Paul Judah Himango

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            • L leppie

              Judah Himango wrote:

              I kind of cheated.

              He did say "find a number" :) So there are more than one of these. I wonder if its some kind of series...

              **

              xacc.ide-0.2.0.50 - now with partial MSBuild support!

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              • L leppie

                2701439 last 4 digits by deduction, rest trial and error guess with 3/9 rule. :)

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                • A Andrew Bleakley

                  It's not a mexican is it ?

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                  • R Raj Lal

                    Ok lets me be the first to ask a maths question Find a number which 1. divided by 10 gives a remainder 9 2. divided by 9 gives remainder 8 --- --- so on till divided by 2 gives a remainder 1 Any one ?

                    Omit Needless Words - Strunk, William, Jr.


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                    • L leppie

                      Here's a wild guess: 123456789 ? [edit] ok I got the 9 bit :p [edit] -- modified at 18:37 Wednesday 26th July, 2006

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