Java Integer Fun
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Integer i = 1;
Integer j = 1;
Integer n = 1000;
Integer m = 1000;boolean b1 = (i == j);
boolean b2 = (n == m);Now, what are
b1andb2? Surprisinglyb1is true,b2is false. Of course, if you know why it works this way, it's totally obvious. But if you're a Java novice, the code can be pretty surprising :) Let's hope Microsoft will never introduce ugly hacks like this into .NET...
_outp(0x64, 0xAD);and__asm mov al, 0xAD __asm out 0x64, aldo the same... but what do they do?? ;) (doesn't work on NT) -
Integer i = 1;
Integer j = 1;
Integer n = 1000;
Integer m = 1000;boolean b1 = (i == j);
boolean b2 = (n == m);Now, what are
b1andb2? Surprisinglyb1is true,b2is false. Of course, if you know why it works this way, it's totally obvious. But if you're a Java novice, the code can be pretty surprising :) Let's hope Microsoft will never introduce ugly hacks like this into .NET...
_outp(0x64, 0xAD);and__asm mov al, 0xAD __asm out 0x64, aldo the same... but what do they do?? ;) (doesn't work on NT) -
Integer i = 1;
Integer j = 1;
Integer n = 1000;
Integer m = 1000;boolean b1 = (i == j);
boolean b2 = (n == m);Now, what are
b1andb2? Surprisinglyb1is true,b2is false. Of course, if you know why it works this way, it's totally obvious. But if you're a Java novice, the code can be pretty surprising :) Let's hope Microsoft will never introduce ugly hacks like this into .NET...
_outp(0x64, 0xAD);and__asm mov al, 0xAD __asm out 0x64, aldo the same... but what do they do?? ;) (doesn't work on NT) -
More details please! I'm studyin basic Java in my own time, so an explanation would be great. :) Is the answer something to do with autoboxing? :confused:
When I am king, you will be first against the wall.
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I think you mean auto-wrapping where Java wraps the 1000 into an Integer Object automatically instead of throwing an error.
On the degree course I'm studying it is described as autoboxing! I think both are correct - and I have come across the term boxing used in the same context too. http://en.wikipedia.org/wiki/Autoboxing[^]
When I am king, you will be first against the wall.
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On the degree course I'm studying it is described as autoboxing! I think both are correct - and I have come across the term boxing used in the same context too. http://en.wikipedia.org/wiki/Autoboxing[^]
When I am king, you will be first against the wall.
hey that's good info, thanks. Here's some back... "For example, Java has primitive wrapper classes corresponding to each primitive type:" http://en.wikipedia.org/wiki/Primitive_wrapper_class[^] I find it strange that they would use two different words for similar meaning. Oh well :^) I guess "boxing" is the one that stuck.
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Integer i = 1;
Integer j = 1;
Integer n = 1000;
Integer m = 1000;boolean b1 = (i == j);
boolean b2 = (n == m);Now, what are
b1andb2? Surprisinglyb1is true,b2is false. Of course, if you know why it works this way, it's totally obvious. But if you're a Java novice, the code can be pretty surprising :) Let's hope Microsoft will never introduce ugly hacks like this into .NET...
_outp(0x64, 0xAD);and__asm mov al, 0xAD __asm out 0x64, aldo the same... but what do they do?? ;) (doesn't work on NT)OK, I assume that, as i, j, n and m are actually objects, and not primitive types, the correct way to compare them would be using the
equalsmethod thus:boolean b1 = i.equals(j);
boolean b2 = n.equals(m);But I still don't see why
i == j! Please put me out of my misery. :)
When I am king, you will be first against the wall.
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OK, I assume that, as i, j, n and m are actually objects, and not primitive types, the correct way to compare them would be using the
equalsmethod thus:boolean b1 = i.equals(j);
boolean b2 = n.equals(m);But I still don't see why
i == j! Please put me out of my misery. :)
When I am king, you will be first against the wall.
See java.lang.Integer.valueOf(int i) method code which is used for auboxing. It return the same object for values in range -128 .. 127
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Integer i = 1;
Integer j = 1;
Integer n = 1000;
Integer m = 1000;boolean b1 = (i == j);
boolean b2 = (n == m);Now, what are
b1andb2? Surprisinglyb1is true,b2is false. Of course, if you know why it works this way, it's totally obvious. But if you're a Java novice, the code can be pretty surprising :) Let's hope Microsoft will never introduce ugly hacks like this into .NET...
_outp(0x64, 0xAD);and__asm mov al, 0xAD __asm out 0x64, aldo the same... but what do they do?? ;) (doesn't work on NT)Ok, so here's the solution why it works this way :) First of all, we are using
Integerwrapper classes instead of the primitiveinttype. When compiling, the integral values 1 and 1000 are implicitely converted toIntegerobjects (called auto-boxing, frominttoInteger). So, we got 4 differentIntegerinstances, right? No! :) The Java VM automatically packs "small" primitive values into identical objects (1 is small, 1000 isn't small). You can easily verify this by pasting the code above into a small testing project and fire up the debugger:iandjreference the same object, whilenandmreference different objects. The==operator is comparing references, thereforeb1is true (same references) andb2is false (different references). Currently "small" means any integer between -128 and 127. But according to Sun this can change to [-32768, +32767] in the future. This packing trick has been introduced to solve performance problems when doing arithmetic with wrapper classes.
_outp(0x64, 0xAD);and__asm mov al, 0xAD __asm out 0x64, aldo the same... but what do they do?? ;) (doesn't work on NT) -
Ok, so here's the solution why it works this way :) First of all, we are using
Integerwrapper classes instead of the primitiveinttype. When compiling, the integral values 1 and 1000 are implicitely converted toIntegerobjects (called auto-boxing, frominttoInteger). So, we got 4 differentIntegerinstances, right? No! :) The Java VM automatically packs "small" primitive values into identical objects (1 is small, 1000 isn't small). You can easily verify this by pasting the code above into a small testing project and fire up the debugger:iandjreference the same object, whilenandmreference different objects. The==operator is comparing references, thereforeb1is true (same references) andb2is false (different references). Currently "small" means any integer between -128 and 127. But according to Sun this can change to [-32768, +32767] in the future. This packing trick has been introduced to solve performance problems when doing arithmetic with wrapper classes.
_outp(0x64, 0xAD);and__asm mov al, 0xAD __asm out 0x64, aldo the same... but what do they do?? ;) (doesn't work on NT):wtf: :omg: :~ :wtf: :omg: :~ :wtf: :omg: :~ That is absolutely insane.
--Mike-- Visual C++ MVP :cool: LINKS~! Ericahist | PimpFish | CP SearchBar v3.0 | C++ Forum FAQ
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Ok, so here's the solution why it works this way :) First of all, we are using
Integerwrapper classes instead of the primitiveinttype. When compiling, the integral values 1 and 1000 are implicitely converted toIntegerobjects (called auto-boxing, frominttoInteger). So, we got 4 differentIntegerinstances, right? No! :) The Java VM automatically packs "small" primitive values into identical objects (1 is small, 1000 isn't small). You can easily verify this by pasting the code above into a small testing project and fire up the debugger:iandjreference the same object, whilenandmreference different objects. The==operator is comparing references, thereforeb1is true (same references) andb2is false (different references). Currently "small" means any integer between -128 and 127. But according to Sun this can change to [-32768, +32767] in the future. This packing trick has been introduced to solve performance problems when doing arithmetic with wrapper classes.
_outp(0x64, 0xAD);and__asm mov al, 0xAD __asm out 0x64, aldo the same... but what do they do?? ;) (doesn't work on NT) -
Integer i = 1;
Integer j = 1;
Integer n = 1000;
Integer m = 1000;boolean b1 = (i == j);
boolean b2 = (n == m);Now, what are
b1andb2? Surprisinglyb1is true,b2is false. Of course, if you know why it works this way, it's totally obvious. But if you're a Java novice, the code can be pretty surprising :) Let's hope Microsoft will never introduce ugly hacks like this into .NET...
_outp(0x64, 0xAD);and__asm mov al, 0xAD __asm out 0x64, aldo the same... but what do they do?? ;) (doesn't work on NT)I'm glad I don't code java.
how vital enterprise application are for proactive organizations leveraging collective synergy to think outside the box and formulate their key objectives into a win-win game plan with a quality-driven approach that focuses on empowering key players to drive-up their core competencies and increase expectations with an all-around initiative to drive up the bottom-line. But of course, that's all a "high level" overview of things --thedailywtf 3/21/06
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Ok, so here's the solution why it works this way :) First of all, we are using
Integerwrapper classes instead of the primitiveinttype. When compiling, the integral values 1 and 1000 are implicitely converted toIntegerobjects (called auto-boxing, frominttoInteger). So, we got 4 differentIntegerinstances, right? No! :) The Java VM automatically packs "small" primitive values into identical objects (1 is small, 1000 isn't small). You can easily verify this by pasting the code above into a small testing project and fire up the debugger:iandjreference the same object, whilenandmreference different objects. The==operator is comparing references, thereforeb1is true (same references) andb2is false (different references). Currently "small" means any integer between -128 and 127. But according to Sun this can change to [-32768, +32767] in the future. This packing trick has been introduced to solve performance problems when doing arithmetic with wrapper classes.
_outp(0x64, 0xAD);and__asm mov al, 0xAD __asm out 0x64, aldo the same... but what do they do?? ;) (doesn't work on NT) -
Integer i = 1;
Integer j = 1;
Integer n = 1000;
Integer m = 1000;boolean b1 = (i == j);
boolean b2 = (n == m);Now, what are
b1andb2? Surprisinglyb1is true,b2is false. Of course, if you know why it works this way, it's totally obvious. But if you're a Java novice, the code can be pretty surprising :) Let's hope Microsoft will never introduce ugly hacks like this into .NET...
_outp(0x64, 0xAD);and__asm mov al, 0xAD __asm out 0x64, aldo the same... but what do they do?? ;) (doesn't work on NT) -
:wtf: :omg: :~ :wtf: :omg: :~ :wtf: :omg: :~ That is absolutely insane.
--Mike-- Visual C++ MVP :cool: LINKS~! Ericahist | PimpFish | CP SearchBar v3.0 | C++ Forum FAQ
Michael Dunn wrote:
That is absolutely insane.
We are talking about Java, remember... ;)
Ryan
"Punctuality is only a virtue for those who aren't smart enough to think of good excuses for being late" John Nichol "Point Of Impact"
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Ok, so here's the solution why it works this way :) First of all, we are using
Integerwrapper classes instead of the primitiveinttype. When compiling, the integral values 1 and 1000 are implicitely converted toIntegerobjects (called auto-boxing, frominttoInteger). So, we got 4 differentIntegerinstances, right? No! :) The Java VM automatically packs "small" primitive values into identical objects (1 is small, 1000 isn't small). You can easily verify this by pasting the code above into a small testing project and fire up the debugger:iandjreference the same object, whilenandmreference different objects. The==operator is comparing references, thereforeb1is true (same references) andb2is false (different references). Currently "small" means any integer between -128 and 127. But according to Sun this can change to [-32768, +32767] in the future. This packing trick has been introduced to solve performance problems when doing arithmetic with wrapper classes.
_outp(0x64, 0xAD);and__asm mov al, 0xAD __asm out 0x64, aldo the same... but what do they do?? ;) (doesn't work on NT)But what happens when the boxed value is modified? Does some kind of "Write on copy" thing happen in the background?
Regards Senthil _____________________________ My Blog | My Articles | WinMacro
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Integer i = 1;
Integer j = 1;
Integer n = 1000;
Integer m = 1000;boolean b1 = (i == j);
boolean b2 = (n == m);Now, what are
b1andb2? Surprisinglyb1is true,b2is false. Of course, if you know why it works this way, it's totally obvious. But if you're a Java novice, the code can be pretty surprising :) Let's hope Microsoft will never introduce ugly hacks like this into .NET...
_outp(0x64, 0xAD);and__asm mov al, 0xAD __asm out 0x64, aldo the same... but what do they do?? ;) (doesn't work on NT)The people who decided that should be euthanized as a service to humanity.
Software Zen:
delete this;