Skip to content
  • Categories
  • Recent
  • Tags
  • Popular
  • World
  • Users
  • Groups
Skins
  • Light
  • Cerulean
  • Cosmo
  • Flatly
  • Journal
  • Litera
  • Lumen
  • Lux
  • Materia
  • Minty
  • Morph
  • Pulse
  • Sandstone
  • Simplex
  • Sketchy
  • Spacelab
  • United
  • Yeti
  • Zephyr
  • Dark
  • Cyborg
  • Darkly
  • Quartz
  • Slate
  • Solar
  • Superhero
  • Vapor

  • Default (No Skin)
  • No Skin
Collapse
Code Project
  1. Home
  2. General Programming
  3. C#
  4. New Editor

New Editor

Scheduled Pinned Locked Moved C#
questiontutorial
15 Posts 4 Posters 0 Views 1 Watching
  • Oldest to Newest
  • Newest to Oldest
  • Most Votes
Reply
  • Reply as topic
Log in to reply
This topic has been deleted. Only users with topic management privileges can see it.
  • G GunaChinna

    Hi, When i use Main(string[] args) or Environment.GetCommandLineArgs; it shows me the following error. Error 1 'string' does not contain a definition for 'rtbFile' (Richtextbox instance)

    B Offline
    B Offline
    bobsugar222
    wrote on last edited by
    #6

    show us the code.

    G 1 Reply Last reply
    0
    • B bobsugar222

      show us the code.

      G Offline
      G Offline
      GunaChinna
      wrote on last edited by
      #7

      The error is ok now. and i have done main(string[] args) or Environment.GetCommandLineargs..... But still when i double click the created file(file with .gun extension),, it still doesn't contain the content.

      L 1 Reply Last reply
      0
      • G GunaChinna

        The error is ok now. and i have done main(string[] args) or Environment.GetCommandLineargs..... But still when i double click the created file(file with .gun extension),, it still doesn't contain the content.

        L Offline
        L Offline
        Lost User
        wrote on last edited by
        #8

        Just for example :

        static void Main(string[] args)
        {
        string fileToOpen = args[0]; // it is the same like openFileDialog.FileName

        // Now you MUST open the file "fileToOpen"
        }

        G 1 Reply Last reply
        0
        • L Lost User

          Just for example :

          static void Main(string[] args)
          {
          string fileToOpen = args[0]; // it is the same like openFileDialog.FileName

          // Now you MUST open the file "fileToOpen"
          }

          G Offline
          G Offline
          GunaChinna
          wrote on last edited by
          #9

          I dont get what u try to say. This is my code. Can u suggest with this code....(ofdFile=Openfiledialog,rtbFile=richtextbox) void btnOpen_Click(object sender, EventArgs e) { ofdFile = new OpenFileDialog(); ofdFile.DefaultExt = @"*.gun"; ofdFile.Filter = @"Gun Files|*.gun"; if (ofdFile.ShowDialog() == System.Windows.Forms.DialogResult.OK && ofdFile.FileName.Length > 0) { //ofdFile.FileName. rtbFile.LoadFile(ofdFile.FileName, RichTextBoxStreamType.PlainText); } }

          G L 2 Replies Last reply
          0
          • G GunaChinna

            I dont get what u try to say. This is my code. Can u suggest with this code....(ofdFile=Openfiledialog,rtbFile=richtextbox) void btnOpen_Click(object sender, EventArgs e) { ofdFile = new OpenFileDialog(); ofdFile.DefaultExt = @"*.gun"; ofdFile.Filter = @"Gun Files|*.gun"; if (ofdFile.ShowDialog() == System.Windows.Forms.DialogResult.OK && ofdFile.FileName.Length > 0) { //ofdFile.FileName. rtbFile.LoadFile(ofdFile.FileName, RichTextBoxStreamType.PlainText); } }

            G Offline
            G Offline
            GunaChinna
            wrote on last edited by
            #10

            And my main function is in Program.cs file

            1 Reply Last reply
            0
            • G GunaChinna

              I dont get what u try to say. This is my code. Can u suggest with this code....(ofdFile=Openfiledialog,rtbFile=richtextbox) void btnOpen_Click(object sender, EventArgs e) { ofdFile = new OpenFileDialog(); ofdFile.DefaultExt = @"*.gun"; ofdFile.Filter = @"Gun Files|*.gun"; if (ofdFile.ShowDialog() == System.Windows.Forms.DialogResult.OK && ofdFile.FileName.Length > 0) { //ofdFile.FileName. rtbFile.LoadFile(ofdFile.FileName, RichTextBoxStreamType.PlainText); } }

              L Offline
              L Offline
              Lost User
              wrote on last edited by
              #11

              pass the args[0] to your form class.

              static void Main(string[] args)
              {
              Application.Run(new Form1(args[0]));
              }

              For example your form class is Form1. Then change the constructor to

              public Form1(string fileToBeOpened)
              {
              if(fileToBeOpened != string.Empty)
              {
              // rtbFile.LoadFile(fileToBeOpened , RichTextBoxStreamType.PlainText);
              }
              }

              G 1 Reply Last reply
              0
              • L Lost User

                pass the args[0] to your form class.

                static void Main(string[] args)
                {
                Application.Run(new Form1(args[0]));
                }

                For example your form class is Form1. Then change the constructor to

                public Form1(string fileToBeOpened)
                {
                if(fileToBeOpened != string.Empty)
                {
                // rtbFile.LoadFile(fileToBeOpened , RichTextBoxStreamType.PlainText);
                }
                }

                G Offline
                G Offline
                GunaChinna
                wrote on last edited by
                #12

                It shows me 'IndexOutOfRangeException Unhandled' in program.cs Application.Run(new Form1(args[0]));

                L 1 Reply Last reply
                0
                • G GunaChinna

                  It shows me 'IndexOutOfRangeException Unhandled' in program.cs Application.Run(new Form1(args[0]));

                  L Offline
                  L Offline
                  Lost User
                  wrote on last edited by
                  #13

                  I think you just COPY and PASTE the code. You must AWARE OF ERRORS. You MUST check if args.Length > 0 // you get the file directly args.Length == 0 // without file

                  G 1 Reply Last reply
                  0
                  • L Lost User

                    I think you just COPY and PASTE the code. You must AWARE OF ERRORS. You MUST check if args.Length > 0 // you get the file directly args.Length == 0 // without file

                    G Offline
                    G Offline
                    GunaChinna
                    wrote on last edited by
                    #14

                    Yes it works. Thanks a lot.

                    G 1 Reply Last reply
                    0
                    • G GunaChinna

                      Yes it works. Thanks a lot.

                      G Offline
                      G Offline
                      GunaChinna
                      wrote on last edited by
                      #15

                      Will get u back if i get more doubts.

                      1 Reply Last reply
                      0
                      Reply
                      • Reply as topic
                      Log in to reply
                      • Oldest to Newest
                      • Newest to Oldest
                      • Most Votes


                      • Login

                      • Don't have an account? Register

                      • Login or register to search.
                      • First post
                        Last post
                      0
                      • Categories
                      • Recent
                      • Tags
                      • Popular
                      • World
                      • Users
                      • Groups