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Scheduled Pinned Locked Moved C#
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  • L Lost User

    Look for method "Main" in your application. If you have no parameters in it "Main()" then change it to "Main(string[] args)". If you double-click .gun file, then it is like calling using command prompt: MyApplication.exe myFile.gun Just take your .gun file in "args" variable.

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    bobsugar222
    wrote on last edited by
    #4

    Or just call Environment.GetCommandLineArgs()

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    • G GunaChinna

      Requirement: I want to create an application, which should be able to create a file, with the file extension be specified by me. And, when i double click to open that file, it should open it's content in that application. How can this be achieved? ( like word,excel..etc) Code so far: For example.. I have created a application with a Richtextbox control to display data,buttons to create a new file, openfile,savefile and to exit. And let my file extension be ".gun". Time to Answer: Now, what happens is i create new file, save(savefiledialog) it with .gun extension. This files gets opened when i open it using 'open(openfiledialog) button' which is present in my application. But when i double this file (which is placed on desktop) it opens only the application and not with the content.? How can i get it with the content when the file is double clicked?

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      GunaChinna
      wrote on last edited by
      #5

      Hi, When i use Main(string[] args) or Environment.GetCommandLineArgs; it shows me the following error. Error 1 'string' does not contain a definition for 'rtbFile' (Richtextbox instance)

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      • G GunaChinna

        Hi, When i use Main(string[] args) or Environment.GetCommandLineArgs; it shows me the following error. Error 1 'string' does not contain a definition for 'rtbFile' (Richtextbox instance)

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        bobsugar222
        wrote on last edited by
        #6

        show us the code.

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        • B bobsugar222

          show us the code.

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          GunaChinna
          wrote on last edited by
          #7

          The error is ok now. and i have done main(string[] args) or Environment.GetCommandLineargs..... But still when i double click the created file(file with .gun extension),, it still doesn't contain the content.

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          • G GunaChinna

            The error is ok now. and i have done main(string[] args) or Environment.GetCommandLineargs..... But still when i double click the created file(file with .gun extension),, it still doesn't contain the content.

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            Lost User
            wrote on last edited by
            #8

            Just for example :

            static void Main(string[] args)
            {
            string fileToOpen = args[0]; // it is the same like openFileDialog.FileName

            // Now you MUST open the file "fileToOpen"
            }

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            • L Lost User

              Just for example :

              static void Main(string[] args)
              {
              string fileToOpen = args[0]; // it is the same like openFileDialog.FileName

              // Now you MUST open the file "fileToOpen"
              }

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              GunaChinna
              wrote on last edited by
              #9

              I dont get what u try to say. This is my code. Can u suggest with this code....(ofdFile=Openfiledialog,rtbFile=richtextbox) void btnOpen_Click(object sender, EventArgs e) { ofdFile = new OpenFileDialog(); ofdFile.DefaultExt = @"*.gun"; ofdFile.Filter = @"Gun Files|*.gun"; if (ofdFile.ShowDialog() == System.Windows.Forms.DialogResult.OK && ofdFile.FileName.Length > 0) { //ofdFile.FileName. rtbFile.LoadFile(ofdFile.FileName, RichTextBoxStreamType.PlainText); } }

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              • G GunaChinna

                I dont get what u try to say. This is my code. Can u suggest with this code....(ofdFile=Openfiledialog,rtbFile=richtextbox) void btnOpen_Click(object sender, EventArgs e) { ofdFile = new OpenFileDialog(); ofdFile.DefaultExt = @"*.gun"; ofdFile.Filter = @"Gun Files|*.gun"; if (ofdFile.ShowDialog() == System.Windows.Forms.DialogResult.OK && ofdFile.FileName.Length > 0) { //ofdFile.FileName. rtbFile.LoadFile(ofdFile.FileName, RichTextBoxStreamType.PlainText); } }

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                GunaChinna
                wrote on last edited by
                #10

                And my main function is in Program.cs file

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                • G GunaChinna

                  I dont get what u try to say. This is my code. Can u suggest with this code....(ofdFile=Openfiledialog,rtbFile=richtextbox) void btnOpen_Click(object sender, EventArgs e) { ofdFile = new OpenFileDialog(); ofdFile.DefaultExt = @"*.gun"; ofdFile.Filter = @"Gun Files|*.gun"; if (ofdFile.ShowDialog() == System.Windows.Forms.DialogResult.OK && ofdFile.FileName.Length > 0) { //ofdFile.FileName. rtbFile.LoadFile(ofdFile.FileName, RichTextBoxStreamType.PlainText); } }

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                  Lost User
                  wrote on last edited by
                  #11

                  pass the args[0] to your form class.

                  static void Main(string[] args)
                  {
                  Application.Run(new Form1(args[0]));
                  }

                  For example your form class is Form1. Then change the constructor to

                  public Form1(string fileToBeOpened)
                  {
                  if(fileToBeOpened != string.Empty)
                  {
                  // rtbFile.LoadFile(fileToBeOpened , RichTextBoxStreamType.PlainText);
                  }
                  }

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                  • L Lost User

                    pass the args[0] to your form class.

                    static void Main(string[] args)
                    {
                    Application.Run(new Form1(args[0]));
                    }

                    For example your form class is Form1. Then change the constructor to

                    public Form1(string fileToBeOpened)
                    {
                    if(fileToBeOpened != string.Empty)
                    {
                    // rtbFile.LoadFile(fileToBeOpened , RichTextBoxStreamType.PlainText);
                    }
                    }

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                    GunaChinna
                    wrote on last edited by
                    #12

                    It shows me 'IndexOutOfRangeException Unhandled' in program.cs Application.Run(new Form1(args[0]));

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                    • G GunaChinna

                      It shows me 'IndexOutOfRangeException Unhandled' in program.cs Application.Run(new Form1(args[0]));

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                      L Offline
                      Lost User
                      wrote on last edited by
                      #13

                      I think you just COPY and PASTE the code. You must AWARE OF ERRORS. You MUST check if args.Length > 0 // you get the file directly args.Length == 0 // without file

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                      • L Lost User

                        I think you just COPY and PASTE the code. You must AWARE OF ERRORS. You MUST check if args.Length > 0 // you get the file directly args.Length == 0 // without file

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                        GunaChinna
                        wrote on last edited by
                        #14

                        Yes it works. Thanks a lot.

                        G 1 Reply Last reply
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                        • G GunaChinna

                          Yes it works. Thanks a lot.

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                          G Offline
                          GunaChinna
                          wrote on last edited by
                          #15

                          Will get u back if i get more doubts.

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