New Editor
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Requirement: I want to create an application, which should be able to create a file, with the file extension be specified by me. And, when i double click to open that file, it should open it's content in that application. How can this be achieved? ( like word,excel..etc) Code so far: For example.. I have created a application with a Richtextbox control to display data,buttons to create a new file, openfile,savefile and to exit. And let my file extension be ".gun". Time to Answer: Now, what happens is i create new file, save(savefiledialog) it with .gun extension. This files gets opened when i open it using 'open(openfiledialog) button' which is present in my application. But when i double this file (which is placed on desktop) it opens only the application and not with the content.? How can i get it with the content when the file is double clicked?
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Requirement: I want to create an application, which should be able to create a file, with the file extension be specified by me. And, when i double click to open that file, it should open it's content in that application. How can this be achieved? ( like word,excel..etc) Code so far: For example.. I have created a application with a Richtextbox control to display data,buttons to create a new file, openfile,savefile and to exit. And let my file extension be ".gun". Time to Answer: Now, what happens is i create new file, save(savefiledialog) it with .gun extension. This files gets opened when i open it using 'open(openfiledialog) button' which is present in my application. But when i double this file (which is placed on desktop) it opens only the application and not with the content.? How can i get it with the content when the file is double clicked?
Look for method "Main" in your application. If you have no parameters in it "Main()" then change it to "Main(string[] args)". If you double-click .gun file, then it is like calling using command prompt: MyApplication.exe myFile.gun Just take your .gun file in "args" variable.
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Requirement: I want to create an application, which should be able to create a file, with the file extension be specified by me. And, when i double click to open that file, it should open it's content in that application. How can this be achieved? ( like word,excel..etc) Code so far: For example.. I have created a application with a Richtextbox control to display data,buttons to create a new file, openfile,savefile and to exit. And let my file extension be ".gun". Time to Answer: Now, what happens is i create new file, save(savefiledialog) it with .gun extension. This files gets opened when i open it using 'open(openfiledialog) button' which is present in my application. But when i double this file (which is placed on desktop) it opens only the application and not with the content.? How can i get it with the content when the file is double clicked?
You will need to associate the file extension *.gun with your application - the article http://support.microsoft.com/kb/185453 describes for VB but its basicallyde sticking some info in the registry...
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Look for method "Main" in your application. If you have no parameters in it "Main()" then change it to "Main(string[] args)". If you double-click .gun file, then it is like calling using command prompt: MyApplication.exe myFile.gun Just take your .gun file in "args" variable.
Or just call
Environment.GetCommandLineArgs() -
Requirement: I want to create an application, which should be able to create a file, with the file extension be specified by me. And, when i double click to open that file, it should open it's content in that application. How can this be achieved? ( like word,excel..etc) Code so far: For example.. I have created a application with a Richtextbox control to display data,buttons to create a new file, openfile,savefile and to exit. And let my file extension be ".gun". Time to Answer: Now, what happens is i create new file, save(savefiledialog) it with .gun extension. This files gets opened when i open it using 'open(openfiledialog) button' which is present in my application. But when i double this file (which is placed on desktop) it opens only the application and not with the content.? How can i get it with the content when the file is double clicked?
Hi, When i use Main(string[] args) or Environment.GetCommandLineArgs; it shows me the following error. Error 1 'string' does not contain a definition for 'rtbFile' (Richtextbox instance)
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Hi, When i use Main(string[] args) or Environment.GetCommandLineArgs; it shows me the following error. Error 1 'string' does not contain a definition for 'rtbFile' (Richtextbox instance)
show us the code.
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show us the code.
The error is ok now. and i have done main(string[] args) or Environment.GetCommandLineargs..... But still when i double click the created file(file with .gun extension),, it still doesn't contain the content.
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The error is ok now. and i have done main(string[] args) or Environment.GetCommandLineargs..... But still when i double click the created file(file with .gun extension),, it still doesn't contain the content.
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Just for example :
static void Main(string[] args)
{
string fileToOpen = args[0]; // it is the same like openFileDialog.FileName// Now you MUST open the file "fileToOpen"
}I dont get what u try to say. This is my code. Can u suggest with this code....(ofdFile=Openfiledialog,rtbFile=richtextbox) void btnOpen_Click(object sender, EventArgs e) { ofdFile = new OpenFileDialog(); ofdFile.DefaultExt = @"*.gun"; ofdFile.Filter = @"Gun Files|*.gun"; if (ofdFile.ShowDialog() == System.Windows.Forms.DialogResult.OK && ofdFile.FileName.Length > 0) { //ofdFile.FileName. rtbFile.LoadFile(ofdFile.FileName, RichTextBoxStreamType.PlainText); } }
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I dont get what u try to say. This is my code. Can u suggest with this code....(ofdFile=Openfiledialog,rtbFile=richtextbox) void btnOpen_Click(object sender, EventArgs e) { ofdFile = new OpenFileDialog(); ofdFile.DefaultExt = @"*.gun"; ofdFile.Filter = @"Gun Files|*.gun"; if (ofdFile.ShowDialog() == System.Windows.Forms.DialogResult.OK && ofdFile.FileName.Length > 0) { //ofdFile.FileName. rtbFile.LoadFile(ofdFile.FileName, RichTextBoxStreamType.PlainText); } }
And my main function is in Program.cs file
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I dont get what u try to say. This is my code. Can u suggest with this code....(ofdFile=Openfiledialog,rtbFile=richtextbox) void btnOpen_Click(object sender, EventArgs e) { ofdFile = new OpenFileDialog(); ofdFile.DefaultExt = @"*.gun"; ofdFile.Filter = @"Gun Files|*.gun"; if (ofdFile.ShowDialog() == System.Windows.Forms.DialogResult.OK && ofdFile.FileName.Length > 0) { //ofdFile.FileName. rtbFile.LoadFile(ofdFile.FileName, RichTextBoxStreamType.PlainText); } }
pass the args[0] to your form class.
static void Main(string[] args)
{
Application.Run(new Form1(args[0]));
}For example your form class is Form1. Then change the constructor to
public Form1(string fileToBeOpened)
{
if(fileToBeOpened != string.Empty)
{
// rtbFile.LoadFile(fileToBeOpened , RichTextBoxStreamType.PlainText);
}
} -
pass the args[0] to your form class.
static void Main(string[] args)
{
Application.Run(new Form1(args[0]));
}For example your form class is Form1. Then change the constructor to
public Form1(string fileToBeOpened)
{
if(fileToBeOpened != string.Empty)
{
// rtbFile.LoadFile(fileToBeOpened , RichTextBoxStreamType.PlainText);
}
}It shows me 'IndexOutOfRangeException Unhandled' in program.cs Application.Run(new Form1(args[0]));
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It shows me 'IndexOutOfRangeException Unhandled' in program.cs Application.Run(new Form1(args[0]));
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I think you just COPY and PASTE the code. You must AWARE OF ERRORS. You MUST check if args.Length > 0 // you get the file directly args.Length == 0 // without file
Yes it works. Thanks a lot.
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Yes it works. Thanks a lot.
Will get u back if i get more doubts.