"Simple" POTD [modified]

Jim Crafton

wouldn't 9 to the power of (9 to the power of 9)

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RodgerB

999! i.e. 999 factorial

Paul Watson

Quartz... wrote:

How will you divide 5 potatoes among 6 childrens, you cannot use fractions

Plant one potatoe, wait awhile, get out two, give to six children. Though by then they are probably all dead from starvation so you get to keep the potatoes for yourself.

regards, Paul Watson Ireland & South Africa

Shog9 wrote:

And with that, Paul closed his browser, sipped his herbal tea, fixed the flower in his hair, and smiled brightly at the multitude of cute, furry animals flocking around the grassy hillside where he sat coding Ruby on his Mac...

Lost User

9^9^9!

The tigress is here :-D

Shog9 0

Quartz... wrote:

How will you divide 5 potatoes among 6 childrens, you cannot use fractions

Since we can't use fractions, we'll have to use a knife to divide up the potatoes. This is fine though; knives cut through potatoes much faster than fractions do.
Eat one, then give a potato to each child.
Sit children in a row, give each a fork, then place potatoes between them. They'll work it out...
Sit children in a circle, and working clockwise, hand out potatoes. When you run out of potatoes, start handing out rocks. Then run away.

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Andy Brummer

You could always just mash the potatoes.

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Fernando A Gomez F

peterchen wrote:

Or what about 99/0

:wtf: undefined... at least in the real field...

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brianwelsch

Shog9 wrote:

Eat one, then give a potato to each child.

This one concerns me a little, Shog. For the numbers to work out, you'd have to have meant to eat a child, then pass out the 5 spuds to the remaining 5 sad, fearful children. Otherwise, excellent solutions! Good "out-of-the-box" thinking!

BW

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Ignorance and prejudice and fear walk hand in hand.
-- Neil Peart

Shog9 0

brianwelsch wrote:

For the numbers to work out, you'd have to have meant to eat a child, then pass out the 5 spuds to the remaining 5 sad, fearful children.

Yeah, but i'll bet they'd appreciate their potatoes a bit more after that...

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MrBic

I think the first question you need to ask is: are they your children? or.... (sorry for this one) You could always have meat and potatoes.....

Gary Kirkham

limit as x->0 11/x

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Raj Lal

A 1: 999 As a lot of you had already figured out , the question was only three digits so cannot use factorial there. A 2: Serve mashed potatoes , a lot of you have guessed this one too

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Raj Lal

brianwelsch wrote:

5 sad, fearful children

LMAO

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Ravi Bhavnani

My guess for the largest value would be ((9! raised to 9!) raised to 9!). /ravi

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peterchen

but as close as possible to "as big as it can get" :rolleyes: ok, lim (x->0) (99/x)<7code> would stretch the requirements a bit (and it's not really a number, but it might pass) * * * _Developers, Developers, Developers, Developers, Developers, Developers, Velopers, Develprs, Developers!_ We are a big screwed up dysfunctional psychotic happy family - some more screwed up, others more happy, but everybody's psychotic _joint venture definition of CP_ [Linkify!](http://www.codeproject.com/useritems/Linkify.asp)|[Fold With Us!](http://www.codeproject.com/script/profile/whos_who.asp?msg=919055&id=175#xx919055xx)

RC_Sebastien_C

Good, but you're loosing a bit on the coolness factor posting an hour after the solution and without using the superscript :-D

Ravi Bhavnani

HollyHooo wrote:

loosing a bit on the coolness factor

That's OK. Everyone knows: ASSERT (me == !cool); ASSERT ((me & cool) == NULL); :) /ravi

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RC_Sebastien_C

A 1: Question was only three digits, but question should have been only three digits and digts only. A 2: I prefer Shog's answer

Raj Lal

HollyHooo wrote:

only three digits and digts only.

oh ! that IFF factor :-> missed it

HollyHooo wrote:

I prefer Shog's answer

me too :-D

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RC_Sebastien_C

You gained it all back :) thanks for taking it for what it was, as a joke