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GDI / GDI+

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  • A Adno

    hi im trying to code below, but is not working. void update(HWND hwnd){ HBITMAP pBitmap; pBitmap = LoadBitmap(GetModuleHandle(NULL), MAKEINTRESOURCE(IDB_BITMAP1)); // using this it works //Image* pBitmap = new Image(L"clockbg.bmp"); // this is the same image as above, it doesn't work when i use it no errors it compiles fine just no window // i want to use GDI+ to load the image because i want to use a png just trying to get it to work first HDC pDC = GetDC(hwnd); HDC dcMem; dcMem = CreateCompatibleDC(pDC); COLORREF colour; colour = RGB(255,255,255); SelectObject(dcMem,pBitmap); BLENDFUNCTION blend; blend.BlendOp = AC_SRC_OVER; blend.BlendFlags = 0; blend.SourceConstantAlpha = 255; blend.AlphaFormat = AC_SRC_ALPHA; POINT ptSrc = {0, 0 }; SIZE sz = { 270, 270 }; //int t = UpdateLayeredWindow(hwnd, NULL, NULL, &sz, dcMem, &ptSrc, colour, &blend, ULW_COLORKEY ); int p = UpdateLayeredWindow(hwnd, NULL, NULL, &sz, dcMem, &ptSrc, colour, &blend, LWA_ALPHA ); } thank you

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    Hamid Taebi
    wrote on last edited by
    #2

    Whats the problem?


    WhiteSky


    A 1 Reply Last reply
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    • H Hamid Taebi

      Whats the problem?


      WhiteSky


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      Adno
      wrote on last edited by
      #3

      pBitmap = LoadBitmap(GetModuleHandle(NULL), MAKEINTRESOURCE(IDB_BITMAP1)); // ^ this shows the window Image* pBitmap = new Image(L"clockbg.bmp"); ^ this does not they are the same image loaded differently. thank you

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      • A Adno

        pBitmap = LoadBitmap(GetModuleHandle(NULL), MAKEINTRESOURCE(IDB_BITMAP1)); // ^ this shows the window Image* pBitmap = new Image(L"clockbg.bmp"); ^ this does not they are the same image loaded differently. thank you

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        Mark Salsbery
        wrote on last edited by
        #4

        Lamefif wrote:

        Image* pBitmap = new Image(L"clockbg.bmp"); ^ this does not

        Maybe you need the full pathname of the file? Mark

        "Posting a VB.NET question in the C++ forum will end in tears." Chris Maunder

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        • A Adno

          pBitmap = LoadBitmap(GetModuleHandle(NULL), MAKEINTRESOURCE(IDB_BITMAP1)); // ^ this shows the window Image* pBitmap = new Image(L"clockbg.bmp"); ^ this does not they are the same image loaded differently. thank you

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          Hamid Taebi
          wrote on last edited by
          #5

          And where's clockbg.bmp(path of file)?


          WhiteSky


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          • H Hamid Taebi

            And where's clockbg.bmp(path of file)?


            WhiteSky


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            Adno
            wrote on last edited by
            #6

            the image is in my project folder and i know it loads because i can display it like this: Bitmap bitmap(L"clockbg.bmp"); graphics.DrawImage(&bitmap, 0, 0); and it shows :confused: thanks

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            • A Adno

              the image is in my project folder and i know it loads because i can display it like this: Bitmap bitmap(L"clockbg.bmp"); graphics.DrawImage(&bitmap, 0, 0); and it shows :confused: thanks

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              Mark Salsbery
              wrote on last edited by
              #7

              Bitmap is derived from Image. If Bitmap bitmap(L"clockbg.bmp"); graphics.DrawImage(&bitmap, 0, 0); works, then Image* pBitmap = new Image(L"clockbg.bmp"); graphics.DrawImage(pBitmap, 0, 0); should work. Mark

              "Posting a VB.NET question in the C++ forum will end in tears." Chris Maunder

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              • M Mark Salsbery

                Bitmap is derived from Image. If Bitmap bitmap(L"clockbg.bmp"); graphics.DrawImage(&bitmap, 0, 0); works, then Image* pBitmap = new Image(L"clockbg.bmp"); graphics.DrawImage(pBitmap, 0, 0); should work. Mark

                "Posting a VB.NET question in the C++ forum will end in tears." Chris Maunder

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                Adno
                wrote on last edited by
                #8

                i know Mark thats not my problem, but when i use GDI+ to load the image: Image* pBitmap = new Image(L"clockbg.bmp"); or Bitmap. as appose to: HBITMAP pBitmap = LoadBitmap(GetModuleHandle(NULL), MAKEINTRESOURCE(IDB_BITMAP1)); and i use it for my: UpdateLayeredWindow(hwnd, NULL, NULL, &sz, dcMem, &ptSrc, colour, &blend, LWA_ALPHA ); the window doesn't show, as i've posted in the code above is the same image and i now it loads, i dont now.. thank you

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                • A Adno

                  i know Mark thats not my problem, but when i use GDI+ to load the image: Image* pBitmap = new Image(L"clockbg.bmp"); or Bitmap. as appose to: HBITMAP pBitmap = LoadBitmap(GetModuleHandle(NULL), MAKEINTRESOURCE(IDB_BITMAP1)); and i use it for my: UpdateLayeredWindow(hwnd, NULL, NULL, &sz, dcMem, &ptSrc, colour, &blend, LWA_ALPHA ); the window doesn't show, as i've posted in the code above is the same image and i now it loads, i dont now.. thank you

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                  Mark Salsbery
                  wrote on last edited by
                  #9

                  Sorry about that - I should have read the first post more closely :) Maybe this will work better...

                  Image* pBitmap = new Image(L"clockbg.bmp");

                  HDC pDC = GetDC(hwnd);
                  HDC dcMem;
                  dcMem = CreateCompatibleDC(pDC);
                  COLORREF colour;
                  colour = RGB(255,255,255);

                  // Assuming white is the transparent color
                  HBITMAP hBitmap; pBitmap->GetHBITMAP(Color(0xFF,0xFF,0xFF), &hBitmap);

                  SelectObject(dcMem, hBitmap);
                  ...

                  "Posting a VB.NET question in the C++ forum will end in tears." Chris Maunder

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                  • M Mark Salsbery

                    Sorry about that - I should have read the first post more closely :) Maybe this will work better...

                    Image* pBitmap = new Image(L"clockbg.bmp");

                    HDC pDC = GetDC(hwnd);
                    HDC dcMem;
                    dcMem = CreateCompatibleDC(pDC);
                    COLORREF colour;
                    colour = RGB(255,255,255);

                    // Assuming white is the transparent color
                    HBITMAP hBitmap; pBitmap->GetHBITMAP(Color(0xFF,0xFF,0xFF), &hBitmap);

                    SelectObject(dcMem, hBitmap);
                    ...

                    "Posting a VB.NET question in the C++ forum will end in tears." Chris Maunder

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                    Adno
                    wrote on last edited by
                    #10

                    Thanks Mark, but my aim is to use the transparency of the png and Alpha channel to define the transparency, perpixelvlue as it were. am goind all wrong about it? thanks

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                    • A Adno

                      Thanks Mark, but my aim is to use the transparency of the png and Alpha channel to define the transparency, perpixelvlue as it were. am goind all wrong about it? thanks

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                      Mark Salsbery
                      wrote on last edited by
                      #11

                      I "think" you may be able to use a 32-bit ARGB DIBsection - I put together this test just to make sure the alpha channel stuff was working. (My "hdc" would be your "dcMem" and you wouldn't want to delete it or un-select your alpha bitmap like I have if you pass it to UpdateLayeredWindow())

                      Image TransparentSrcBitmap(L"clockbg.bmp");

                      LONG lImageWidth = TransparentSrcBitmap.GetWidth();
                      LONG lImageHeight = TransparentSrcBitmap.GetHeight();
                      WORD wBitsPerPixel = 32;

                      //LONG lBytesPerRow = (((lImageWidth * (long)wBitsPerPixel + 31L) & (~31L)) / 8L);
                      LONG lBytesPerRow = lImageWidth * 4;

                      BITMAPINFO bmi;
                      memset(&bmi, 0, sizeof(BITMAPINFO));
                      bmi.bmiHeader.biSize = sizeof(BITMAPINFOHEADER);
                      bmi.bmiHeader.biWidth = lImageWidth;
                      bmi.bmiHeader.biHeight = lImageHeight;
                      bmi.bmiHeader.biPlanes = 1;
                      bmi.bmiHeader.biBitCount = wBitsPerPixel;
                      bmi.bmiHeader.biCompression = BI_RGB;
                      bmi.bmiHeader.biSizeImage = lBytesPerRow * lImageHeight;
                      //bmi.bmiHeader.biXPelsPerMeter = 0;
                      //bmi.bmiHeader.biYPelsPerMeter = 0;
                      //bmi.bmiHeader.biClrUsed = 0;
                      //bmi.bmiHeader.biClrImportant = 0;

                      HDC hdc = ::CreateCompatibleDC(0);

                      BYTE* pBitmapBits;
                      HBITMAP hBitmap = ::CreateDIBSection(hdc, &bmi, DIB_RGB_COLORS, (void**)&pBitmapBits, NULL, 0);

                      if (hBitmap)
                      {
                      memset(pBitmapBits, 0, bmi.bmiHeader.biSizeImage);

                      HGDIOBJ hOldBitmap = ::SelectObject(hdc, hBitmap);

                      Graphics DstGraphics(hdc);
                      DstGraphics.DrawImage(&TransparentSrcBitmap, 0, 0, TransparentSrcBitmap.GetWidth(), TransparentSrcBitmap.GetHeight());

                      //** Test - blt the memory dc to the screen to make sure alpha channel data carried over
                      BLENDFUNCTION bf;
                      bf.BlendOp = AC_SRC_OVER;
                      bf.BlendFlags = 0;
                      bf.SourceConstantAlpha = 0x7F; // Alpha multiplier applied overall - use 0xFF - 0x7F is a test
                      bf.AlphaFormat = AC_SRC_ALPHA;

                      HDC hClientDC = ::GetDC(*this);
                      ::AlphaBlend(hClientDC, 50, 50, TransparentSrcBitmap.GetWidth(), TransparentSrcBitmap.GetHeight(),
                      hdc, 0, 0, TransparentSrcBitmap.GetWidth(), TransparentSrcBitmap.GetHeight(), bf);
                      ::ReleaseDC(*this, hClientDC);
                      //** End Test

                      ::SelectObject(hdc, hOldBitmap); //<-- Don't do this when using with UpdateLayeredWindow()

                      ::DeleteObject(hBitmap); //<-- Don't do this when using with UpdateLayeredWindow()
                      }

                      ::DeleteDC(hdc); //<-- Don't do this when using with UpdateLayeredWindow()

                      Sorry about all the strange extra variables - I cut and paste from assorted worki

                      A 1 Reply Last reply
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                      • M Mark Salsbery

                        I "think" you may be able to use a 32-bit ARGB DIBsection - I put together this test just to make sure the alpha channel stuff was working. (My "hdc" would be your "dcMem" and you wouldn't want to delete it or un-select your alpha bitmap like I have if you pass it to UpdateLayeredWindow())

                        Image TransparentSrcBitmap(L"clockbg.bmp");

                        LONG lImageWidth = TransparentSrcBitmap.GetWidth();
                        LONG lImageHeight = TransparentSrcBitmap.GetHeight();
                        WORD wBitsPerPixel = 32;

                        //LONG lBytesPerRow = (((lImageWidth * (long)wBitsPerPixel + 31L) & (~31L)) / 8L);
                        LONG lBytesPerRow = lImageWidth * 4;

                        BITMAPINFO bmi;
                        memset(&bmi, 0, sizeof(BITMAPINFO));
                        bmi.bmiHeader.biSize = sizeof(BITMAPINFOHEADER);
                        bmi.bmiHeader.biWidth = lImageWidth;
                        bmi.bmiHeader.biHeight = lImageHeight;
                        bmi.bmiHeader.biPlanes = 1;
                        bmi.bmiHeader.biBitCount = wBitsPerPixel;
                        bmi.bmiHeader.biCompression = BI_RGB;
                        bmi.bmiHeader.biSizeImage = lBytesPerRow * lImageHeight;
                        //bmi.bmiHeader.biXPelsPerMeter = 0;
                        //bmi.bmiHeader.biYPelsPerMeter = 0;
                        //bmi.bmiHeader.biClrUsed = 0;
                        //bmi.bmiHeader.biClrImportant = 0;

                        HDC hdc = ::CreateCompatibleDC(0);

                        BYTE* pBitmapBits;
                        HBITMAP hBitmap = ::CreateDIBSection(hdc, &bmi, DIB_RGB_COLORS, (void**)&pBitmapBits, NULL, 0);

                        if (hBitmap)
                        {
                        memset(pBitmapBits, 0, bmi.bmiHeader.biSizeImage);

                        HGDIOBJ hOldBitmap = ::SelectObject(hdc, hBitmap);

                        Graphics DstGraphics(hdc);
                        DstGraphics.DrawImage(&TransparentSrcBitmap, 0, 0, TransparentSrcBitmap.GetWidth(), TransparentSrcBitmap.GetHeight());

                        //** Test - blt the memory dc to the screen to make sure alpha channel data carried over
                        BLENDFUNCTION bf;
                        bf.BlendOp = AC_SRC_OVER;
                        bf.BlendFlags = 0;
                        bf.SourceConstantAlpha = 0x7F; // Alpha multiplier applied overall - use 0xFF - 0x7F is a test
                        bf.AlphaFormat = AC_SRC_ALPHA;

                        HDC hClientDC = ::GetDC(*this);
                        ::AlphaBlend(hClientDC, 50, 50, TransparentSrcBitmap.GetWidth(), TransparentSrcBitmap.GetHeight(),
                        hdc, 0, 0, TransparentSrcBitmap.GetWidth(), TransparentSrcBitmap.GetHeight(), bf);
                        ::ReleaseDC(*this, hClientDC);
                        //** End Test

                        ::SelectObject(hdc, hOldBitmap); //<-- Don't do this when using with UpdateLayeredWindow()

                        ::DeleteObject(hBitmap); //<-- Don't do this when using with UpdateLayeredWindow()
                        }

                        ::DeleteDC(hdc); //<-- Don't do this when using with UpdateLayeredWindow()

                        Sorry about all the strange extra variables - I cut and paste from assorted worki

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                        Adno
                        wrote on last edited by
                        #12

                        thank you Mark very much for taking the time, it mean as lot me. but is not quite there is coming out pixalated, the alpha value is being replace by a black colour. program running image: http://img118.imageshack.us/img118/8953/testwindowhu9.png . . . Code: the main method. http://rafb.net/p/1Dfouz58.html thank you so much ....:-D

                        M 2 Replies Last reply
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                        • A Adno

                          thank you Mark very much for taking the time, it mean as lot me. but is not quite there is coming out pixalated, the alpha value is being replace by a black colour. program running image: http://img118.imageshack.us/img118/8953/testwindowhu9.png . . . Code: the main method. http://rafb.net/p/1Dfouz58.html thank you so much ....:-D

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                          Mark Salsbery
                          wrote on last edited by
                          #13

                          No problem! Can you show your latest code? Mark

                          "Posting a VB.NET question in the C++ forum will end in tears." Chris Maunder

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                          • A Adno

                            thank you Mark very much for taking the time, it mean as lot me. but is not quite there is coming out pixalated, the alpha value is being replace by a black colour. program running image: http://img118.imageshack.us/img118/8953/testwindowhu9.png . . . Code: the main method. http://rafb.net/p/1Dfouz58.html thank you so much ....:-D

                            M Offline
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                            Mark Salsbery
                            wrote on last edited by
                            #14

                            What's "image" and what's "program window" in your screenshot? Never mind I get it LOL I'd still like to see your updated code if you can :) Mark

                            "Posting a VB.NET question in the C++ forum will end in tears." Chris Maunder

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                            • M Mark Salsbery

                              What's "image" and what's "program window" in your screenshot? Never mind I get it LOL I'd still like to see your updated code if you can :) Mark

                              "Posting a VB.NET question in the C++ forum will end in tears." Chris Maunder

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                              Adno
                              wrote on last edited by
                              #15

                              Code: the main method. http://rafb.net/p/1Dfouz58.html ^i posted here

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                              • A Adno

                                Code: the main method. http://rafb.net/p/1Dfouz58.html ^i posted here

                                M Offline
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                                Mark Salsbery
                                wrote on last edited by
                                #16

                                Try replacing int t = UpdateLayeredWindow(hwnd, NULL, NULL, &sz, hdc, &ptSrc, NULL, &bf, ULW_COLORKEY ); with int t = UpdateLayeredWindow(hwnd, NULL, NULL, &sz, hdc, &ptSrc, NULL, &bf, ULW_ALPHA ); You probably want to set bf.SourceConstantAlpha = 0xFF; (instead of 0x7F) too. Mark

                                "Posting a VB.NET question in the C++ forum will end in tears." Chris Maunder

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                                • A Adno

                                  Code: the main method. http://rafb.net/p/1Dfouz58.html ^i posted here

                                  M Offline
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                                  Mark Salsbery
                                  wrote on last edited by
                                  #17

                                  And comment out these lines - they were there for testing only (leave in the BLENDFUNCTION since you're using that)... // comment these out HDC hClientDC = ::GetDC(hwnd); ::AlphaBlend(hClientDC, 50, 50, TransparentSrcBitmap.GetWidth(), TransparentSrcBitmap.GetHeight(), hdc, 0, 0, TransparentSrcBitmap.GetWidth(), TransparentSrcBitmap.GetHeight(), bf); ::ReleaseDC(hwnd, hClientDC);

                                  "Posting a VB.NET question in the C++ forum will end in tears." Chris Maunder

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                                  • M Mark Salsbery

                                    And comment out these lines - they were there for testing only (leave in the BLENDFUNCTION since you're using that)... // comment these out HDC hClientDC = ::GetDC(hwnd); ::AlphaBlend(hClientDC, 50, 50, TransparentSrcBitmap.GetWidth(), TransparentSrcBitmap.GetHeight(), hdc, 0, 0, TransparentSrcBitmap.GetWidth(), TransparentSrcBitmap.GetHeight(), bf); ::ReleaseDC(hwnd, hClientDC);

                                    "Posting a VB.NET question in the C++ forum will end in tears." Chris Maunder

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                                    Adno
                                    wrote on last edited by
                                    #18

                                    thanks a million one more thing since i've got you here. will i be able to draw on this window? i.e: Graphics graphics(GetDC(hwnd)); Bitmap bitmap(L"clockbg.bmp"); graphics.DrawImage(&bitmap, 100,100); i did a quick test it dont seem to be working. my goal would be to be as great as you one day lol

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                                    • A Adno

                                      thanks a million one more thing since i've got you here. will i be able to draw on this window? i.e: Graphics graphics(GetDC(hwnd)); Bitmap bitmap(L"clockbg.bmp"); graphics.DrawImage(&bitmap, 100,100); i did a quick test it dont seem to be working. my goal would be to be as great as you one day lol

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                                      Mark Salsbery
                                      wrote on last edited by
                                      #19

                                      Lamefif wrote:

                                      will i be able to draw on this window?

                                      Absolutely not! Just kidding. The DIBSection bitmap is already in a DC which is associated with a Graphics object (DstGraphics). That's where you should draw. Example...

                                      // redraw the image background
                                      DstGraphics.DrawImage(&TransparentSrcBitmap, 0, 0, TransparentSrcBitmap.GetWidth(), TransparentSrcBitmap.GetHeight());

                                      // draw some stuff on top of the background
                                      Bitmap bitmap(L"clockbg.bmp");
                                      DstGraphics.DrawImage(&bitmap, 100,100);

                                      You have full access to the bitmap that IS your window. You can write directly to the pixel bytes, use GDI+ to draw, use GDI to draw, or any combination of those :) You may need to call UpdateLayeredWindow() again to see changes (i think the hdcSrc param can be NULL for updates). Mark

                                      "Posting a VB.NET question in the C++ forum will end in tears." Chris Maunder

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                                      • M Mark Salsbery

                                        Lamefif wrote:

                                        will i be able to draw on this window?

                                        Absolutely not! Just kidding. The DIBSection bitmap is already in a DC which is associated with a Graphics object (DstGraphics). That's where you should draw. Example...

                                        // redraw the image background
                                        DstGraphics.DrawImage(&TransparentSrcBitmap, 0, 0, TransparentSrcBitmap.GetWidth(), TransparentSrcBitmap.GetHeight());

                                        // draw some stuff on top of the background
                                        Bitmap bitmap(L"clockbg.bmp");
                                        DstGraphics.DrawImage(&bitmap, 100,100);

                                        You have full access to the bitmap that IS your window. You can write directly to the pixel bytes, use GDI+ to draw, use GDI to draw, or any combination of those :) You may need to call UpdateLayeredWindow() again to see changes (i think the hdcSrc param can be NULL for updates). Mark

                                        "Posting a VB.NET question in the C++ forum will end in tears." Chris Maunder

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                                        Adno
                                        wrote on last edited by
                                        #20

                                        Cheers Mark man i new i could do it. :->

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                                        • A Adno

                                          Cheers Mark man i new i could do it. :->

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                                          Mark Salsbery
                                          wrote on last edited by
                                          #21

                                          :beer:

                                          "Posting a VB.NET question in the C++ forum will end in tears." Chris Maunder

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