problem related to linkbuuton

[biswa47]

hi frndz... i have a very small problem .. plz help me out.. last time i aske did qns but no body answered me.. hope dis time get the soln. i have link button and panel. i want to display the panel while click on the link button first time and while clicking on the same link button another time dat panel should be disable. i am only able enable the panel on the first click on the link button. but how to disble it on 2nd click. like wise if i clicked on the 3rd time the panel will be enable and if i clicked it 4 4th time d panel will again disable.. plz help me out.i am developing my project n c#.net

[Sun Rays]

Hi, try this, on link button click event check If panel.visible == true then make it false. Else make it true. :) if(Panel1.Visible == true) Panel1.Visible = false; else Panel1.Visible = true;

Thanks, Sun Rays To get something you must have to try once. My Articles

modified on Monday, December 17, 2007 12:36:25 AM

[Parwej Ahamad]

Hi you do this in two way : (1) Server Side : Link button click Event if( Session["pnlFlag"] != null ) { bool flg=(bool)Session["pnlFlag"]; if (Flg == true ) Session["pnlFlag"]=false; else Session["pnlFlag"]=true; } else Session["pnlFlag"]=true; Then on page load if( Session["pnlFlag"] != null ) yourPanle.visible=(bool)Session["pnlFlag"]; else //set the default visible of panel what you want OR (2) You can handle it client side mean java script. if you want then let me know

/***********************/ * Parwej Ahamad * * g.parwez@gmail.com * /***********************/

[Sun Rays]

Hi,

Parwej Ahamad wrote:

Link button click Event if( Session["pnlFlag"] != null ) { bool flg=(bool)Session["pnlFlag"]; if (Flg == true ) Session["pnlFlag"]=false; else Session["pnlFlag"]=true; } else Session["pnlFlag"]=true; Then on page load if( Session["pnlFlag"] != null ) yourPanle.visible=(bool)Session["pnlFlag"]; else //set the default visible of panel what you want OR

Why to use Session ? No need to use it.

Thanks, Sun Rays To get something you must have to try once. My Articles

[N a v a n e e t h]

Use ViewState and keep the clicked status there. Check this status on link button click and show/hide it as well.

if(ViewState["PanelVisible"] != null && (bool)ViewState["PanelVisible"] == true)
{
//hide you panel here
ViewState["PanelVisible"] = false;
}
else
{
//show your panel here
ViewState["PanelVisible"] = true;
}

use this on your link buttons onclick event.

All C# applications should call Application.Quit(); in the beginning to avoid any .NET problems.- Unclyclopedia My Website | Ask smart questions

[John ph]

How about using a DIV tag and writting a javascript to toggle the DIV on the click of Link button?

function ToggleDIV(divid) {
if (document.getElementById(divid).style.display == 'none')
document.getElementById(divid).style.display="inline";
else
document.getElementById(divid).style.display="none";
}

- Regards -
   JON

---

Life is not measured by the amount of breaths we take, but by the moments that take our breath away.

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[Sun Rays]

N a v a n e e t h wrote:

if(ViewState["PanelVisible"] != null && (bool)ViewState["PanelVisible"] == true){ //hide you panel here ViewState["PanelVisible"] = false;}else{ //show your panel here ViewState["PanelVisible"] = true;}

Hi, Why to use viewstate ?? We can do it in simple way. Without using ViewState["PanelVisible"] or Session.

Thanks, Sun Rays To get something you must have to try once. My Articles

[N a v a n e e t h]

It's the two ways for the problem. Your method also will work, which does what I wrote, internally.

All C# applications should call Application.Quit(); in the beginning to avoid any .NET problems.- Unclyclopedia My Website | Ask smart questions

[Sun Rays]

Hi, thats true. But what my question is. If we can solve it without using viewstate then why to use it ? Bcoz smart coding it this. :cool: Anyways good to hear that my method can work. :laugh:

Thanks, Sun Rays To get something you must have to try once. My Articles