constructor failed??? [modified]
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Hello all. I have this code with something error occured: //------------------------------------------ #include "iostream" using namespace std; class aa { public: aa() { aa(5); } aa(int t) { x = t; } void print() { cout << x << endl; } private: int x; }; int main() { aa t; t.print();//this can't output "5", why? return 0; } ///--------------------------- As is descriped above, thanks in advance!
If we dream, every thing is possible!
modified on Thursday, June 5, 2008 3:31 AM
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Hello all. I have this code with something error occured: //------------------------------------------ #include "iostream" using namespace std; class aa { public: aa() { aa(5); } aa(int t) { x = t; } void print() { cout << x << endl; } private: int x; }; int main() { aa t; t.print();//this can't output "5", why? return 0; } ///--------------------------- As is descriped above, thanks in advance!
If we dream, every thing is possible!
modified on Thursday, June 5, 2008 3:31 AM
Could you please elaborate the problem ? What's wrong ? And please use the "code block" option when posting code (all of that is clearly explained in the posting guidelines).
Cédric Moonen Software developer
Charting control [v1.4] -
Hello all. I have this code with something error occured: //------------------------------------------ #include "iostream" using namespace std; class aa { public: aa() { aa(5); } aa(int t) { x = t; } void print() { cout << x << endl; } private: int x; }; int main() { aa t; t.print();//this can't output "5", why? return 0; } ///--------------------------- As is descriped above, thanks in advance!
If we dream, every thing is possible!
modified on Thursday, June 5, 2008 3:31 AM
and WHAT IS the error occuring dude ?! :doh: BTW, i see a problem in your
coutstatements.coutcannot use the>>operator. it uses<<operator only, so change your code into this :void print() {
cout << x << endl;
}and everywhere you're doing such a mistake...
[VisualCalc][Binary Guide][CommDialogs] | [Forums Guidelines]
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Hello all. I have this code with something error occured: //------------------------------------------ #include "iostream" using namespace std; class aa { public: aa() { aa(5); } aa(int t) { x = t; } void print() { cout << x << endl; } private: int x; }; int main() { aa t; t.print();//this can't output "5", why? return 0; } ///--------------------------- As is descriped above, thanks in advance!
If we dream, every thing is possible!
modified on Thursday, June 5, 2008 3:31 AM
You made a mistake in the default constructor. Can you spot it? BTW: The correct method is
class aa
{
public:
aa():x(5)
{
}
//...
};If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke -
Could you please elaborate the problem ? What's wrong ? And please use the "code block" option when posting code (all of that is clearly explained in the posting guidelines).
Cédric Moonen Software developer
Charting control [v1.4](excluding
<<and>>operators usage!) He creates a temporary object (callingaa(5)) inside the default constructor, probably he wanted to initializexwith5instead. :)If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke -
and WHAT IS the error occuring dude ?! :doh: BTW, i see a problem in your
coutstatements.coutcannot use the>>operator. it uses<<operator only, so change your code into this :void print() {
cout << x << endl;
}and everywhere you're doing such a mistake...
[VisualCalc][Binary Guide][CommDialogs] | [Forums Guidelines]
He creates a temporary object (calling
aa(5)) inside the default constructor (leaving garbage insidex), probably he wanted to initializexwith5instead. :)If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke -
He creates a temporary object (calling
aa(5)) inside the default constructor (leaving garbage insidex), probably he wanted to initializexwith5instead. :)If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarkethanks dear. but i saw your answer, so no need to flood the thread ;P :cool:
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Hello all. I have this code with something error occured: //------------------------------------------ #include "iostream" using namespace std; class aa { public: aa() { aa(5); } aa(int t) { x = t; } void print() { cout << x << endl; } private: int x; }; int main() { aa t; t.print();//this can't output "5", why? return 0; } ///--------------------------- As is descriped above, thanks in advance!
If we dream, every thing is possible!
modified on Thursday, June 5, 2008 3:31 AM
Is This program working ???
cout>>x>>endl;
cin<<ch;try using debuging than you find that why x is not giving right output :) #include "stdafx.h" #include <iostream> using namespace std;
class aa
{public: aa(int t = 5) { x = t; } void print() { cout<<x <<endl; } private: int x;};
int main(int argc, char* argv[])
{
aa t;
t.print();
cout<<"---------------------"<<endl;aa t1(4); t1.print(); char ch; cin>>ch; return 0;}
Yes U Can ...If U Can ,Dream it , U can do it ...ICAN
modified on Thursday, June 5, 2008 3:41 AM
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thanks dear. but i saw your answer, so no need to flood the thread ;P :cool:
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~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~~~~~~~~~~~ ;P ~~~~~~~~~~~~~~~~~ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
toxcct wrote:
so no need to flood the thread
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~~~~~~~~~~~ ;P ~~~~~~~~~~~~~~~~~ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke -
You made a mistake in the default constructor. Can you spot it? BTW: The correct method is
class aa
{
public:
aa():x(5)
{
}
//...
};If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke -
Is This program working ???
cout>>x>>endl;
cin<<ch;try using debuging than you find that why x is not giving right output :) #include "stdafx.h" #include <iostream> using namespace std;
class aa
{public: aa(int t = 5) { x = t; } void print() { cout<<x <<endl; } private: int x;};
int main(int argc, char* argv[])
{
aa t;
t.print();
cout<<"---------------------"<<endl;aa t1(4); t1.print(); char ch; cin>>ch; return 0;}
Yes U Can ...If U Can ,Dream it , U can do it ...ICAN
modified on Thursday, June 5, 2008 3:41 AM
Shilpi Boosar wrote:
cout>>x>>endl;cin<<ch;
you're not serious, are you ? :~ X| when you don't know what you're talking about, please avoid posting crap, that will avoid the question poster to be confused at last.
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Thank you Pallini.I got it... But i found this code can't work. class aa { public: aa():x(5) { }//... }; it said x(5) is not a base class. Thanks once again! :)
If we dream, every thing is possible!
it's because in this class, you don't define a x member...
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Is This program working ???
cout>>x>>endl;
cin<<ch;try using debuging than you find that why x is not giving right output :) #include "stdafx.h" #include <iostream> using namespace std;
class aa
{public: aa(int t = 5) { x = t; } void print() { cout<<x <<endl; } private: int x;};
int main(int argc, char* argv[])
{
aa t;
t.print();
cout<<"---------------------"<<endl;aa t1(4); t1.print(); char ch; cin>>ch; return 0;}
Yes U Can ...If U Can ,Dream it , U can do it ...ICAN
modified on Thursday, June 5, 2008 3:41 AM
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Shilpi Boosar wrote:
cout>>x>>endl;cin<<ch;
you're not serious, are you ? :~ X| when you don't know what you're talking about, please avoid posting crap, that will avoid the question poster to be confused at last.
[VisualCalc][Binary Guide][CommDialogs] | [Forums Guidelines]
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Thank you Pallini.I got it... But i found this code can't work. class aa { public: aa():x(5) { }//... }; it said x(5) is not a base class. Thanks once again! :)
If we dream, every thing is possible!
In my sample
//...
was the concise notation for
aa(int t)
{
x = t;
}
void print()
{
cout << x << endl;
}
private:
int x;
};:)
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke -
Shilpi Boosar wrote:
cout>>x>>endl;cin<<ch;
you're not serious, are you ? :~ X| when you don't know what you're talking about, please avoid posting crap, that will avoid the question poster to be confused at last.
[VisualCalc][Binary Guide][CommDialogs] | [Forums Guidelines]
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Thans Shilpi. I'm so sorry.It's my fault. I have edited my post... :)
If we dream, every thing is possible!
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I think now you got the answer why i write that code. :)
Yes U Can ...If U Can ,Dream it , U can do it ...ICAN
nope. i still don't understand why you used the wrong operators... cout use <<, not >>
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I think now you got the answer why i write that code. :)
Yes U Can ...If U Can ,Dream it , U can do it ...ICAN
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nope. i still don't understand why you used the wrong operators... cout use <<, not >>
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