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  3. Friday Programming Quiz (It's back) [modified]

Friday Programming Quiz (It's back) [modified]

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  • E Ennis Ray Lynch Jr

    Simple, how about a hard one? Given a tic-tac-toe board where the board can be represented by a one-dimensional array of chars with 'X' being x, 'Y' being y, and all others being empty such that the top left most square is the 0 index, followed by the middle square on the top row as the 1 index ....

    0 | 1 | 2
    _____________
    3 | 4 | 5
    _____________
    6 | 7 | 8

    Write an algorithm to display the number of winning combination available for each X and O based on the game state when passed an array in under n^2.

    Need a C# Consultant? I'm available.
    Happiness in intelligent people is the rarest thing I know. -- Ernest Hemingway

    R Offline
    R Offline
    Rama Krishna Vavilala
    wrote on last edited by
    #12

    Ennis Ray Lynch, Jr. wrote:

    Simple,

    Friday is meant for simple quizzes:)

    Proud to be a CPHog user

    1 Reply Last reply
    0
    • E Ennis Ray Lynch Jr

      Simple, how about a hard one? Given a tic-tac-toe board where the board can be represented by a one-dimensional array of chars with 'X' being x, 'Y' being y, and all others being empty such that the top left most square is the 0 index, followed by the middle square on the top row as the 1 index ....

      0 | 1 | 2
      _____________
      3 | 4 | 5
      _____________
      6 | 7 | 8

      Write an algorithm to display the number of winning combination available for each X and O based on the game state when passed an array in under n^2.

      Need a C# Consultant? I'm available.
      Happiness in intelligent people is the rarest thing I know. -- Ernest Hemingway

      L Offline
      L Offline
      leppie
      wrote on last edited by
      #13

      Ha! I think I did this in first year uni :) Wow, I did some scary (but still cool) code back then, in C!

      Ennis Ray Lynch, Jr. wrote:

      under n^2.

      What is n suppose to be?

      xacc.ide - now with TabsToSpaces support
      IronScheme - 1.0 alpha 4a out now (29 May 2008)

      E 1 Reply Last reply
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      • L leppie

        Ha! I think I did this in first year uni :) Wow, I did some scary (but still cool) code back then, in C!

        Ennis Ray Lynch, Jr. wrote:

        under n^2.

        What is n suppose to be?

        xacc.ide - now with TabsToSpaces support
        IronScheme - 1.0 alpha 4a out now (29 May 2008)

        E Offline
        E Offline
        Ennis Ray Lynch Jr
        wrote on last edited by
        #14

        That is the efficiency of the algorithm, as in O(n^2) or less. It is a large topic that I cannot explain here.

        Need a C# Consultant? I'm available.
        Happiness in intelligent people is the rarest thing I know. -- Ernest Hemingway

        L 1 Reply Last reply
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        • R Rama Krishna Vavilala

          Back on Popular demand You are given two lists. List 1 contains certain strings in a particular order. List 2 contains all the allowed values in List 1. List 1, however, can contain some elements not in List 2. The objective is to generate a List 3 which will have elements from List 1 in exactly the same order specified in List 1 followed by elements not in List 1 but present in List 2. Any elements not in List 2 should not be included. Example: List 1:

          A,B,C,D

          List 2:

          B,A,X,S,L,D

          Output:

          A,B,D,X,S,L


          Last modified: 10mins after originally posted --

          Proud to be a CPHog user

          S Offline
          S Offline
          Shog9 0
          wrote on last edited by
          #15

          var list1 = ['A','B','C','D'];
          var list2 = ['B','A','X','S','L','D'];

          var result = list1.filter(function(i) list2.indexOf(i) >= 0)
          .concat( list2.filter(function(i) list1.indexOf(i) < 0 ) );

          Javascript 1.8 (tested on Firefox 3.0.1)

          You must be careful in the forest Broken glass and rusty nails If you're to bring back something for us I have bullets for sale...

          N 1 Reply Last reply
          0
          • E Ennis Ray Lynch Jr

            That is the efficiency of the algorithm, as in O(n^2) or less. It is a large topic that I cannot explain here.

            Need a C# Consultant? I'm available.
            Happiness in intelligent people is the rarest thing I know. -- Ernest Hemingway

            L Offline
            L Offline
            leppie
            wrote on last edited by
            #16

            Ennis Ray Lynch, Jr. wrote:

            That is the efficiency of the algorithm, as in O(n^2) or less. It is a large topic that I cannot explain here.

            Jeez. I hope you being sarcastic... :| What is n, the size of the input? Size of the board?

            xacc.ide - now with TabsToSpaces support
            IronScheme - 1.0 alpha 4a out now (29 May 2008)

            E P 2 Replies Last reply
            0
            • L leppie

              Ennis Ray Lynch, Jr. wrote:

              That is the efficiency of the algorithm, as in O(n^2) or less. It is a large topic that I cannot explain here.

              Jeez. I hope you being sarcastic... :| What is n, the size of the input? Size of the board?

              xacc.ide - now with TabsToSpaces support
              IronScheme - 1.0 alpha 4a out now (29 May 2008)

              E Offline
              E Offline
              Ennis Ray Lynch Jr
              wrote on last edited by
              #17

              your kidding right?

              Need a C# Consultant? I'm available.
              Happiness in intelligent people is the rarest thing I know. -- Ernest Hemingway

              L 1 Reply Last reply
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              • L leppie

                Ennis Ray Lynch, Jr. wrote:

                That is the efficiency of the algorithm, as in O(n^2) or less. It is a large topic that I cannot explain here.

                Jeez. I hope you being sarcastic... :| What is n, the size of the input? Size of the board?

                xacc.ide - now with TabsToSpaces support
                IronScheme - 1.0 alpha 4a out now (29 May 2008)

                P Offline
                P Offline
                Paul Conrad
                wrote on last edited by
                #18

                :eek:

                "The clue train passed his station without stopping." - John Simmons / outlaw programmer "Real programmers just throw a bunch of 1s and 0s at the computer to see what sticks" - Pete O'Hanlon

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                • J Judah Gabriel Himango

                  Sweet! I love these! Is it cheating to use LINQ?

                  var list1Allowed = from element in list1
                                     where list2.Contains(element)
                                     select element;

                  var list2ElementsNotInList1 = from element in list2
                                                where !list1.Contains(element)
                                               select element;

                  var result = list1Allowed.Concat(list2ElementsNotInList1);

                  Alternately, since we're not doing any fabulous let clauses, we could just call the extension methods directly for a more terse syntax:

                  var list1Allowed = list1.Where(el => list2.Contains(el));
                  var list2ElementsNotInList1 = list2.Where(el => !list1.Contains(el));
                  var result = list1Allowed.Concat(list2ElementsNotInList1);

                  Nifty! I :heart: LINQ. :)

                  Life, family, faith: Give me a visit. From my latest post: "The themes and truths of the Jewish holidays follow God's complete plan for this world. They are the root from which Christianity sprang and the historical reasons the church had for leaving them behind were unsound." Judah Himango

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                  Nish Nishant
                  wrote on last edited by
                  #19

                  Judah Himango wrote:

                  var list2ElementsNotInList1 = list2.Where(el => !list1.Contains(el));

                  Hey Judah, I would probably replace that with :

                  var list2ElementsNotInList1 = list2.Except(list1);

                  Regards, Nish


                  Nish’s thoughts on MFC, C++/CLI and .NET (my blog)
                  My latest book : C++/CLI in Action / Amazon.com link

                  1 Reply Last reply
                  0
                  • J Judah Gabriel Himango

                    Sweet! I love these! Is it cheating to use LINQ?

                    var list1Allowed = from element in list1
                                       where list2.Contains(element)
                                       select element;

                    var list2ElementsNotInList1 = from element in list2
                                                  where !list1.Contains(element)
                                                 select element;

                    var result = list1Allowed.Concat(list2ElementsNotInList1);

                    Alternately, since we're not doing any fabulous let clauses, we could just call the extension methods directly for a more terse syntax:

                    var list1Allowed = list1.Where(el => list2.Contains(el));
                    var list2ElementsNotInList1 = list2.Where(el => !list1.Contains(el));
                    var result = list1Allowed.Concat(list2ElementsNotInList1);

                    Nifty! I :heart: LINQ. :)

                    Life, family, faith: Give me a visit. From my latest post: "The themes and truths of the Jewish holidays follow God's complete plan for this world. They are the root from which Christianity sprang and the historical reasons the church had for leaving them behind were unsound." Judah Himango

                    N Offline
                    N Offline
                    Nish Nishant
                    wrote on last edited by
                    #20

                    In fact this would be even more straightforward :

                    var result = list1.Intersect(list2).Concat(list2.Except(list1));

                    Regards, Nish


                    Nish’s thoughts on MFC, C++/CLI and .NET (my blog)
                    My latest book : C++/CLI in Action / Amazon.com link

                    S J 2 Replies Last reply
                    0
                    • N Nish Nishant

                      In fact this would be even more straightforward :

                      var result = list1.Intersect(list2).Concat(list2.Except(list1));

                      Regards, Nish


                      Nish’s thoughts on MFC, C++/CLI and .NET (my blog)
                      My latest book : C++/CLI in Action / Amazon.com link

                      S Offline
                      S Offline
                      Shog9 0
                      wrote on last edited by
                      #21

                      :cool:

                      You must be careful in the forest Broken glass and rusty nails If you're to bring back something for us I have bullets for sale...

                      N 1 Reply Last reply
                      0
                      • S Shog9 0

                        var list1 = ['A','B','C','D'];
                        var list2 = ['B','A','X','S','L','D'];

                        var result = list1.filter(function(i) list2.indexOf(i) >= 0)
                        .concat( list2.filter(function(i) list1.indexOf(i) < 0 ) );

                        Javascript 1.8 (tested on Firefox 3.0.1)

                        You must be careful in the forest Broken glass and rusty nails If you're to bring back something for us I have bullets for sale...

                        N Offline
                        N Offline
                        Nish Nishant
                        wrote on last edited by
                        #22

                        Ah you have a one-liner too I see - in fact the same algorithm as the one in mine.

                        Regards, Nish


                        Nish’s thoughts on MFC, C++/CLI and .NET (my blog)
                        My latest book : C++/CLI in Action / Amazon.com link

                        S 1 Reply Last reply
                        0
                        • S Shog9 0

                          :cool:

                          You must be careful in the forest Broken glass and rusty nails If you're to bring back something for us I have bullets for sale...

                          N Offline
                          N Offline
                          Nish Nishant
                          wrote on last edited by
                          #23

                          Thank you :-)

                          Regards, Nish


                          Nish’s thoughts on MFC, C++/CLI and .NET (my blog)
                          My latest book : C++/CLI in Action / Amazon.com link

                          1 Reply Last reply
                          0
                          • N Nish Nishant

                            Ah you have a one-liner too I see - in fact the same algorithm as the one in mine.

                            Regards, Nish


                            Nish’s thoughts on MFC, C++/CLI and .NET (my blog)
                            My latest book : C++/CLI in Action / Amazon.com link

                            S Offline
                            S Offline
                            Shog9 0
                            wrote on last edited by
                            #24

                            Yeah, same algorithm, but more verbose so i split it into two lines.

                            You must be careful in the forest Broken glass and rusty nails If you're to bring back something for us I have bullets for sale...

                            1 Reply Last reply
                            0
                            • R Rama Krishna Vavilala

                              Back on Popular demand You are given two lists. List 1 contains certain strings in a particular order. List 2 contains all the allowed values in List 1. List 1, however, can contain some elements not in List 2. The objective is to generate a List 3 which will have elements from List 1 in exactly the same order specified in List 1 followed by elements not in List 1 but present in List 2. Any elements not in List 2 should not be included. Example: List 1:

                              A,B,C,D

                              List 2:

                              B,A,X,S,L,D

                              Output:

                              A,B,D,X,S,L


                              Last modified: 10mins after originally posted --

                              Proud to be a CPHog user

                              J Offline
                              J Offline
                              Joe Woodbury
                              wrote on last edited by
                              #25

                              This is Friday, so my steps were: 1) Pick up phone 2) Call junior programmer Hank 3) Tell him this is due ASAP 4) Go home

                              Anyone who thinks he has a better idea of what's good for people than people do is a swine. - P.J. O'Rourke

                              G 1 Reply Last reply
                              0
                              • R Rama Krishna Vavilala

                                Back on Popular demand You are given two lists. List 1 contains certain strings in a particular order. List 2 contains all the allowed values in List 1. List 1, however, can contain some elements not in List 2. The objective is to generate a List 3 which will have elements from List 1 in exactly the same order specified in List 1 followed by elements not in List 1 but present in List 2. Any elements not in List 2 should not be included. Example: List 1:

                                A,B,C,D

                                List 2:

                                B,A,X,S,L,D

                                Output:

                                A,B,D,X,S,L


                                Last modified: 10mins after originally posted --

                                Proud to be a CPHog user

                                P Offline
                                P Offline
                                PIEBALDconsult
                                wrote on last edited by
                                #26

                                I think my Set[^] class/struct was my first article. (It wasn't, but I wrote the class before the others.)

                                PIEBALD.Types.Set<char> a = new PIEBALD.Types.Set<char> ( 'A' , 'B' , 'C' , 'D' ) ;
                                PIEBALD.Types.Set<char> b = new PIEBALD.Types.Set<char> ( 'B' , 'A' , 'X' , 'S' , 'L' , 'D' ) ;

                                foreach ( char c in ( a & b ) + b ) ...

                                A HashSet didn't preserve the order, and isn't as expressive. X|

                                System.Collections.Generic.HashSet<char> c = new System.Collections.Generic.HashSet<char> ( a ) ;
                                System.Collections.Generic.HashSet<char> d = new System.Collections.Generic.HashSet<char> ( b ) ;

                                System.Collections.Generic.HashSet<char> f = c ;
                                f.IntersectWith ( d ) ;
                                f.UnionWith ( d ) ;

                                foreach ( char e in f )

                                I've been considering reworking Set to use a HashSet rather than a Dictionary (originally it used a Hashtable).

                                modified on Friday, August 1, 2008 9:08 PM

                                R 1 Reply Last reply
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                                • P PIEBALDconsult

                                  I think my Set[^] class/struct was my first article. (It wasn't, but I wrote the class before the others.)

                                  PIEBALD.Types.Set<char> a = new PIEBALD.Types.Set<char> ( 'A' , 'B' , 'C' , 'D' ) ;
                                  PIEBALD.Types.Set<char> b = new PIEBALD.Types.Set<char> ( 'B' , 'A' , 'X' , 'S' , 'L' , 'D' ) ;

                                  foreach ( char c in ( a & b ) + b ) ...

                                  A HashSet didn't preserve the order, and isn't as expressive. X|

                                  System.Collections.Generic.HashSet<char> c = new System.Collections.Generic.HashSet<char> ( a ) ;
                                  System.Collections.Generic.HashSet<char> d = new System.Collections.Generic.HashSet<char> ( b ) ;

                                  System.Collections.Generic.HashSet<char> f = c ;
                                  f.IntersectWith ( d ) ;
                                  f.UnionWith ( d ) ;

                                  foreach ( char e in f )

                                  I've been considering reworking Set to use a HashSet rather than a Dictionary (originally it used a Hashtable).

                                  modified on Friday, August 1, 2008 9:08 PM

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                                  Rama Krishna Vavilala
                                  wrote on last edited by
                                  #27

                                  PIEBALDconsult wrote:

                                  ( a & b ) + b

                                  It took me a while to understand that code:)

                                  Proud to be a CPHog user

                                  P 1 Reply Last reply
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                                  • R Rama Krishna Vavilala

                                    PIEBALDconsult wrote:

                                    ( a & b ) + b

                                    It took me a while to understand that code:)

                                    Proud to be a CPHog user

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                                    P Offline
                                    PIEBALDconsult
                                    wrote on last edited by
                                    #28

                                    I had to access my article to figure out what operator I used for intersection. Then found that the order of operations is wrong. :( Ha! a & b | b works as required. I've been looking forward to a good FPQ for ages, I keep trying to think of my own.

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                                    • E Ennis Ray Lynch Jr

                                      your kidding right?

                                      Need a C# Consultant? I'm available.
                                      Happiness in intelligent people is the rarest thing I know. -- Ernest Hemingway

                                      L Offline
                                      L Offline
                                      leppie
                                      wrote on last edited by
                                      #29

                                      Ennis Ray Lynch, Jr. wrote:

                                      your kidding right?

                                      Sorry, I went to sleep :) No, I wasn't kidding. I meant what is n in relation to the problem. Does it refer to the 'variable' amount of 'squares'? Does it refer to the 'variable' amount of winning combinations? Does it refer to the 'width' of the board? Is it the number of sheep I count before I pass out? From your problem statement, all of the above are constant, (9, 8, 3, 42). You get what I am saying? Remember O(3000000000n) is still O(n).

                                      xacc.ide - now with TabsToSpaces support
                                      IronScheme - 1.0 alpha 4a out now (29 May 2008)

                                      E 1 Reply Last reply
                                      0
                                      • R Rama Krishna Vavilala

                                        Back on Popular demand You are given two lists. List 1 contains certain strings in a particular order. List 2 contains all the allowed values in List 1. List 1, however, can contain some elements not in List 2. The objective is to generate a List 3 which will have elements from List 1 in exactly the same order specified in List 1 followed by elements not in List 1 but present in List 2. Any elements not in List 2 should not be included. Example: List 1:

                                        A,B,C,D

                                        List 2:

                                        B,A,X,S,L,D

                                        Output:

                                        A,B,D,X,S,L


                                        Last modified: 10mins after originally posted --

                                        Proud to be a CPHog user

                                        S Offline
                                        S Offline
                                        Stuart Dootson
                                        wrote on last edited by
                                        #30

                                        In Haskell:

                                        import Data.List
                                        
                                        munge a b = (a `intersect` b) ++ (b \\ a)
                                        

                                        a `intersect` b retrieves the stable intersection of a with b. b \\ a takes all elements in a out of b. Job's a good'un! [edit]Should have read the Data.List documentation *before* answering rather than after! The code should be

                                        munge a b = a `intersect` b ++ filter (not.(`elem` a)) b
                                        

                                        \\ only deletes the first instances of elements of b that are also in a, i.e. ("ABA"\\"A" == "BA" which is not what's wanted here) [/edit]

                                        modified on Saturday, August 2, 2008 7:13 AM

                                        1 Reply Last reply
                                        0
                                        • R Rama Krishna Vavilala

                                          Back on Popular demand You are given two lists. List 1 contains certain strings in a particular order. List 2 contains all the allowed values in List 1. List 1, however, can contain some elements not in List 2. The objective is to generate a List 3 which will have elements from List 1 in exactly the same order specified in List 1 followed by elements not in List 1 but present in List 2. Any elements not in List 2 should not be included. Example: List 1:

                                          A,B,C,D

                                          List 2:

                                          B,A,X,S,L,D

                                          Output:

                                          A,B,D,X,S,L


                                          Last modified: 10mins after originally posted --

                                          Proud to be a CPHog user

                                          G Offline
                                          G Offline
                                          Gary R Wheeler
                                          wrote on last edited by
                                          #31

                                          CTypedPtrList<CPtrList,_TCHAR *> list1,list2,list3;
                                           
                                          list1.AddTail(_T("A"));
                                          list1.AddTail(_T("B"));
                                          list1.AddTail(_T("C"));
                                          list1.AddTail(_T("D"));
                                           
                                          list2.AddTail(_T("B"));
                                          list2.AddTail(_T("A"));
                                          list2.AddTail(_T("X"));
                                          list2.AddTail(_T("S"));
                                          list2.AddTail(_T("L"));
                                          list2.AddTail(_T("D"));
                                           
                                          POSITION p1 = list1.GetHeadPosition();
                                           
                                          while (p1 != NULL) {
                                           
                                          _TCHAR *s1 = list1.GetNext(p1);
                                           
                                          POSITION p2 = list2.GetHeadPosition();
                                           
                                          while (p2 != NULL) {
                                           
                                          POSITION r2 = p2;
                                           
                                          _TCHAR *s2 = list2.GetNext(p2);
                                           
                                          if (_tcsicmp(s1,s2) == 0) {
                                          list3.AddTail(s1);
                                          list2.RemoveAt(r2);
                                          }
                                           
                                          }
                                           
                                          }
                                           
                                          list3.AddTail(&list2);

                                          BTW: I did compile and run this; it works. While it does alter list2 in the process, a version that doesn't wouldn't be difficult.

                                          Software Zen: delete this;
                                          Fold With Us![^]

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