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diamond problem and virtual inheritance

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  • G George_George

    Hello everyone, Just want to confirm a basic concept when reading a couple of documents about diamond problem and virtual inheritance. 1. Diamond problem covers both ambiguity methods and data member variable? 2. Virtual inheritance only solves ambiguity data member issue (making data member one copy)? 3. So, it is not correct to say virtual inheritance solves diamond problem 100% since ambiguity member methods is not covered and solved? thanks in advance, George

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    tony_Udz
    wrote on last edited by
    #2

    Hi, Try the following code it might help you: ========================================================================== #include "iostream.h" #include "stdio.h" class A { public: int m_nAInt; A(int n = 1):m_nAInt(n) { cout << "Class A Constructor called" << endl; } Display() { cout << "A::Display()" << endl; } }; class B: public virtual A { public: B() { cout << "Class B Constructor called" << endl; } }; class C: public virtual A { public: C() { cout << "Class C Constructor called" << endl; } }; class D: public B, C { public: D() { cout << "Class D Constructor called" << endl; } }; int main(int argc, char* argv[]) { D dObj; dObj.Display(); return 0; } ==========================================================================

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    • T tony_Udz

      Hi, Try the following code it might help you: ========================================================================== #include "iostream.h" #include "stdio.h" class A { public: int m_nAInt; A(int n = 1):m_nAInt(n) { cout << "Class A Constructor called" << endl; } Display() { cout << "A::Display()" << endl; } }; class B: public virtual A { public: B() { cout << "Class B Constructor called" << endl; } }; class C: public virtual A { public: C() { cout << "Class C Constructor called" << endl; } }; class D: public B, C { public: D() { cout << "Class D Constructor called" << endl; } }; int main(int argc, char* argv[]) { D dObj; dObj.Display(); return 0; } ==========================================================================

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      George_George
      wrote on last edited by
      #3

      What is the issue, tony_udz? Could you clarify please? You code runs ok without any compile/build warning/errors. Here is the output.

      Class A Constructor called
      Class B Constructor called
      Class C Constructor called
      Class D Constructor called
      A::Display()

      regards, George

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      • G George_George

        What is the issue, tony_udz? Could you clarify please? You code runs ok without any compile/build warning/errors. Here is the output.

        Class A Constructor called
        Class B Constructor called
        Class C Constructor called
        Class D Constructor called
        A::Display()

        regards, George

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        SandipG
        wrote on last edited by
        #4

        Hi George,

        George_George wrote:

        You code runs ok without any compile/build warning/errors.

        That means virtual resolved methods as well as data member ambiguity so that does not clear your doubt. I hope it helps..

        Regards, Sandip.

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        • S SandipG

          Hi George,

          George_George wrote:

          You code runs ok without any compile/build warning/errors.

          That means virtual resolved methods as well as data member ambiguity so that does not clear your doubt. I hope it helps..

          Regards, Sandip.

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          George_George
          wrote on last edited by
          #5

          Thanks, Sandip! So, you mean virtual inheritance makes one copy of both methods and data? regards, George

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          • G George_George

            Thanks, Sandip! So, you mean virtual inheritance makes one copy of both methods and data? regards, George

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            SandipG
            wrote on last edited by
            #6

            George_George wrote:

            So, you mean virtual inheritance makes one copy of both methods and data?

            Yes unless you do not override the common method in both derived classes. In above case if you override Display method in both derived classes you will get ambiguity error.

            Regards, Sandip.

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            • S SandipG

              George_George wrote:

              So, you mean virtual inheritance makes one copy of both methods and data?

              Yes unless you do not override the common method in both derived classes. In above case if you override Display method in both derived classes you will get ambiguity error.

              Regards, Sandip.

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              George_George
              wrote on last edited by
              #7

              Thanks Sandip, I have tried that when overriding in both classes, there will be compile error regarding the ambiguity issue. But when overriding only in one class, there is no compile error regarding the ambiguity issue, why?? regards, George

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              • G George_George

                Thanks Sandip, I have tried that when overriding in both classes, there will be compile error regarding the ambiguity issue. But when overriding only in one class, there is no compile error regarding the ambiguity issue, why?? regards, George

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                SandipG
                wrote on last edited by
                #8

                George_George wrote:

                But when overriding only in one class, there is no compile error regarding the ambiguity issue, why??

                In that case i think preference is given to overridden method. and you can always use scope resolution operator to execute desired method :)

                Regards, Sandip.

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                • S SandipG

                  George_George wrote:

                  But when overriding only in one class, there is no compile error regarding the ambiguity issue, why??

                  In that case i think preference is given to overridden method. and you can always use scope resolution operator to execute desired method :)

                  Regards, Sandip.

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                  George_George
                  wrote on last edited by
                  #9

                  Thanks Sandip, "In that case i think preference is given to overridden method." -- you mean when calling D.Display, there are two choices, 1. D::B::Display; 2. D::C::A::Display. But since (1) is "more" overridden than (2), (1) is preferred, but if we derive Display in both B and C, D will have no choice and there will be ambiguity compile error? regards, George

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                  • G George_George

                    Thanks Sandip, "In that case i think preference is given to overridden method." -- you mean when calling D.Display, there are two choices, 1. D::B::Display; 2. D::C::A::Display. But since (1) is "more" overridden than (2), (1) is preferred, but if we derive Display in both B and C, D will have no choice and there will be ambiguity compile error? regards, George

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                    SandipG
                    wrote on last edited by
                    #10

                    George_George wrote:

                    "In that case i think preference is given to overridden method." -- you mean when calling D.Display, there are two choices, 1. D::B::Display; 2. D::C::A::Display. But since (1) is "more" overridden than (2), (1) is preferred,

                    Yes from the behavior it seems like that. Even i did not come across any documents that states above behavior.

                    Regards, Sandip.

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                    • S SandipG

                      George_George wrote:

                      "In that case i think preference is given to overridden method." -- you mean when calling D.Display, there are two choices, 1. D::B::Display; 2. D::C::A::Display. But since (1) is "more" overridden than (2), (1) is preferred,

                      Yes from the behavior it seems like that. Even i did not come across any documents that states above behavior.

                      Regards, Sandip.

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                      George_George
                      wrote on last edited by
                      #11

                      Thanks Sandip, Here is what I learned from you -- virtual inheritance solves both member method and member data issue -- so we can say virtual inheritance solves all diamond problem issues (both ambiguity member method and data member). Could you review and confirm my understanding now is correct please? :-) regards, George

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                      • G George_George

                        Thanks Sandip, Here is what I learned from you -- virtual inheritance solves both member method and member data issue -- so we can say virtual inheritance solves all diamond problem issues (both ambiguity member method and data member). Could you review and confirm my understanding now is correct please? :-) regards, George

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                        SandipG
                        wrote on last edited by
                        #12

                        Yes unless there is no overriding of methods from the common ancestor as i said earlier.

                        Regards, Sandip.

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                        • S SandipG

                          Yes unless there is no overriding of methods from the common ancestor as i said earlier.

                          Regards, Sandip.

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                          George_George
                          wrote on last edited by
                          #13

                          I agree, thanks Sandip! regards, George

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                          • S SandipG

                            Hi George,

                            George_George wrote:

                            You code runs ok without any compile/build warning/errors.

                            That means virtual resolved methods as well as data member ambiguity so that does not clear your doubt. I hope it helps..

                            Regards, Sandip.

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                            laksh2204
                            wrote on last edited by
                            #14

                            I have some queries here.. 1. By making the inheritance virtual how the ambiguity is actually resolved? I mean, what this virtual inheritance does internally? Does it create another vptr of another vtable? if it is so how does the new vtable looks like?? 2. And as the diamond problem says that there is an ambiguity that whether D will have path A->B->D or A->C->D A / \ B C \ / D So after removing ambiguity which path is taken?

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