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diamond problem and virtual inheritance

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  • S SandipG

    Hi George,

    George_George wrote:

    You code runs ok without any compile/build warning/errors.

    That means virtual resolved methods as well as data member ambiguity so that does not clear your doubt. I hope it helps..

    Regards, Sandip.

    G Offline
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    George_George
    wrote on last edited by
    #5

    Thanks, Sandip! So, you mean virtual inheritance makes one copy of both methods and data? regards, George

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    • G George_George

      Thanks, Sandip! So, you mean virtual inheritance makes one copy of both methods and data? regards, George

      S Offline
      S Offline
      SandipG
      wrote on last edited by
      #6

      George_George wrote:

      So, you mean virtual inheritance makes one copy of both methods and data?

      Yes unless you do not override the common method in both derived classes. In above case if you override Display method in both derived classes you will get ambiguity error.

      Regards, Sandip.

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      • S SandipG

        George_George wrote:

        So, you mean virtual inheritance makes one copy of both methods and data?

        Yes unless you do not override the common method in both derived classes. In above case if you override Display method in both derived classes you will get ambiguity error.

        Regards, Sandip.

        G Offline
        G Offline
        George_George
        wrote on last edited by
        #7

        Thanks Sandip, I have tried that when overriding in both classes, there will be compile error regarding the ambiguity issue. But when overriding only in one class, there is no compile error regarding the ambiguity issue, why?? regards, George

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        • G George_George

          Thanks Sandip, I have tried that when overriding in both classes, there will be compile error regarding the ambiguity issue. But when overriding only in one class, there is no compile error regarding the ambiguity issue, why?? regards, George

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          S Offline
          SandipG
          wrote on last edited by
          #8

          George_George wrote:

          But when overriding only in one class, there is no compile error regarding the ambiguity issue, why??

          In that case i think preference is given to overridden method. and you can always use scope resolution operator to execute desired method :)

          Regards, Sandip.

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          • S SandipG

            George_George wrote:

            But when overriding only in one class, there is no compile error regarding the ambiguity issue, why??

            In that case i think preference is given to overridden method. and you can always use scope resolution operator to execute desired method :)

            Regards, Sandip.

            G Offline
            G Offline
            George_George
            wrote on last edited by
            #9

            Thanks Sandip, "In that case i think preference is given to overridden method." -- you mean when calling D.Display, there are two choices, 1. D::B::Display; 2. D::C::A::Display. But since (1) is "more" overridden than (2), (1) is preferred, but if we derive Display in both B and C, D will have no choice and there will be ambiguity compile error? regards, George

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            • G George_George

              Thanks Sandip, "In that case i think preference is given to overridden method." -- you mean when calling D.Display, there are two choices, 1. D::B::Display; 2. D::C::A::Display. But since (1) is "more" overridden than (2), (1) is preferred, but if we derive Display in both B and C, D will have no choice and there will be ambiguity compile error? regards, George

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              S Offline
              SandipG
              wrote on last edited by
              #10

              George_George wrote:

              "In that case i think preference is given to overridden method." -- you mean when calling D.Display, there are two choices, 1. D::B::Display; 2. D::C::A::Display. But since (1) is "more" overridden than (2), (1) is preferred,

              Yes from the behavior it seems like that. Even i did not come across any documents that states above behavior.

              Regards, Sandip.

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              • S SandipG

                George_George wrote:

                "In that case i think preference is given to overridden method." -- you mean when calling D.Display, there are two choices, 1. D::B::Display; 2. D::C::A::Display. But since (1) is "more" overridden than (2), (1) is preferred,

                Yes from the behavior it seems like that. Even i did not come across any documents that states above behavior.

                Regards, Sandip.

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                G Offline
                George_George
                wrote on last edited by
                #11

                Thanks Sandip, Here is what I learned from you -- virtual inheritance solves both member method and member data issue -- so we can say virtual inheritance solves all diamond problem issues (both ambiguity member method and data member). Could you review and confirm my understanding now is correct please? :-) regards, George

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                • G George_George

                  Thanks Sandip, Here is what I learned from you -- virtual inheritance solves both member method and member data issue -- so we can say virtual inheritance solves all diamond problem issues (both ambiguity member method and data member). Could you review and confirm my understanding now is correct please? :-) regards, George

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                  SandipG
                  wrote on last edited by
                  #12

                  Yes unless there is no overriding of methods from the common ancestor as i said earlier.

                  Regards, Sandip.

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                  • S SandipG

                    Yes unless there is no overriding of methods from the common ancestor as i said earlier.

                    Regards, Sandip.

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                    G Offline
                    George_George
                    wrote on last edited by
                    #13

                    I agree, thanks Sandip! regards, George

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                    • S SandipG

                      Hi George,

                      George_George wrote:

                      You code runs ok without any compile/build warning/errors.

                      That means virtual resolved methods as well as data member ambiguity so that does not clear your doubt. I hope it helps..

                      Regards, Sandip.

                      L Offline
                      L Offline
                      laksh2204
                      wrote on last edited by
                      #14

                      I have some queries here.. 1. By making the inheritance virtual how the ambiguity is actually resolved? I mean, what this virtual inheritance does internally? Does it create another vptr of another vtable? if it is so how does the new vtable looks like?? 2. And as the diamond problem says that there is an ambiguity that whether D will have path A->B->D or A->C->D A / \ B C \ / D So after removing ambiguity which path is taken?

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