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Need Help with Shuffle of a deck

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  • D Dalek Dave

    have you tried applying a number between 1 and 52 to each card, the as each number is picked randomly it is added to an array. on the next random call, it is checked to the contents of the array, and if found to have been picked already is rejected. It will slow doown as the cards are dealt, but then that array will be filled from 1 to 52 in random order, just apply the numbers back to the cards to give a random shuffle.

    ------------------------------------ "I am always serious about what I do, not necessarily about how I do it." Tom Baker

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    ymilan
    wrote on last edited by
    #8

    Thank you; I will try this...I appreciate your time.

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    • R riced

      Here's a possible solution. Note that I have not Dimmed all the variables. It's a classic way to do shuffling of card decks.

      Private Sub Start_Click()

      Dim arrDeck(52)
      Randomize

      ' Fill deck with cards in order 1 to 52
      CardCount = 1
      Do While CardCount <= 52
      arrDeck(CardCount) = Cardcount
      CardCount = CardCount + 1
      Loop

      ' Shuufle the deck - end value (100) could be anything, bigger it is the more shuffled deck is
      Counter = 0
      Do While Counter <= 100
      ' Get two random card positions
      card1 = Int((52 * Rnd) + 1)
      card2 = Int((52 * Rnd) + 1)

        ' Swap cards at these positions
        tmpCard        = arrDeck(card1)
        arrDeck(card1) = arrDeck(card2)
        arrDeck(card2) = tmpCard
      

      Loop

      ' Now output immages in order of deck
      CardCount = 1
      Do While CardCount <= 52
      Subnum = arrDeck(CardCount)
      Image1(Subnum).Visible = True
      CardCount = CardCount + 1
      Loop
      End Sub

      Regards David R

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      ymilan
      wrote on last edited by
      #9

      I went to compile this code in MS VB and it rejected as Compile Error all the values that were not dimmed....any ideas why? Thanks in advance.

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      • R riced

        Here's a possible solution. Note that I have not Dimmed all the variables. It's a classic way to do shuffling of card decks.

        Private Sub Start_Click()

        Dim arrDeck(52)
        Randomize

        ' Fill deck with cards in order 1 to 52
        CardCount = 1
        Do While CardCount <= 52
        arrDeck(CardCount) = Cardcount
        CardCount = CardCount + 1
        Loop

        ' Shuufle the deck - end value (100) could be anything, bigger it is the more shuffled deck is
        Counter = 0
        Do While Counter <= 100
        ' Get two random card positions
        card1 = Int((52 * Rnd) + 1)
        card2 = Int((52 * Rnd) + 1)

          ' Swap cards at these positions
          tmpCard        = arrDeck(card1)
          arrDeck(card1) = arrDeck(card2)
          arrDeck(card2) = tmpCard
        

        Loop

        ' Now output immages in order of deck
        CardCount = 1
        Do While CardCount <= 52
        Subnum = arrDeck(CardCount)
        Image1(Subnum).Visible = True
        CardCount = CardCount + 1
        Loop
        End Sub

        Regards David R

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        ymilan
        wrote on last edited by
        #10

        Hmm, seems to compile, but when I click the start button, the program hangs....any ideas?

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        • Y ymilan

          Hmm, seems to compile, but when I click the start button, the program hangs....any ideas?

          R Offline
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          riced
          wrote on last edited by
          #11

          Not without seeing the actual code you did and where it is called. I don't think there's anything in it that should cause a hang. I did not Dim all the variables because I was not sure what you had already declared. Obviously they need to be Dimmed somewhere.

          Regards David R

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          • R riced

            Here's a possible solution. Note that I have not Dimmed all the variables. It's a classic way to do shuffling of card decks.

            Private Sub Start_Click()

            Dim arrDeck(52)
            Randomize

            ' Fill deck with cards in order 1 to 52
            CardCount = 1
            Do While CardCount <= 52
            arrDeck(CardCount) = Cardcount
            CardCount = CardCount + 1
            Loop

            ' Shuufle the deck - end value (100) could be anything, bigger it is the more shuffled deck is
            Counter = 0
            Do While Counter <= 100
            ' Get two random card positions
            card1 = Int((52 * Rnd) + 1)
            card2 = Int((52 * Rnd) + 1)

              ' Swap cards at these positions
              tmpCard        = arrDeck(card1)
              arrDeck(card1) = arrDeck(card2)
              arrDeck(card2) = tmpCard
            

            Loop

            ' Now output immages in order of deck
            CardCount = 1
            Do While CardCount <= 52
            Subnum = arrDeck(CardCount)
            Image1(Subnum).Visible = True
            CardCount = CardCount + 1
            Loop
            End Sub

            Regards David R

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            ymilan
            wrote on last edited by
            #12

            ' I x'd out the lines to show what I am trying to do... Option Explicit Public Sub Main() Start_Game.Show End Sub Private Sub Exit_Click() MsgBox ("Thank you for playing! Good bye") End End Sub Private Sub Start_Click() Dim arrDeck(52) Randomize Dim Cardcount As Integer Dim Counter As Integer Dim Card1 As Integer Dim Card2 As Integer 'Dim CardVal As Integer 'Dim SubNum As Integer ' Fill deck with cards in order 1 to 52 Cardcount = 1 Do While Cardcount <= 52 arrDeck(Cardcount) = Cardcount Cardcount = Cardcount + 1 Loop ' Shuffle the deck - end value (100) Counter = 0 Do While Counter <= 100 ' Get two random card positions Card1 = Int((52 * Rnd) + 1) Card2 = Int((52 * Rnd) + 1) ' Swap cards at these positions Tmpcard = arrDeck(Card1) arrDeck(Card1) = arrDeck(Card2) arrDeck(Card2) = Tmpcard 'CardVal = Tmpcard ? Looking for a single value out of the random cards you made... Loop ' Now output images in order of deck Cardcount = 1 Counter = 0 ' It seems I need a counter in here for Subnum, 0-52 so it can display the cards from 0-52 slots, ' But the array of a single value out of the random cards you made need to be set to another counter, ' Right? I'm not sure...I x'd out the lines to show what I meant... 'Do While Cardcount <= 52 And Counter < 53 'If arrDeck(CardVal) = -1 Then ' arrDeck(CardVal) = Cardcount 'Image1(Cardcount) = CardVal ' Subnum = Counter 'Image1(Subnum).Visible = True Cardcount = Cardcount + 1 'Counter = Counter + 1 ' End If Loop End Sub

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            • Y ymilan

              Wow, thanks! This does make total sense, except I have one question which might be a "newbie type:" Cards.Add(i) would produce 0 -51 cards right? Then deck.Add(cards(cardNum" would produce a random ineger and remove at cardnum....since it is in the same function, then there is an end value of 52 right? It seems confusing to me on how the end value is represented in your shuffle procedure. Thanks very much for your time! You are AWESOME!

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              Dave Kreskowiak
              wrote on last edited by
              #13

              ymilan wrote:

              since it is in the same function, then there is an end value of 52 right?

              I don't get what your referring to. There is a COUNT of 52 items, 0 to 51 inclusive. The reason I wrote the method this way is because you can eliminate the top part the populates Cards with 0 to 51 and just pass in a collection of cards of any order. This method would then just "shuffle" a randomized deck. For example, you could have a method that passes a deck into this shuffle method a few times, passing in the deck that was returned, to really shuffle the deck. Also, you can create your own Card class and replace the List(Of Integer) references with List(Of Card) instead.

              A guide to posting questions on CodeProject[^]
              Dave Kreskowiak Microsoft MVP Visual Developer - Visual Basic
                   2006, 2007, 2008

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              • Y ymilan

                ' I x'd out the lines to show what I am trying to do... Option Explicit Public Sub Main() Start_Game.Show End Sub Private Sub Exit_Click() MsgBox ("Thank you for playing! Good bye") End End Sub Private Sub Start_Click() Dim arrDeck(52) Randomize Dim Cardcount As Integer Dim Counter As Integer Dim Card1 As Integer Dim Card2 As Integer 'Dim CardVal As Integer 'Dim SubNum As Integer ' Fill deck with cards in order 1 to 52 Cardcount = 1 Do While Cardcount <= 52 arrDeck(Cardcount) = Cardcount Cardcount = Cardcount + 1 Loop ' Shuffle the deck - end value (100) Counter = 0 Do While Counter <= 100 ' Get two random card positions Card1 = Int((52 * Rnd) + 1) Card2 = Int((52 * Rnd) + 1) ' Swap cards at these positions Tmpcard = arrDeck(Card1) arrDeck(Card1) = arrDeck(Card2) arrDeck(Card2) = Tmpcard 'CardVal = Tmpcard ? Looking for a single value out of the random cards you made... Loop ' Now output images in order of deck Cardcount = 1 Counter = 0 ' It seems I need a counter in here for Subnum, 0-52 so it can display the cards from 0-52 slots, ' But the array of a single value out of the random cards you made need to be set to another counter, ' Right? I'm not sure...I x'd out the lines to show what I meant... 'Do While Cardcount <= 52 And Counter < 53 'If arrDeck(CardVal) = -1 Then ' arrDeck(CardVal) = Cardcount 'Image1(Cardcount) = CardVal ' Subnum = Counter 'Image1(Subnum).Visible = True Cardcount = Cardcount + 1 'Counter = Counter + 1 ' End If Loop End Sub

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                riced
                wrote on last edited by
                #14

                I'm not sure why you need all the counters. Your Counter is always one less than Cardcount so is effectively redundant. In Do While Cardcount <= 52 And Counter < 53 both parts of the condition will have same logical value. What is Image1() - it looks like an array but has a Visible property. And this line implies that it is an array of integer: Image1(Cardcount) = CardVal In any case here's a new version of the code that shuffles the images directly. You would need to Dim tmpImage as an appropriate type. To get a single random image after shuffling you could just use Image1(1) i.e. the top of the pack; or you could use tmpImage.

                Private Sub Start_Click()
                Randomize

                'Dim tmpImage As ????
                Dim card1 As Integer
                Dim card2 As Integer
                Dim counter As Integer

                ' Shuffle the images - end value (100)
                Counter = 0
                Do While Counter <= 100
                ' Get two random image positions
                card1 = Int((52 * Rnd) + 1)
                card2 = Int((52 * Rnd) + 1)

                  ' Swap images at these positions
                  tmpImage      = Image1(card1)
                  Image1(card1) = Image1(card2)
                  Image1(card2) = tmpImage
                

                Loop

                ' Now output images in order
                counter = 1
                Do While counter <= 52
                Image1(counter).Visible = True
                counter = counter + 1
                Loop
                End Sub

                What version of VB are you using? I'd assumed VB.NET but I can't see where Image1() would fit in. But, IIRC, in VB6 there is an Image control (not used VB6 for about 5 years). EDIT: forgot to Dim counter :)

                Regards David R

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                • D Dave Kreskowiak

                  ymilan wrote:

                  since it is in the same function, then there is an end value of 52 right?

                  I don't get what your referring to. There is a COUNT of 52 items, 0 to 51 inclusive. The reason I wrote the method this way is because you can eliminate the top part the populates Cards with 0 to 51 and just pass in a collection of cards of any order. This method would then just "shuffle" a randomized deck. For example, you could have a method that passes a deck into this shuffle method a few times, passing in the deck that was returned, to really shuffle the deck. Also, you can create your own Card class and replace the List(Of Integer) references with List(Of Card) instead.

                  A guide to posting questions on CodeProject[^]
                  Dave Kreskowiak Microsoft MVP Visual Developer - Visual Basic
                       2006, 2007, 2008

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                  ymilan
                  wrote on last edited by
                  #15

                  Ok, I get it now. I was thinking along those lines, but got confused. Thanks.

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                  • R riced

                    I'm not sure why you need all the counters. Your Counter is always one less than Cardcount so is effectively redundant. In Do While Cardcount <= 52 And Counter < 53 both parts of the condition will have same logical value. What is Image1() - it looks like an array but has a Visible property. And this line implies that it is an array of integer: Image1(Cardcount) = CardVal In any case here's a new version of the code that shuffles the images directly. You would need to Dim tmpImage as an appropriate type. To get a single random image after shuffling you could just use Image1(1) i.e. the top of the pack; or you could use tmpImage.

                    Private Sub Start_Click()
                    Randomize

                    'Dim tmpImage As ????
                    Dim card1 As Integer
                    Dim card2 As Integer
                    Dim counter As Integer

                    ' Shuffle the images - end value (100)
                    Counter = 0
                    Do While Counter <= 100
                    ' Get two random image positions
                    card1 = Int((52 * Rnd) + 1)
                    card2 = Int((52 * Rnd) + 1)

                      ' Swap images at these positions
                      tmpImage      = Image1(card1)
                      Image1(card1) = Image1(card2)
                      Image1(card2) = tmpImage
                    

                    Loop

                    ' Now output images in order
                    counter = 1
                    Do While counter <= 52
                    Image1(counter).Visible = True
                    counter = counter + 1
                    Loop
                    End Sub

                    What version of VB are you using? I'd assumed VB.NET but I can't see where Image1() would fit in. But, IIRC, in VB6 there is an Image control (not used VB6 for about 5 years). EDIT: forgot to Dim counter :)

                    Regards David R

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                    Y Offline
                    ymilan
                    wrote on last edited by
                    #16

                    Ok, sure then, I can just pass the images through directly...then having overkill of counting. I see now. Thanks. As far as the version, perhaps this would be good to ask this question also, I'm using VB6 because that's all I have. It costs for VB.NET right? Not sure. I'm doing a specific game for my Mom, that's why I haven't upgraded am just using an older version. Images() was the visual image of the card I created on the form.

                    R 1 Reply Last reply
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                    • R riced

                      I'm not sure why you need all the counters. Your Counter is always one less than Cardcount so is effectively redundant. In Do While Cardcount <= 52 And Counter < 53 both parts of the condition will have same logical value. What is Image1() - it looks like an array but has a Visible property. And this line implies that it is an array of integer: Image1(Cardcount) = CardVal In any case here's a new version of the code that shuffles the images directly. You would need to Dim tmpImage as an appropriate type. To get a single random image after shuffling you could just use Image1(1) i.e. the top of the pack; or you could use tmpImage.

                      Private Sub Start_Click()
                      Randomize

                      'Dim tmpImage As ????
                      Dim card1 As Integer
                      Dim card2 As Integer
                      Dim counter As Integer

                      ' Shuffle the images - end value (100)
                      Counter = 0
                      Do While Counter <= 100
                      ' Get two random image positions
                      card1 = Int((52 * Rnd) + 1)
                      card2 = Int((52 * Rnd) + 1)

                        ' Swap images at these positions
                        tmpImage      = Image1(card1)
                        Image1(card1) = Image1(card2)
                        Image1(card2) = tmpImage
                      

                      Loop

                      ' Now output images in order
                      counter = 1
                      Do While counter <= 52
                      Image1(counter).Visible = True
                      counter = counter + 1
                      Loop
                      End Sub

                      What version of VB are you using? I'd assumed VB.NET but I can't see where Image1() would fit in. But, IIRC, in VB6 there is an Image control (not used VB6 for about 5 years). EDIT: forgot to Dim counter :)

                      Regards David R

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                      ymilan
                      wrote on last edited by
                      #17

                      Ok, I set tmpImage to As Image, is that correct? Then would I have the change the last few lines to reflect Do While Counter <= 52 Image1(TmpImage).Visible = True Counter = Counter + 1 Loop If so, gives an error like object variable or with block variable not set debugs on TmpImage = Image1(Card1)

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                      • Y ymilan

                        Ok, sure then, I can just pass the images through directly...then having overkill of counting. I see now. Thanks. As far as the version, perhaps this would be good to ask this question also, I'm using VB6 because that's all I have. It costs for VB.NET right? Not sure. I'm doing a specific game for my Mom, that's why I haven't upgraded am just using an older version. Images() was the visual image of the card I created on the form.

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                        riced
                        wrote on last edited by
                        #18

                        Glad to be of some help - my VB6 is a bit rusty but I should have spotted the use of Image1() :) You'll probably find that Dave K's solution won't work - it's .NET stuff. You can download VB.NET Express editions for free. There's two versions - 2005 and 2008. Probably best to go for 2008. Worth looking into. You can see what's available at http://www.microsoft.com/express/[^]

                        Regards David R

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                        • Y ymilan

                          Ok, I set tmpImage to As Image, is that correct? Then would I have the change the last few lines to reflect Do While Counter <= 52 Image1(TmpImage).Visible = True Counter = Counter + 1 Loop If so, gives an error like object variable or with block variable not set debugs on TmpImage = Image1(Card1)

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                          riced
                          wrote on last edited by
                          #19

                          If tmpImage is an Image (it has to be whatever is in Image1() so what type of object does Image1() store?) then you can't use it as an index to Image1(). Using counter as the index will make all the images visible. I don't have VB6 running anymore so I'm relying on memory. :)

                          Regards David R

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                          • R riced

                            If tmpImage is an Image (it has to be whatever is in Image1() so what type of object does Image1() store?) then you can't use it as an index to Image1(). Using counter as the index will make all the images visible. I don't have VB6 running anymore so I'm relying on memory. :)

                            Regards David R

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                            ymilan
                            wrote on last edited by
                            #20

                            Image1() stores an array... 0-52, was created automatically when I set up the cards on the form.

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                            • Y ymilan

                              Image1() stores an array... 0-52, was created automatically when I set up the cards on the form.

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                              riced
                              wrote on last edited by
                              #21

                              It must be an array of something - the same type as the cards? Can yo see the code that fills the array? That should tell you what the type is. As an alternative, you could try Dimming tmpImage As Variant - that would allow it to hold anything. But you still can't use it as an index into the array.

                              Regards David R

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                              • R riced

                                It must be an array of something - the same type as the cards? Can yo see the code that fills the array? That should tell you what the type is. As an alternative, you could try Dimming tmpImage As Variant - that would allow it to hold anything. But you still can't use it as an index into the array.

                                Regards David R

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                                ymilan
                                wrote on last edited by
                                #22

                                It's an array of images, as in I click on one of the images on the form and it states image1(0) Image That's what it states, so I should set tmpImage to Image, but it still produces the same error. Should I try a third integer variable to use with tmpImage, as in tmpImage(Card3) and have Card3 be a random number?

                                1 Reply Last reply
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                                • R riced

                                  It must be an array of something - the same type as the cards? Can yo see the code that fills the array? That should tell you what the type is. As an alternative, you could try Dimming tmpImage As Variant - that would allow it to hold anything. But you still can't use it as an index into the array.

                                  Regards David R

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                                  ymilan
                                  wrote on last edited by
                                  #23

                                  Should I dim tmpimage as image and set it using a set statement to an array of an index? or integer? How would I do that?

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                                  • Y ymilan

                                    Should I dim tmpimage as image and set it using a set statement to an array of an index? or integer? How would I do that?

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                                    riced
                                    wrote on last edited by
                                    #24

                                    I'd forgotten you need to use Set when dealing with 'objects - mea culpa. :) So in the shuffle loop you need this:

                                      Set tmpImage      = Image1(card1)
                                      Set Image1(card1) = Image1(card2)
                                      Set Image1(card2) = tmpImage
                                    

                                    tmpImage must be of the same type as whatever the Image1() array holds (or it could be Variant). It can't be an Integer nor an array of anything. All it's used for is to allow items in the Image1() array to be swapped. It has no other use in the code. How many images do you want to display at once? If you only want one then the second loop is not needed. You could just do something like Image1(1).Visible = True to display the first image.

                                    Regards David R

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                                    • R riced

                                      I'd forgotten you need to use Set when dealing with 'objects - mea culpa. :) So in the shuffle loop you need this:

                                        Set tmpImage      = Image1(card1)
                                        Set Image1(card1) = Image1(card2)
                                        Set Image1(card2) = tmpImage
                                      

                                      tmpImage must be of the same type as whatever the Image1() array holds (or it could be Variant). It can't be an Integer nor an array of anything. All it's used for is to allow items in the Image1() array to be swapped. It has no other use in the code. How many images do you want to display at once? If you only want one then the second loop is not needed. You could just do something like Image1(1).Visible = True to display the first image.

                                      Regards David R

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                                      ymilan
                                      wrote on last edited by
                                      #25

                                      Ok, great! I had to put in counter + 1 though for it to partially work... Set tmpImage = Image1(Card1) Set Image1(Card1) = Image1(Card2) Set Image1(Card2) = tmpImage Counter = Counter + 1 Loop But also, it doesn't show the first card; tried changing counter to equal 0, but didn't help; any ideas?

                                      R 1 Reply Last reply
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                                      • Y ymilan

                                        Ok, great! I had to put in counter + 1 though for it to partially work... Set tmpImage = Image1(Card1) Set Image1(Card1) = Image1(Card2) Set Image1(Card2) = tmpImage Counter = Counter + 1 Loop But also, it doesn't show the first card; tried changing counter to equal 0, but didn't help; any ideas?

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                                        riced
                                        wrote on last edited by
                                        #26

                                        Can't believe I made such a blunder :doh: - but it's because I would normally use a For loop like so (and I'm writing the code in Notepad so no help from the editor :) ).

                                        For counter = 0 to 100
                                        ' Get two random image positions
                                        card1 = Int((52 * Rnd) + 1)
                                        card2 = Int((52 * Rnd) + 1)

                                          ' Swap images at these positions
                                          Set tmpImage      = Image1(card1)
                                          Set Image1(card1) = Image1(card2)
                                          Set Image1(card2) = tmpImage
                                        

                                        Next counter

                                        Then I don't have to increase counter, the loop does it for me. Note that counter is just counting the numbers of swaps done - it has nothing to do with the number of images it could be set to do 1000 or whatever you like. All this loop does is shuffle the images. It does not display them in any way - that's down to the Image1(x).Visible = True where x is the number of the image you want to display. Not sure why it's not displaying. You might try refreshing the the form (i.e add Form.Refresh or a DoEvents after setting Image1(1).Visible = True.

                                        Regards David R

                                        Y 3 Replies Last reply
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                                        • R riced

                                          Can't believe I made such a blunder :doh: - but it's because I would normally use a For loop like so (and I'm writing the code in Notepad so no help from the editor :) ).

                                          For counter = 0 to 100
                                          ' Get two random image positions
                                          card1 = Int((52 * Rnd) + 1)
                                          card2 = Int((52 * Rnd) + 1)

                                            ' Swap images at these positions
                                            Set tmpImage      = Image1(card1)
                                            Set Image1(card1) = Image1(card2)
                                            Set Image1(card2) = tmpImage
                                          

                                          Next counter

                                          Then I don't have to increase counter, the loop does it for me. Note that counter is just counting the numbers of swaps done - it has nothing to do with the number of images it could be set to do 1000 or whatever you like. All this loop does is shuffle the images. It does not display them in any way - that's down to the Image1(x).Visible = True where x is the number of the image you want to display. Not sure why it's not displaying. You might try refreshing the the form (i.e add Form.Refresh or a DoEvents after setting Image1(1).Visible = True.

                                          Regards David R

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                                          ymilan
                                          wrote on last edited by
                                          #27

                                          No problem; you'll always be smarter at this than me. Anyhow, I'll try refreshing the form then. Thanks so much! Yvonne

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