Need Help with Shuffle of a deck
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Wow, thanks! This does make total sense, except I have one question which might be a "newbie type:" Cards.Add(i) would produce 0 -51 cards right? Then deck.Add(cards(cardNum" would produce a random ineger and remove at cardnum....since it is in the same function, then there is an end value of 52 right? It seems confusing to me on how the end value is represented in your shuffle procedure. Thanks very much for your time! You are AWESOME!
ymilan wrote:
since it is in the same function, then there is an end value of 52 right?
I don't get what your referring to. There is a COUNT of 52 items, 0 to 51 inclusive. The reason I wrote the method this way is because you can eliminate the top part the populates Cards with 0 to 51 and just pass in a collection of cards of any order. This method would then just "shuffle" a randomized deck. For example, you could have a method that passes a deck into this shuffle method a few times, passing in the deck that was returned, to really shuffle the deck. Also, you can create your own Card class and replace the List(Of Integer) references with List(Of Card) instead.
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Dave Kreskowiak Microsoft MVP Visual Developer - Visual Basic
2006, 2007, 2008 -
' I x'd out the lines to show what I am trying to do... Option Explicit Public Sub Main() Start_Game.Show End Sub Private Sub Exit_Click() MsgBox ("Thank you for playing! Good bye") End End Sub Private Sub Start_Click() Dim arrDeck(52) Randomize Dim Cardcount As Integer Dim Counter As Integer Dim Card1 As Integer Dim Card2 As Integer 'Dim CardVal As Integer 'Dim SubNum As Integer ' Fill deck with cards in order 1 to 52 Cardcount = 1 Do While Cardcount <= 52 arrDeck(Cardcount) = Cardcount Cardcount = Cardcount + 1 Loop ' Shuffle the deck - end value (100) Counter = 0 Do While Counter <= 100 ' Get two random card positions Card1 = Int((52 * Rnd) + 1) Card2 = Int((52 * Rnd) + 1) ' Swap cards at these positions Tmpcard = arrDeck(Card1) arrDeck(Card1) = arrDeck(Card2) arrDeck(Card2) = Tmpcard 'CardVal = Tmpcard ? Looking for a single value out of the random cards you made... Loop ' Now output images in order of deck Cardcount = 1 Counter = 0 ' It seems I need a counter in here for Subnum, 0-52 so it can display the cards from 0-52 slots, ' But the array of a single value out of the random cards you made need to be set to another counter, ' Right? I'm not sure...I x'd out the lines to show what I meant... 'Do While Cardcount <= 52 And Counter < 53 'If arrDeck(CardVal) = -1 Then ' arrDeck(CardVal) = Cardcount 'Image1(Cardcount) = CardVal ' Subnum = Counter 'Image1(Subnum).Visible = True Cardcount = Cardcount + 1 'Counter = Counter + 1 ' End If Loop End Sub
I'm not sure why you need all the counters. Your Counter is always one less than Cardcount so is effectively redundant. In
Do While Cardcount <= 52 And Counter < 53both parts of the condition will have same logical value. What is Image1() - it looks like an array but has a Visible property. And this line implies that it is an array of integer:Image1(Cardcount) = CardValIn any case here's a new version of the code that shuffles the images directly. You would need to Dim tmpImage as an appropriate type. To get a single random image after shuffling you could just use Image1(1) i.e. the top of the pack; or you could use tmpImage.Private Sub Start_Click()
Randomize'Dim tmpImage As ????
Dim card1 As Integer
Dim card2 As Integer
Dim counter As Integer' Shuffle the images - end value (100)
Counter = 0
Do While Counter <= 100
' Get two random image positions
card1 = Int((52 * Rnd) + 1)
card2 = Int((52 * Rnd) + 1)' Swap images at these positions tmpImage = Image1(card1) Image1(card1) = Image1(card2) Image1(card2) = tmpImageLoop
' Now output images in order
counter = 1
Do While counter <= 52
Image1(counter).Visible = True
counter = counter + 1
Loop
End SubWhat version of VB are you using? I'd assumed VB.NET but I can't see where Image1() would fit in. But, IIRC, in VB6 there is an Image control (not used VB6 for about 5 years). EDIT: forgot to Dim counter :)
Regards David R
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ymilan wrote:
since it is in the same function, then there is an end value of 52 right?
I don't get what your referring to. There is a COUNT of 52 items, 0 to 51 inclusive. The reason I wrote the method this way is because you can eliminate the top part the populates Cards with 0 to 51 and just pass in a collection of cards of any order. This method would then just "shuffle" a randomized deck. For example, you could have a method that passes a deck into this shuffle method a few times, passing in the deck that was returned, to really shuffle the deck. Also, you can create your own Card class and replace the List(Of Integer) references with List(Of Card) instead.
A guide to posting questions on CodeProject[^]
Dave Kreskowiak Microsoft MVP Visual Developer - Visual Basic
2006, 2007, 2008 -
I'm not sure why you need all the counters. Your Counter is always one less than Cardcount so is effectively redundant. In
Do While Cardcount <= 52 And Counter < 53both parts of the condition will have same logical value. What is Image1() - it looks like an array but has a Visible property. And this line implies that it is an array of integer:Image1(Cardcount) = CardValIn any case here's a new version of the code that shuffles the images directly. You would need to Dim tmpImage as an appropriate type. To get a single random image after shuffling you could just use Image1(1) i.e. the top of the pack; or you could use tmpImage.Private Sub Start_Click()
Randomize'Dim tmpImage As ????
Dim card1 As Integer
Dim card2 As Integer
Dim counter As Integer' Shuffle the images - end value (100)
Counter = 0
Do While Counter <= 100
' Get two random image positions
card1 = Int((52 * Rnd) + 1)
card2 = Int((52 * Rnd) + 1)' Swap images at these positions tmpImage = Image1(card1) Image1(card1) = Image1(card2) Image1(card2) = tmpImageLoop
' Now output images in order
counter = 1
Do While counter <= 52
Image1(counter).Visible = True
counter = counter + 1
Loop
End SubWhat version of VB are you using? I'd assumed VB.NET but I can't see where Image1() would fit in. But, IIRC, in VB6 there is an Image control (not used VB6 for about 5 years). EDIT: forgot to Dim counter :)
Regards David R
Ok, sure then, I can just pass the images through directly...then having overkill of counting. I see now. Thanks. As far as the version, perhaps this would be good to ask this question also, I'm using VB6 because that's all I have. It costs for VB.NET right? Not sure. I'm doing a specific game for my Mom, that's why I haven't upgraded am just using an older version. Images() was the visual image of the card I created on the form.
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I'm not sure why you need all the counters. Your Counter is always one less than Cardcount so is effectively redundant. In
Do While Cardcount <= 52 And Counter < 53both parts of the condition will have same logical value. What is Image1() - it looks like an array but has a Visible property. And this line implies that it is an array of integer:Image1(Cardcount) = CardValIn any case here's a new version of the code that shuffles the images directly. You would need to Dim tmpImage as an appropriate type. To get a single random image after shuffling you could just use Image1(1) i.e. the top of the pack; or you could use tmpImage.Private Sub Start_Click()
Randomize'Dim tmpImage As ????
Dim card1 As Integer
Dim card2 As Integer
Dim counter As Integer' Shuffle the images - end value (100)
Counter = 0
Do While Counter <= 100
' Get two random image positions
card1 = Int((52 * Rnd) + 1)
card2 = Int((52 * Rnd) + 1)' Swap images at these positions tmpImage = Image1(card1) Image1(card1) = Image1(card2) Image1(card2) = tmpImageLoop
' Now output images in order
counter = 1
Do While counter <= 52
Image1(counter).Visible = True
counter = counter + 1
Loop
End SubWhat version of VB are you using? I'd assumed VB.NET but I can't see where Image1() would fit in. But, IIRC, in VB6 there is an Image control (not used VB6 for about 5 years). EDIT: forgot to Dim counter :)
Regards David R
Ok, I set tmpImage to As Image, is that correct? Then would I have the change the last few lines to reflect Do While Counter <= 52 Image1(TmpImage).Visible = True Counter = Counter + 1 Loop If so, gives an error like object variable or with block variable not set debugs on TmpImage = Image1(Card1)
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Ok, sure then, I can just pass the images through directly...then having overkill of counting. I see now. Thanks. As far as the version, perhaps this would be good to ask this question also, I'm using VB6 because that's all I have. It costs for VB.NET right? Not sure. I'm doing a specific game for my Mom, that's why I haven't upgraded am just using an older version. Images() was the visual image of the card I created on the form.
Glad to be of some help - my VB6 is a bit rusty but I should have spotted the use of Image1() :) You'll probably find that Dave K's solution won't work - it's .NET stuff. You can download VB.NET Express editions for free. There's two versions - 2005 and 2008. Probably best to go for 2008. Worth looking into. You can see what's available at http://www.microsoft.com/express/[^]
Regards David R
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Ok, I set tmpImage to As Image, is that correct? Then would I have the change the last few lines to reflect Do While Counter <= 52 Image1(TmpImage).Visible = True Counter = Counter + 1 Loop If so, gives an error like object variable or with block variable not set debugs on TmpImage = Image1(Card1)
If tmpImage is an Image (it has to be whatever is in Image1() so what type of object does Image1() store?) then you can't use it as an index to Image1(). Using counter as the index will make all the images visible. I don't have VB6 running anymore so I'm relying on memory. :)
Regards David R
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If tmpImage is an Image (it has to be whatever is in Image1() so what type of object does Image1() store?) then you can't use it as an index to Image1(). Using counter as the index will make all the images visible. I don't have VB6 running anymore so I'm relying on memory. :)
Regards David R
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Image1() stores an array... 0-52, was created automatically when I set up the cards on the form.
It must be an array of something - the same type as the cards? Can yo see the code that fills the array? That should tell you what the type is. As an alternative, you could try Dimming tmpImage As Variant - that would allow it to hold anything. But you still can't use it as an index into the array.
Regards David R
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It must be an array of something - the same type as the cards? Can yo see the code that fills the array? That should tell you what the type is. As an alternative, you could try Dimming tmpImage As Variant - that would allow it to hold anything. But you still can't use it as an index into the array.
Regards David R
It's an array of images, as in I click on one of the images on the form and it states image1(0) Image That's what it states, so I should set tmpImage to Image, but it still produces the same error. Should I try a third integer variable to use with tmpImage, as in tmpImage(Card3) and have Card3 be a random number?
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It must be an array of something - the same type as the cards? Can yo see the code that fills the array? That should tell you what the type is. As an alternative, you could try Dimming tmpImage As Variant - that would allow it to hold anything. But you still can't use it as an index into the array.
Regards David R
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Should I dim tmpimage as image and set it using a set statement to an array of an index? or integer? How would I do that?
I'd forgotten you need to use Set when dealing with 'objects - mea culpa. :) So in the shuffle loop you need this:
Set tmpImage = Image1(card1) Set Image1(card1) = Image1(card2) Set Image1(card2) = tmpImagetmpImage must be of the same type as whatever the Image1() array holds (or it could be Variant). It can't be an Integer nor an array of anything. All it's used for is to allow items in the Image1() array to be swapped. It has no other use in the code. How many images do you want to display at once? If you only want one then the second loop is not needed. You could just do something like
Image1(1).Visible = Trueto display the first image.Regards David R
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I'd forgotten you need to use Set when dealing with 'objects - mea culpa. :) So in the shuffle loop you need this:
Set tmpImage = Image1(card1) Set Image1(card1) = Image1(card2) Set Image1(card2) = tmpImagetmpImage must be of the same type as whatever the Image1() array holds (or it could be Variant). It can't be an Integer nor an array of anything. All it's used for is to allow items in the Image1() array to be swapped. It has no other use in the code. How many images do you want to display at once? If you only want one then the second loop is not needed. You could just do something like
Image1(1).Visible = Trueto display the first image.Regards David R
Ok, great! I had to put in counter + 1 though for it to partially work... Set tmpImage = Image1(Card1) Set Image1(Card1) = Image1(Card2) Set Image1(Card2) = tmpImage Counter = Counter + 1 Loop But also, it doesn't show the first card; tried changing counter to equal 0, but didn't help; any ideas?
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Ok, great! I had to put in counter + 1 though for it to partially work... Set tmpImage = Image1(Card1) Set Image1(Card1) = Image1(Card2) Set Image1(Card2) = tmpImage Counter = Counter + 1 Loop But also, it doesn't show the first card; tried changing counter to equal 0, but didn't help; any ideas?
Can't believe I made such a blunder :doh: - but it's because I would normally use a For loop like so (and I'm writing the code in Notepad so no help from the editor :) ).
For counter = 0 to 100
' Get two random image positions
card1 = Int((52 * Rnd) + 1)
card2 = Int((52 * Rnd) + 1)' Swap images at these positions Set tmpImage = Image1(card1) Set Image1(card1) = Image1(card2) Set Image1(card2) = tmpImageNext counter
Then I don't have to increase
counter, the loop does it for me. Note thatcounteris just counting the numbers of swaps done - it has nothing to do with the number of images it could be set to do 1000 or whatever you like. All this loop does is shuffle the images. It does not display them in any way - that's down to theImage1(x).Visible = Truewhere x is the number of the image you want to display. Not sure why it's not displaying. You might try refreshing the the form (i.e add Form.Refresh or a DoEvents after settingImage1(1).Visible = True.Regards David R
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Can't believe I made such a blunder :doh: - but it's because I would normally use a For loop like so (and I'm writing the code in Notepad so no help from the editor :) ).
For counter = 0 to 100
' Get two random image positions
card1 = Int((52 * Rnd) + 1)
card2 = Int((52 * Rnd) + 1)' Swap images at these positions Set tmpImage = Image1(card1) Set Image1(card1) = Image1(card2) Set Image1(card2) = tmpImageNext counter
Then I don't have to increase
counter, the loop does it for me. Note thatcounteris just counting the numbers of swaps done - it has nothing to do with the number of images it could be set to do 1000 or whatever you like. All this loop does is shuffle the images. It does not display them in any way - that's down to theImage1(x).Visible = Truewhere x is the number of the image you want to display. Not sure why it's not displaying. You might try refreshing the the form (i.e add Form.Refresh or a DoEvents after settingImage1(1).Visible = True.Regards David R
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No problem; you'll always be smarter at this than me. Anyhow, I'll try refreshing the form then. Thanks so much! Yvonne
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Can't believe I made such a blunder :doh: - but it's because I would normally use a For loop like so (and I'm writing the code in Notepad so no help from the editor :) ).
For counter = 0 to 100
' Get two random image positions
card1 = Int((52 * Rnd) + 1)
card2 = Int((52 * Rnd) + 1)' Swap images at these positions Set tmpImage = Image1(card1) Set Image1(card1) = Image1(card2) Set Image1(card2) = tmpImageNext counter
Then I don't have to increase
counter, the loop does it for me. Note thatcounteris just counting the numbers of swaps done - it has nothing to do with the number of images it could be set to do 1000 or whatever you like. All this loop does is shuffle the images. It does not display them in any way - that's down to theImage1(x).Visible = Truewhere x is the number of the image you want to display. Not sure why it's not displaying. You might try refreshing the the form (i.e add Form.Refresh or a DoEvents after settingImage1(1).Visible = True.Regards David R
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Can't believe I made such a blunder :doh: - but it's because I would normally use a For loop like so (and I'm writing the code in Notepad so no help from the editor :) ).
For counter = 0 to 100
' Get two random image positions
card1 = Int((52 * Rnd) + 1)
card2 = Int((52 * Rnd) + 1)' Swap images at these positions Set tmpImage = Image1(card1) Set Image1(card1) = Image1(card2) Set Image1(card2) = tmpImageNext counter
Then I don't have to increase
counter, the loop does it for me. Note thatcounteris just counting the numbers of swaps done - it has nothing to do with the number of images it could be set to do 1000 or whatever you like. All this loop does is shuffle the images. It does not display them in any way - that's down to theImage1(x).Visible = Truewhere x is the number of the image you want to display. Not sure why it's not displaying. You might try refreshing the the form (i.e add Form.Refresh or a DoEvents after settingImage1(1).Visible = True.Regards David R
This doesn't work, but this is what I'm trying to say: ' Shuffle the deck - end value (100) Card1 = 0 Card2 = 1 Counter = 0 If Card1 <> Card2 And Counter <= 100 Then ' Get two random image positions 3 Card1 = Int((52 * Rnd) + 1) Card2 = Int((52 * Rnd) + 1) ' Swap images at these positions Set tmpImage = Image1(Card1) Set Image1(Card1) = Image1(Card2) Set Image1(Card2) = tmpImage Counter = Counter + 1 ElseIf Card1 = Card2 Then GoTo 3 End If
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Hello, Well it still shows two of a kinds after the shuffle. I've tried various things with While and Do nested loops and same with If Then EndIf, but nothing seems to work...I'm trying though. Any ideas?
I'm not sure what the program is supposed to do so not sure why it's not working. Can you tell me what the form looks like (e.g. how many image controls it displays)? What should happen when the Start button is clicked (I assume Start is a button)? Should it display one card or more than one?
Regards David R
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I'm not sure what the program is supposed to do so not sure why it's not working. Can you tell me what the form looks like (e.g. how many image controls it displays)? What should happen when the Start button is clicked (I assume Start is a button)? Should it display one card or more than one?
Regards David R
Well, it is displaying all the cards 4 across and 13 down in full suits w/out jokers, of course. Then when the cards are random and shuffled, they should display the same amount of cards in same positions, but random ones. What happens when I compile and run the program, is that more of one of the same cards are displayed, thus showing not totally random cards. Somehow, I'm thinking Card1 should not equal Card2 from the random procedure, then the cards are shuffled, and then distributed out....but there is no code that shows Card1 should not equal to Card2 at all, for to be randomly displayed. Any ideas? Thank you.