how to solve zipe files with space ? [modified]

[Golden Jing]

Dear all, I use VB 2005 with shell comman for zip file. my task for zip is with space of folder name and file. So when i zip them. it was not successfull. It causes of space. that my source code: shell("C:\Program Files\WinZip\WZZIP.EXE -u D:\Ready Sent\File1.zip D:\Source File\File Send.PDF") Do you have any solve of this issue ? Thanks for your help...

VB.Net

modified on Friday, January 1, 2010 6:25 AM

[DaveAuld]

Why did you delete your message previously asked and then create this new post? you should have edited your original question and added the additional info. Have you tried enclosing the path/filename statements in quotation marks? the interpreter is probably failing on the spaces.

shell(""""C:\Program Files\WinZip\WZZIP.EXE -u D:\Ready Sent\File1.zip D:\Source File\File Send.PDF"""")

or split it up further for each parmater like:

shell(""""C:\Program Files\WinZip\WZZIP.EXE -u""" """D:\Ready Sent\File1.zip""" """D:\Source File\File Send.PDF"""")

Dave Who am I?: Web|Facebook|Twitter|LinkedIn|Bebo

[Golden Jing]

ohh becuase the first is similar the new one so i delete. ohh i tryed follow that your code shell(""""C:\Program Files\WinZip\WZZIP.EXE -u""" """D:\Ready Sent\File1.zip""" """D:\Source File\File Send.PDF"""") but it sitll can not work and get that syntax error. what about problem ?

VB.Net

[DaveAuld]

have you tried to get it to work from the command line first? then copy the string into the code. Alternatively, have you tried passing the argument in as a parameter of the process.start method instead of using shell.

Process.Start("C:\Program Files\WinZip\WZZIP.EXE", "-u D:\Ready Sent\File1.zip D:\Source File\File Send.PDF")

Dave Who am I?: Web|Facebook|Twitter|LinkedIn|Bebo

[Golden Jing]

try your code but it is still not support with space. Process.Start("C:\Program Files\WinZip\WZZIP.EXE", "-u D:\Ready Sent\File1.zip D:\Source File\File Send.PDF") i add -yp it shows that: Warning: name not matched: Sent/File1.zip Warning: name not matched: D:/Source Warning: name not matched: File/File Warning: name not matched: Send.PDF Warning: D:\Ready.zip not found or empty Error: No files were found for this action that match your criteria - nothing to do. what about that problem ? Can you give me example ? or any else for solve that?

VB.Net

[Alan N]

Hi, If this were running from the DOS prompt the command line would be

"C:\Program Files\WinZip\WZZIP.EXE" -u "D:\Ready Sent\File1.zip D:\Source File\File Send.PDF"

Providing the correct VB escaping for the quote characters gives

shell("""C:\Program Files\WinZip\WZZIP.EXE"" -u ""D:\Ready Sent\File1.zip D:\Source File\File Send.PDF""")

I think! [EDIT] Ah, didn't spot the multiple filenames Try this

shell("""C:\Program Files\WinZip\WZZIP.EXE"" -u ""D:\Ready Sent\File1.zip"" ""D:\Source File\File Send.PDF""")

Alan.

modified on Friday, January 1, 2010 12:19 PM

[Golden Jing]

Dear Alan yes it runs DOS. i tryed like your code and add -yp for showing DOS message: Shell("""C:\Program Files\WinZip\WZZIP.EXE"" -yp -u ""D:\Ready Sent\File1.zip D:\Source File\File Send.PDF""") the message showed that: Warning: D:\Ready Sent\File1.zip D:\Source File\File Send.PDF not found or empty Error: Could not creat output file Do you have any idea or solving else ?

VB.Net

[Alan N]

Hi, See my corrected modified post. Alan.

[Golden Jing]

Thanks you so much Alan your suport. It is still warning that -> Warning D:Ready Sent\File1.zip not found or empty Adding VB.Net