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RegEx expression help

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regexquestionhelptutorial
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  • F Fayu

    DOH!!! Values with spaces dont work.... how do I resolve that>

    N Offline
    N Offline
    NavnathKale
    wrote on last edited by
    #16

    Dont worry my solution still works !!! I guess u don;t need name captured groups, so I have removed it n here is new one

    (\[{3}MyProperty4\]{3}[\s{1}])(.*?(?=\s{1}\[|$))

    Mark as anwser !!!! :-D

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    • F Fayu

      The property name is looks like this [[[MyProperty2]]] but does not end with . So the property/value item shows up as [[[MyProperty2]]] Value2. So if there are multiple properties it will look like this: [[[MyProperty1]]] Value1 [[[MyProperty2]]] Value2 [[[MyProperty3]]] Value3. Having said that, the pattern provided did not work because I think it is looking for end tag. One other thing I want to point out is that there can be only one property which can or cannot have a space after it. My requirements: 1) Get the value of a property if only one propery is listed ([[[MyProperty1]]] value1) 2) Get the value of a property if there are more than one properies listed ([[[MyProperty1]]] value1 [[[MyProperty2]]] value2 [[[MyProperty3]]] value3 3) In the pattern, I want to pass in the property name and get back the value 4) Use VBScript.RegexExp object (which I dont think will make a difference when it comes to pattern) Thanks so much for assisting me with this.

      P Offline
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      PIEBALDconsult
      wrote on last edited by
      #17

      I prefer the technique I showed. You then enumerate the Matches and fill a Dictionary with the Names and Values. Your requirements 1 -- 3 are then satisfied by the Dictionary and you only have to execute the RegEx once per group of properties.

      Fayu wrote:

      Use VBScript

      Then why post it in the C# forum? Or maybe you should give more information on the bigger picture of what you are trying to accomplish.

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      • N NavnathKale

        Dont worry my solution still works !!! I guess u don;t need name captured groups, so I have removed it n here is new one

        (\[{3}MyProperty4\]{3}[\s{1}])(.*?(?=\s{1}\[|$))

        Mark as anwser !!!! :-D

        F Offline
        F Offline
        Fayu
        wrote on last edited by
        #18

        Works like a charm!!! Any way I can just have the value returned?

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        • N NavnathKale

          Dont worry my solution still works !!! I guess u don;t need name captured groups, so I have removed it n here is new one

          (\[{3}MyProperty4\]{3}[\s{1}])(.*?(?=\s{1}\[|$))

          Mark as anwser !!!! :-D

          F Offline
          F Offline
          Fayu
          wrote on last edited by
          #19

          I would LOVE an explanation on the logic behind this... (\[{3}Property2\]{3}[\s{1}])(.*?(?=\s{1}\[|$)) The only part I understand is (\[{3}Property2\]{3}[\s{1}])

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          • F Fayu

            Works like a charm!!! Any way I can just have the value returned?

            N Offline
            N Offline
            NavnathKale
            wrote on last edited by
            #20

            Now time to callback my initial post. :| Like I said use Named capturing groups. Using this you can just return the value of provided propertyname

            Regex regex = new Regex(@"(\[{3}MyProperty3\]{3}[\s{1}])(?<MyProperty3>.*?(?=\s{1}\[|$))");
            Match regexmatch = regex.Match(@"[[[MyProperty1]]] Value [[[MyProperty2]]] value2 [[[MyProperty3]]] value 3");
            string value = regexmatch.Groups["MyProperty3"].Value

            Above code will return value of property MyProperty3

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            • F Fayu

              I would LOVE an explanation on the logic behind this... (\[{3}Property2\]{3}[\s{1}])(.*?(?=\s{1}\[|$)) The only part I understand is (\[{3}Property2\]{3}[\s{1}])

              N Offline
              N Offline
              NavnathKale
              wrote on last edited by
              #21

              Yeah!!! u ought to know everything thats going around on earth :wtf: Google will take you to right place if you search for positive lookahead in regex :-\

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              • P PIEBALDconsult

                I prefer the technique I showed. You then enumerate the Matches and fill a Dictionary with the Names and Values. Your requirements 1 -- 3 are then satisfied by the Dictionary and you only have to execute the RegEx once per group of properties.

                Fayu wrote:

                Use VBScript

                Then why post it in the C# forum? Or maybe you should give more information on the bigger picture of what you are trying to accomplish.

                N Offline
                N Offline
                NavnathKale
                wrote on last edited by
                #22

                Your solution will also give same result, but it will return all properties. As Fayu asked on his requirement, it wasnt he is looking for. Cheers !!!

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                • N NavnathKale

                  Your solution will also give same result, but it will return all properties. As Fayu asked on his requirement, it wasnt he is looking for. Cheers !!!

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                  PIEBALDconsult
                  wrote on last edited by
                  #23

                  Navnath R. Kale wrote:

                  it wasnt he is looking for

                  It should be.

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                  • P PIEBALDconsult

                    I prefer the technique I showed. You then enumerate the Matches and fill a Dictionary with the Names and Values. Your requirements 1 -- 3 are then satisfied by the Dictionary and you only have to execute the RegEx once per group of properties.

                    Fayu wrote:

                    Use VBScript

                    Then why post it in the C# forum? Or maybe you should give more information on the bigger picture of what you are trying to accomplish.

                    P Offline
                    P Offline
                    PIEBALDconsult
                    wrote on last edited by
                    #24

                    Fayu wrote:

                    I wish I can use the CLR but the requirements I have prevent me from using the CLR.

                    ::Throws up hands::

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                    • P PIEBALDconsult

                      Fayu wrote:

                      I wish I can use the CLR but the requirements I have prevent me from using the CLR.

                      ::Throws up hands::

                      F Offline
                      F Offline
                      Fayu
                      wrote on last edited by
                      #25

                      Yea but I am not using the clr. The pattern he provided worked with all requirement, including not using CLR. I used his pattern using VBScript.RegexExp and it worked wonders. Thanks for your help as well.

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                      • F Fayu

                        Yea but I am not using the clr. The pattern he provided worked with all requirement, including not using CLR. I used his pattern using VBScript.RegexExp and it worked wonders. Thanks for your help as well.

                        P Offline
                        P Offline
                        PIEBALDconsult
                        wrote on last edited by
                        #26

                        Mine works with perl: perl -e "print \"[[[MyProperty1]]] Value [[[MyProperty2]]] value2 [[[MyProperty3]]] value 3\" =~ m/(?:\[\[\[(?'Name'.*?)\]\]\](?'Value'[^\[]*))/g"

                        %stuff = $ARGV[0] =~ m/(?:\[\[\[(?'Name'.*?)\]\]\](?'Value'[^\[]*))/g ;

                        foreach $id ( sort ( keys ( %stuff ) ) )
                        {
                        print ( "$id = $stuff{$id}\n" ) ;
                        }

                        modified on Saturday, April 10, 2010 12:33 AM

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                        • P PIEBALDconsult

                          Mine works with perl: perl -e "print \"[[[MyProperty1]]] Value [[[MyProperty2]]] value2 [[[MyProperty3]]] value 3\" =~ m/(?:\[\[\[(?'Name'.*?)\]\]\](?'Value'[^\[]*))/g"

                          %stuff = $ARGV[0] =~ m/(?:\[\[\[(?'Name'.*?)\]\]\](?'Value'[^\[]*))/g ;

                          foreach $id ( sort ( keys ( %stuff ) ) )
                          {
                          print ( "$id = $stuff{$id}\n" ) ;
                          }

                          modified on Saturday, April 10, 2010 12:33 AM

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                          NavnathKale
                          wrote on last edited by
                          #27

                          Well i guess, all this confusion is because question is in wrong section. Perl supports Named capture groups but client scripts don't.

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                          • N NavnathKale

                            Well i guess, all this confusion is because question is in wrong section. Perl supports Named capture groups but client scripts don't.

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                            PIEBALDconsult
                            wrote on last edited by
                            #28

                            Navnath R. Kale wrote:

                            Named capture groups

                            You don't need to name them. The important thing is to have the engine return all the matches and enumerate them.

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                            • P PIEBALDconsult

                              Navnath R. Kale wrote:

                              Named capture groups

                              You don't need to name them. The important thing is to have the engine return all the matches and enumerate them.

                              N Offline
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                              NavnathKale
                              wrote on last edited by
                              #29

                              :doh: !!! Now the thread becomes the session. Actually (?'Name') and (?'Value') is equal to (?<Name>) and (?<Value>) and is nothing but Named capturing group. .Net supports it both way.

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                              • N NavnathKale

                                :doh: !!! Now the thread becomes the session. Actually (?'Name') and (?'Value') is equal to (?<Name>) and (?<Value>) and is nothing but Named capturing group. .Net supports it both way.

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                                PIEBALDconsult
                                wrote on last edited by
                                #30

                                Yes. I prefer the apostrophes -- at least I don't need to escape them when I post them. :-D

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                                • P PIEBALDconsult

                                  Yes. I prefer the apostrophes -- at least I don't need to escape them when I post them. :-D

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                                  NavnathKale
                                  wrote on last edited by
                                  #31

                                  Yeah :laugh: On first post I was like " :doh: WTF happened to my pattern, it was correct when I typed"

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