[Mathematics] Sum of angles of triangle [Updated]
-
By your own definition perhaps ;) Even if we would use your definition, it still would not be necessarily true. It is the corners that counts here. Whatever happens in other parts of the surface, even if looking only at "the space containing the triangle" does not affect the corner angles. So one can certainly design a surface which has an "average curvature" which is not zero, but which has an "average curvature" of zero if we only consider the three points of the corners. And that would give us a triangle with the angle sum of 180 degrees.
Actually, the vertices are irrelevant. What are important are the ANGLES, as that is what we are measuring. If the angles of a triangle add up to 180 degrees, then space containing the polygon has zero curvature, by the operative definitions of zero-curving space. Space elsewhere, away from the polygon, might have a different curvature, but that is also irrelevant.
-
We have learnt that sum of angles of a triangle is 180 degree. Now, 1, 3^1/2 and 2 form a triangle (based on the trigonometry). Since one cannot draw a line of length 3^1/2, this triangle is not possible which in turn means that sum of angles of a triangle is not 180 degree. Long ago, I had a read a book which stated that sum of angles of a triangle is not 180 degree (it was proven through a triangle formed by centers of three stars). I guess it was non Euclidean or something geometry. Anyone aware of this? And does anyone knows nice book where I can read more about that geometry? Edit: It is past midnight here. Time to sleep. Have a good time everyone.
This is a bit silly, really. You are equating your ability to draw a triangle with the validity of a Euclidean geometric rule! In Euclidean geometry the sum of the angles of a triangle MUST add up to 180 degrees. However, you can have other geometries where this is not true. For example, Lobachevsky created a geometry in which Euclid's 5th postulate (that for any given line and a point not on that line, there is one parallel line through the point not intersecting the line) was false, that is, there is more than one line that can be extended through any given point parallel to another line of which that point is not part. One of the consequences of this is that the sum of the angles of a triangle must be LESS than 180 degrees. This geometry was an idle curiosity for over 100 years until it was found to be useful in relativistic physics.
-
We have learnt that sum of angles of a triangle is 180 degree. Now, 1, 3^1/2 and 2 form a triangle (based on the trigonometry). Since one cannot draw a line of length 3^1/2, this triangle is not possible which in turn means that sum of angles of a triangle is not 180 degree. Long ago, I had a read a book which stated that sum of angles of a triangle is not 180 degree (it was proven through a triangle formed by centers of three stars). I guess it was non Euclidean or something geometry. Anyone aware of this? And does anyone knows nice book where I can read more about that geometry? Edit: It is past midnight here. Time to sleep. Have a good time everyone.
Hello, you can draw this line, and you stated how: - Draw two perpendicular lines. - Take your compass and open it some width; it defines a unit. - With your compass measure, from the intersection of the two lines, measure one unit right and two units up. - Link the two resultant points with a line. This line measures SQRT(3). So you can effectively draw this line. Sum of angles of a triangle is 180 degree, yes, in an Euclidean geometry (plane geometry). But in other geometries this sum can be bigger, take this example: - Take the sphere as the surface of this geometry. - A "straight line" is the line that joins two points with the minimum length, in this case is a circle of maximum length. Over the sphere there are no paralel lines. - Consider the triangle defined by: the North Pole, the Ecuador at meridian 0, and the Ecuador at meridian 90. In this triangle all three angles measure 90 degrees. I cannot recommend you any bibliography, I'm not an expert on Geometry. But some articles about non-Euclidean Geometry in Wikipedia could be a good start in this theme. Regards, Francesc
-
Actually, the vertices are irrelevant. What are important are the ANGLES, as that is what we are measuring. If the angles of a triangle add up to 180 degrees, then space containing the polygon has zero curvature, by the operative definitions of zero-curving space. Space elsewhere, away from the polygon, might have a different curvature, but that is also irrelevant.
> If the angles of a triangle add up to 180 degrees, then space > containing the polygon has zero curvature, by the operative > definitions of zero-curving space. From where are you getting all these strange definitions? Are you just making them up on the fly to fit your original claim or? Perhaps you should qoute your sources, if you have any. In a flat space, the sum of the squares of the sides of a right angled triangle is equal to the square of the hypotenuse. This relationship does not hold for curved spaces. This means that if this is true for any right angled triangle in a given surface, then it is a flat space. If not, then it is a curved space. From this follows that a triangle in a curved space might have an angle sum of 180 degrees. You are making the mistake of saying that all birds are crows. When only the reverse is true, all crows are birds. Magnus
modified on Friday, April 16, 2010 7:05 AM
-
Hello, you can draw this line, and you stated how: - Draw two perpendicular lines. - Take your compass and open it some width; it defines a unit. - With your compass measure, from the intersection of the two lines, measure one unit right and two units up. - Link the two resultant points with a line. This line measures SQRT(3). So you can effectively draw this line. Sum of angles of a triangle is 180 degree, yes, in an Euclidean geometry (plane geometry). But in other geometries this sum can be bigger, take this example: - Take the sphere as the surface of this geometry. - A "straight line" is the line that joins two points with the minimum length, in this case is a circle of maximum length. Over the sphere there are no paralel lines. - Consider the triangle defined by: the North Pole, the Ecuador at meridian 0, and the Ecuador at meridian 90. In this triangle all three angles measure 90 degrees. I cannot recommend you any bibliography, I'm not an expert on Geometry. But some articles about non-Euclidean Geometry in Wikipedia could be a good start in this theme. Regards, Francesc
Oops, of course, if one side is 1 and other side is 2 the hypotenuse measures SQRT(5), not SQRT(3). But there is not a problem; you can construct a triangle with sides 1 and SQRT(2) at the 90 degrees angle, and the hypotenuse will measure SQRT(3). Francesc
-
We have learnt that sum of angles of a triangle is 180 degree. Now, 1, 3^1/2 and 2 form a triangle (based on the trigonometry). Since one cannot draw a line of length 3^1/2, this triangle is not possible which in turn means that sum of angles of a triangle is not 180 degree. Long ago, I had a read a book which stated that sum of angles of a triangle is not 180 degree (it was proven through a triangle formed by centers of three stars). I guess it was non Euclidean or something geometry. Anyone aware of this? And does anyone knows nice book where I can read more about that geometry? Edit: It is past midnight here. Time to sleep. Have a good time everyone.
I assume 1, 3^1/2 and 2 are the lengths of the sides of the triangle and that you are using the Pythagorean theorem where a^2 + b^2 = c^2, The 3^1/2 (or SQRT(3))term seems fishy. If I were to let a = 1 and b = 2, then a^2 + b^2 = 1 + 4 = 5 = c^2. Then the third side should be 5^1/2 or SQRT(5). Would this help solve the question?
-
Well since the square-root of 3 is a non-finite number, no you couldn't draw the line. Hence the figure drawn would not be a triangle at all since the two lines would never meet and the figure would not be closed. Ergo, the "point" were one side "doesn't meet" with the 3^1/2 side has no angle.
ahmed zahmed wrote:
Well since the square-root of 3 is a non-finite number, no you couldn't draw the line.
Sorry for my lateness to the conversation, but by that logic I couldn't draw a circle that has a integral radius.
-
We have learnt that sum of angles of a triangle is 180 degree. Now, 1, 3^1/2 and 2 form a triangle (based on the trigonometry). Since one cannot draw a line of length 3^1/2, this triangle is not possible which in turn means that sum of angles of a triangle is not 180 degree. Long ago, I had a read a book which stated that sum of angles of a triangle is not 180 degree (it was proven through a triangle formed by centers of three stars). I guess it was non Euclidean or something geometry. Anyone aware of this? And does anyone knows nice book where I can read more about that geometry? Edit: It is past midnight here. Time to sleep. Have a good time everyone.
-
We have learnt that sum of angles of a triangle is 180 degree. Now, 1, 3^1/2 and 2 form a triangle (based on the trigonometry). Since one cannot draw a line of length 3^1/2, this triangle is not possible which in turn means that sum of angles of a triangle is not 180 degree. Long ago, I had a read a book which stated that sum of angles of a triangle is not 180 degree (it was proven through a triangle formed by centers of three stars). I guess it was non Euclidean or something geometry. Anyone aware of this? And does anyone knows nice book where I can read more about that geometry? Edit: It is past midnight here. Time to sleep. Have a good time everyone.
Let me ad my 2 cents into how to draw line with length SQRT(3) units. 1. Draw square rectangle with sides equal to 1 unit. 2. Draw any diagonal of that rectangle. Accordingly to Pythagorean theorem length of diagonal will be SQRT(1^2 + 1^2) = SQRT(2) units. See http://en.wikipedia.org/wiki/Square\_root\_of\_2 Notice that we just draw line with length measured as irrational number SQRT(2) units. 3. Draw perpendicular with length 1 unit to the one end of the above diagonal. You can do it by using caliper. 4. Draw line from another end of diagonal to the free end of above perpendicular. Accordingly to Pythagorean theorem length of this line will be SQRT(SQRT(2)^2 + 1^2) = SQRT(3) units. Therefore, we draw line with length measured as irrational number SQRT(3) units. We also can do it using caliper and drawing circle and hexagon. See http://en.wikipedia.org/wiki/Square\_root\_of\_3
-
Wikipedia Square root of 3 The square root of 3 is the positive real number that, when multiplied by itself, gives the number 3. It is denoted by The first sixty significant digits of its decimal expansion are: * 1.73205 08075 68877 29352 74463 41505 87236 69428 05253 81038 06280 5580... (sequence A002194 in OEIS) The rounded value of 1.732 is correct to within 0.01% of the actual value. The square root of 3 is an irrational number. It is also known as Theodorus' constant, named after Theodorus of Cyrene. It can be expressed as the continued fraction [1; 1, 2, 1, 2, 1, 2, ...] (sequence A040001 in OEIS). If you can draw a line of 1 unit accurately to .01% of the actual value, I have a job for you :laugh:
ChrisBraum wrote:
If you can draw a line of 1 unit accurately to .01% of the actual value, I have a job for you
I don't do nude portraits, sorry.