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  4. Adding Attributes to XML node using VBA

Adding Attributes to XML node using VBA

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xmlhelp
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  • D DaveAuld
    1. can you edit your message and put the code in a code block with an attribute lang="vb", so it formats something more readable! 2) Do not user On Error Resume Next, how else will you trap problems Change to On Error Goto ERROR_HANDLER, then at the end of the function put;

    ' Return the HTML string...
    fGenerateXML = strXML
    Exit Function

    ERROR_HANDLER:

    MSGBOX "Error: " & Err.description

    End Function

    1. You are doing far too much in the single function, split it up into smaller helper functions, one to create nodes, one to add attributes etc. It will be easier to program and follow. Dave Don't forget to rate messages!
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    priyaahh
    wrote on last edited by
    #9

    Hi Dave, Ya sure I will split this function. I wanted to add attribute which i have posted in my first post to the tags highlighted in bold. Appreaciate u lot..pls help..its urgent..

    Function fGenerateXML(rngData As Range, rootNodeName As String, sn As Integer, ts As Integer) As String
    On Error Resume Next
    '===============================================================
    ' XML Tags
    ' Table

    Const HEADER As String = "<?xml version=""1.0""?>"
    Dim TAG_BEGIN As String
    Dim TAG_END As String
    'Dim strTAG_END As String
    Const NODE_DELIMITER As String = "/"

    '===============================================================

    Dim intColCount As Integer
    Dim intRowCount As Integer
    Dim intColCounter As Integer
    Dim intRowCounter As Integer

    Dim rngCell As Range

    Dim strXML As String
    'Dim str As String
    'str = ""
    'strTAG_END = ""

    ' Initial table tag...
    Dim rNode() As String
    rNode = Split(rootNodeName, NODE_DELIMITER)

    If sn = 0 Then
    TAG_BEGIN = vbCrLf & "<" & rNode(0) & ">" & vbCrLf & "<" & rNode(1) & ">"
    Else
    TAG_BEGIN = vbCrLf & "<" & rNode(1) & ">" & vbCrLf
    End If

    'determining if it is final sheet for concatenation
    If sn = ts Then
    TAG_END = vbCrLf & "</" & rNode(1) & ">" & vbCrLf & "</" & rNode(0) & ">"
    Else
    TAG_END = vbCrLf & "</" & rNode(1) & ">" & vbCrLf
    End If

    'TAG_BEGIN = vbCrLf & "<" & rootNodeName & ">" & vbCrLf
    'TAG_END = vbCrLf & "</" & rootNodeName & ">" & vbCrLf

    If sn = 0 Then
    strXML = HEADER
    End If
    strXML = strXML & TAG_BEGIN

    With rngData

    ' Discover dimensions of the data we
    ' will be dealing with...
    intColCount = .Columns.Count

    intRowCount = .Rows.Count

    Dim strColNames() As String

    ReDim strColNames(intColCount)

    ' First Row is the Field/Tag names
    If intRowCount >= 1 Then

    ' Loop accross columns...
    For intColCounter = 1 To intColCount

    ' Mark the cell under current scrutiny by setting
    ' an object variable...
    Set rngCell = .Cells(1, intColCounter)

    ' Is the cell merged?..
    If Not rngCell.MergeArea.Address = _
    rngCell.Address Then

    MsgBox ("!! Cell Merged ... Invalid format")
    Exit Function

    End If

    'Sangeetha
    strColNames(intColCounter) = rngCell.Text

    'loop thro the sheets for header
    If rNode(1) = "Actual_Loss_History" Or rNode(1) = "As_If_Loss_History" Then

    If strColNames(intColCounter) = "Policy Years

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    • P priyaahh

      Hi Dave, Ya sure I will split this function. I wanted to add attribute which i have posted in my first post to the tags highlighted in bold. Appreaciate u lot..pls help..its urgent..

      Function fGenerateXML(rngData As Range, rootNodeName As String, sn As Integer, ts As Integer) As String
      On Error Resume Next
      '===============================================================
      ' XML Tags
      ' Table

      Const HEADER As String = "<?xml version=""1.0""?>"
      Dim TAG_BEGIN As String
      Dim TAG_END As String
      'Dim strTAG_END As String
      Const NODE_DELIMITER As String = "/"

      '===============================================================

      Dim intColCount As Integer
      Dim intRowCount As Integer
      Dim intColCounter As Integer
      Dim intRowCounter As Integer

      Dim rngCell As Range

      Dim strXML As String
      'Dim str As String
      'str = ""
      'strTAG_END = ""

      ' Initial table tag...
      Dim rNode() As String
      rNode = Split(rootNodeName, NODE_DELIMITER)

      If sn = 0 Then
      TAG_BEGIN = vbCrLf & "<" & rNode(0) & ">" & vbCrLf & "<" & rNode(1) & ">"
      Else
      TAG_BEGIN = vbCrLf & "<" & rNode(1) & ">" & vbCrLf
      End If

      'determining if it is final sheet for concatenation
      If sn = ts Then
      TAG_END = vbCrLf & "</" & rNode(1) & ">" & vbCrLf & "</" & rNode(0) & ">"
      Else
      TAG_END = vbCrLf & "</" & rNode(1) & ">" & vbCrLf
      End If

      'TAG_BEGIN = vbCrLf & "<" & rootNodeName & ">" & vbCrLf
      'TAG_END = vbCrLf & "</" & rootNodeName & ">" & vbCrLf

      If sn = 0 Then
      strXML = HEADER
      End If
      strXML = strXML & TAG_BEGIN

      With rngData

      ' Discover dimensions of the data we
      ' will be dealing with...
      intColCount = .Columns.Count

      intRowCount = .Rows.Count

      Dim strColNames() As String

      ReDim strColNames(intColCount)

      ' First Row is the Field/Tag names
      If intRowCount >= 1 Then

      ' Loop accross columns...
      For intColCounter = 1 To intColCount

      ' Mark the cell under current scrutiny by setting
      ' an object variable...
      Set rngCell = .Cells(1, intColCounter)

      ' Is the cell merged?..
      If Not rngCell.MergeArea.Address = _
      rngCell.Address Then

      MsgBox ("!! Cell Merged ... Invalid format")
      Exit Function

      End If

      'Sangeetha
      strColNames(intColCounter) = rngCell.Text

      'loop thro the sheets for header
      If rNode(1) = "Actual_Loss_History" Or rNode(1) = "As_If_Loss_History" Then

      If strColNames(intColCounter) = "Policy Years

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      DaveAuld
      wrote on last edited by
      #10

      You have some wierdness going on around your arrays, either i am missing something or your code is wrong, here are all the NodeStack references; Line 141: Dim NodeStack() as String Line 168: ReDim NodeStack(0) Line 229:

      For i = 1 To UBound(Nodes)
      If i <= UBound(NodeStack) Then
      If Trim(Nodes(i)) <> Trim(NodeStack(i)) Then
      'not match
      'MsgBox (Nodes(i) & "," & NodeStack(i))
      MatchAll = False
      Exit For
      End If
      Else
      MatchAll = False
      Exit For
      End If
      Next

      Up until this point NodeStack does not contain any values, it is a completly empty array, but yet you are trying to compare values etc from it. It is not until later in your code that you give it any values by NodeStack = Nodes, and that is only if Nodes does actually contain values. I suspect your code is throwing exceptions, but because you current On Error Resume Next you are not seeing them.

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      • D DaveAuld

        You have some wierdness going on around your arrays, either i am missing something or your code is wrong, here are all the NodeStack references; Line 141: Dim NodeStack() as String Line 168: ReDim NodeStack(0) Line 229:

        For i = 1 To UBound(Nodes)
        If i <= UBound(NodeStack) Then
        If Trim(Nodes(i)) <> Trim(NodeStack(i)) Then
        'not match
        'MsgBox (Nodes(i) & "," & NodeStack(i))
        MatchAll = False
        Exit For
        End If
        Else
        MatchAll = False
        Exit For
        End If
        Next

        Up until this point NodeStack does not contain any values, it is a completly empty array, but yet you are trying to compare values etc from it. It is not until later in your code that you give it any values by NodeStack = Nodes, and that is only if Nodes does actually contain values. I suspect your code is throwing exceptions, but because you current On Error Resume Next you are not seeing them.

        Dave Don't forget to rate messages!
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        priyaahh
        wrote on last edited by
        #11

        Hi, Code is working fine. I tried by removing on error resume next. Problem is that if i add attribute to that tags which is like Attribute="1,1,1,..." then it is giving error. I am not sure the way to keep the attributes there. Or is there any way after generation of an xml, can we open that xml file and add attributes to that? Regards, Priya.

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        • P priyaahh

          Hi, Code is working fine. I tried by removing on error resume next. Problem is that if i add attribute to that tags which is like Attribute="1,1,1,..." then it is giving error. I am not sure the way to keep the attributes there. Or is there any way after generation of an xml, can we open that xml file and add attributes to that? Regards, Priya.

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          DaveAuld
          wrote on last edited by
          #12

          I had a think about what i had written, and no it won't throw an excpetion, All that will happen is MatchAll will always be False so that code is effectively doing nothing (because 1 or higher is always greater than 0). All you are doing is generating a bunch of strings and bolting them altogether. After you generate the xml and the function exits, have you had a look at the XML file to see what it looks like?

          Dave Don't forget to rate messages!
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          • D DaveAuld

            I had a think about what i had written, and no it won't throw an excpetion, All that will happen is MatchAll will always be False so that code is effectively doing nothing (because 1 or higher is always greater than 0). All you are doing is generating a bunch of strings and bolting them altogether. After you generate the xml and the function exits, have you had a look at the XML file to see what it looks like?

            Dave Don't forget to rate messages!
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            priyaahh
            wrote on last edited by
            #13

            Hi Dave, Thanks. Yes XML looks good. Regards, Priya.

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            • P priyaahh

              Hi Dave, Thanks. Yes XML looks good. Regards, Priya.

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              DaveAuld
              wrote on last edited by
              #14

              In that case all you are doing now then is adding the attributes to the node. Create a helper function like; getNodeAttributes(node as integer) as string In it, test node to see which attributes you need to build, then return them in the function, if the node does not need any attributes, then return an empty string. Then modify; strXML = strXML & "<" & Nodes(t) & ">" to strXML = strXML & "<" & Nodes(t) & getNodeAttributes(t) & ">" simples........

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              • D DaveAuld

                In that case all you are doing now then is adding the attributes to the node. Create a helper function like; getNodeAttributes(node as integer) as string In it, test node to see which attributes you need to build, then return them in the function, if the node does not need any attributes, then return an empty string. Then modify; strXML = strXML & "<" & Nodes(t) & ">" to strXML = strXML & "<" & Nodes(t) & getNodeAttributes(t) & ">" simples........

                Dave Don't forget to rate messages!
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                priyaahh
                wrote on last edited by
                #15

                Hi Dave, Thanks lot. I tried adding the funtion like :

                Function getNodeAttributes(node As String) As String
                Dim str_att As String
                If node = "Policy_Years" Then
                str_att = "Attribute=" & "1,1,0,1,16711680,2,0,0,1,16711680,0,0,0,0,0,0.5,10,Arial,1"" Attribute2="""
                End If
                End Function

                and also changed

                strXML = strXML & "<" & Nodes(t) & getNodeAttributes(Nodes(t)) & ">"

                Just tried assigning attribute to only one node. But I am not getting any in the output for the tag Policy_Years. Please Help.. Regards, Priya.

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                • P priyaahh

                  Hi Dave, Thanks lot. I tried adding the funtion like :

                  Function getNodeAttributes(node As String) As String
                  Dim str_att As String
                  If node = "Policy_Years" Then
                  str_att = "Attribute=" & "1,1,0,1,16711680,2,0,0,1,16711680,0,0,0,0,0,0.5,10,Arial,1"" Attribute2="""
                  End If
                  End Function

                  and also changed

                  strXML = strXML & "<" & Nodes(t) & getNodeAttributes(Nodes(t)) & ">"

                  Just tried assigning attribute to only one node. But I am not getting any in the output for the tag Policy_Years. Please Help.. Regards, Priya.

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                  DaveAuld
                  wrote on last edited by
                  #16

                  Of course you wont, your passing across the node index not the node name;

                  priyaahh wrote:

                  strXML = strXML & "<" & Nodes(t) & getNodeAttributes(Nodes(t)) & ">"

                  change to; strXML = strXML & "<" & Nodes(t) & getNodeAttributes("Policy_Years") & ">"

                  Dave Don't forget to rate messages!
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                  • D DaveAuld

                    Of course you wont, your passing across the node index not the node name;

                    priyaahh wrote:

                    strXML = strXML & "<" & Nodes(t) & getNodeAttributes(Nodes(t)) & ">"

                    change to; strXML = strXML & "<" & Nodes(t) & getNodeAttributes("Policy_Years") & ">"

                    Dave Don't forget to rate messages!
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                    priyaahh
                    wrote on last edited by
                    #17

                    Hi Dave, Still no its not showing... :-( Is there any other way to implement this? Regards, Priya.

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                    • P priyaahh

                      Hi Dave, Still no its not showing... :-( Is there any other way to implement this? Regards, Priya.

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                      DaveAuld
                      wrote on last edited by
                      #18

                      Well i fail to see what you are doing wrong. Don't give in! At the end of the day, all you are doing is simple string manipulation, it doesn't matter if it is in XML format or any other text based format. If your output XML file shows the attributes after your text generation then it is working. If your output does not show the attributes, then your code is wrong. You maybe need to start putting in extra breakpoints, debug.print(), or message boxes statements through your code until you can find out what is going on. everytime you generate a node or an attribute use these statements to see what the string is before and after. That way you will be able to see what you are getting versus what you are expecting at each stage. This is basic troubleshooting. As i have stated before your function is way to big, and you really need to restructure and break out lots of smaller helper functions which can then be called to piece the final text XML string. As i say, this is basic string manipulation, so something obvious is wrong somewhere!

                      Dave Don't forget to rate messages!
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                      • D DaveAuld

                        Well i fail to see what you are doing wrong. Don't give in! At the end of the day, all you are doing is simple string manipulation, it doesn't matter if it is in XML format or any other text based format. If your output XML file shows the attributes after your text generation then it is working. If your output does not show the attributes, then your code is wrong. You maybe need to start putting in extra breakpoints, debug.print(), or message boxes statements through your code until you can find out what is going on. everytime you generate a node or an attribute use these statements to see what the string is before and after. That way you will be able to see what you are getting versus what you are expecting at each stage. This is basic troubleshooting. As i have stated before your function is way to big, and you really need to restructure and break out lots of smaller helper functions which can then be called to piece the final text XML string. As i say, this is basic string manipulation, so something obvious is wrong somewhere!

                        Dave Don't forget to rate messages!
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                        priyaahh
                        wrote on last edited by
                        #19

                        Hi Dave, Thanks really!... I am planning another way. TO open the xml file generated and then adding attributes to elements. If you dont mind can you please give me example for this. Yes i remember, you have sent me the reference to DOM Methods for implementing this. But at this point of time with so much stress i cannt think of anything and this have to completed asap i do not have even hours of time...pls pls help.. Thanks in advance..reply if ur online Regards, Priya

                        D 1 Reply Last reply
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                        • P priyaahh

                          Hi Dave, Thanks really!... I am planning another way. TO open the xml file generated and then adding attributes to elements. If you dont mind can you please give me example for this. Yes i remember, you have sent me the reference to DOM Methods for implementing this. But at this point of time with so much stress i cannt think of anything and this have to completed asap i do not have even hours of time...pls pls help.. Thanks in advance..reply if ur online Regards, Priya

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                          DaveAuld
                          wrote on last edited by
                          #20

                          No that is not the way to go, you are making things harder for your self, you will then have to read, parse, inject , save strings. You have already got a function that generates a valid XML file, so you are 99% of the way there. Have you done what i have suggested with regards to breakpoints and or debug statements? strategically place them in your code, and you will see where the attributes you have added are then disappearing (if they are disappearing at all that is). Also, in the previous message did you replace both instances of the code where you inject the attribute function? you have 2 lines that do it depending on the state of some value. Did you please a debug statement in your attribute function to prove it is being called? Did you add a debug.print statement to see what it was adding to the string?

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                          • D DaveAuld

                            No that is not the way to go, you are making things harder for your self, you will then have to read, parse, inject , save strings. You have already got a function that generates a valid XML file, so you are 99% of the way there. Have you done what i have suggested with regards to breakpoints and or debug statements? strategically place them in your code, and you will see where the attributes you have added are then disappearing (if they are disappearing at all that is). Also, in the previous message did you replace both instances of the code where you inject the attribute function? you have 2 lines that do it depending on the state of some value. Did you please a debug statement in your attribute function to prove it is being called? Did you add a debug.print statement to see what it was adding to the string?

                            Dave Don't forget to rate messages!
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                            priyaahh
                            wrote on last edited by
                            #21

                            Dave, <pre attribute="vb"> Yes I did debut and breakpoints. Actually I have to keep getNodeAttribute function in the first set not in the second set. I examined that. During call of the above function i print the var in immediate window. it is printing like : Attribute=1,1,0,1,16711680,2,0,0,1,16711680,0,0,0,0,0,0.5,10,Arial,1" Attribute2=" but when it go back to the main line from where are calling the function it is not returning anything.. Hope u might got my explanation..pls help This is my function: Function getNodeAttributes(node As String) As String dim str_att as string If node = "Policy_Years" Then str_att = "Attribute=" & "1,1,0,1,16711680,2,0,0,1,16711680,0,0,0,0,0,0.5,10,Arial,1"" Attribute2=""" ElseIf node = "Loss_Descriptions" Then str_att = "Attribute=" & "1,1,0,1,16711680,2,0,0,1,16711680,0,0,0,0,0,0.5,10,Arial,1"" Attribute2=""" Debug.Print str_att End If End Function Calling the above function from the below line: strXML = strXML & "<" & Nodes(t) & getNodeAttributes(Nodes(t)) & ">" I wanted output like: <Adjusted_Loss_PD Attribute="1,1,0,1,16711680,2,0,0,1,16711680,0,0,0,0,0,0.5,10,Arial,1" Attribute2=""> <Adjusted_Loss_PD-1 /> <Adjusted_Loss_PD-2 /> <Adjusted_Loss_PD-3 /> <Adjusted_Loss_PD-4 /> <Adjusted_Loss_PD-5 /> <Adjusted_Loss_PD-6 /> <Adjusted_Loss_PD-7 /> <Adjusted_Loss_PD-8 /> <Adjusted_Loss_PD-9 /> <Adjusted_Loss_PD-10 /> </Adjusted_Loss_PD> </pre>

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                            • P priyaahh

                              Dave, <pre attribute="vb"> Yes I did debut and breakpoints. Actually I have to keep getNodeAttribute function in the first set not in the second set. I examined that. During call of the above function i print the var in immediate window. it is printing like : Attribute=1,1,0,1,16711680,2,0,0,1,16711680,0,0,0,0,0,0.5,10,Arial,1" Attribute2=" but when it go back to the main line from where are calling the function it is not returning anything.. Hope u might got my explanation..pls help This is my function: Function getNodeAttributes(node As String) As String dim str_att as string If node = "Policy_Years" Then str_att = "Attribute=" & "1,1,0,1,16711680,2,0,0,1,16711680,0,0,0,0,0,0.5,10,Arial,1"" Attribute2=""" ElseIf node = "Loss_Descriptions" Then str_att = "Attribute=" & "1,1,0,1,16711680,2,0,0,1,16711680,0,0,0,0,0,0.5,10,Arial,1"" Attribute2=""" Debug.Print str_att End If End Function Calling the above function from the below line: strXML = strXML & "<" & Nodes(t) & getNodeAttributes(Nodes(t)) & ">" I wanted output like: <Adjusted_Loss_PD Attribute="1,1,0,1,16711680,2,0,0,1,16711680,0,0,0,0,0,0.5,10,Arial,1" Attribute2=""> <Adjusted_Loss_PD-1 /> <Adjusted_Loss_PD-2 /> <Adjusted_Loss_PD-3 /> <Adjusted_Loss_PD-4 /> <Adjusted_Loss_PD-5 /> <Adjusted_Loss_PD-6 /> <Adjusted_Loss_PD-7 /> <Adjusted_Loss_PD-8 /> <Adjusted_Loss_PD-9 /> <Adjusted_Loss_PD-10 /> </Adjusted_Loss_PD> </pre>

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                              DaveAuld
                              wrote on last edited by
                              #22

                              It looks like you are missing quotes from the output string. As you already know, you have to increase the number of quotes if you want to add quotes to the output, you are only doing this in some of your code.

                              priyaahh wrote:

                              str_att = "Attribute=" & "1,1,0,1,16711680,2,0,0,1,16711680,0,0,0,0,0,0.5,10,Arial,1"" Attribute2="""

                              Look at the code after "Attribute=" the opening value only has a single double quote, which will result in Attribute=1,1,....etc. and not Attribute="1,1,...etc. yet at the end you correctly add the extra quotes. you can always consider user Char(34) in you string generator so you can see where you want to add the quote to the output e.g. (34 is the ASCII value for a double quote, look at asciitable[^]) str_Att = "Attribute1=" & chr(34) & "1,1,0,1,16711680,2,0,0,1,16711680,0,0,0,0,0,0.5,10,Arial,1" & chr(34) & " Attribute2=" & chr(34) & "some value" & chr(34)

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                              • D DaveAuld

                                It looks like you are missing quotes from the output string. As you already know, you have to increase the number of quotes if you want to add quotes to the output, you are only doing this in some of your code.

                                priyaahh wrote:

                                str_att = "Attribute=" & "1,1,0,1,16711680,2,0,0,1,16711680,0,0,0,0,0,0.5,10,Arial,1"" Attribute2="""

                                Look at the code after "Attribute=" the opening value only has a single double quote, which will result in Attribute=1,1,....etc. and not Attribute="1,1,...etc. yet at the end you correctly add the extra quotes. you can always consider user Char(34) in you string generator so you can see where you want to add the quote to the output e.g. (34 is the ASCII value for a double quote, look at asciitable[^]) str_Att = "Attribute1=" & chr(34) & "1,1,0,1,16711680,2,0,0,1,16711680,0,0,0,0,0,0.5,10,Arial,1" & chr(34) & " Attribute2=" & chr(34) & "some value" & chr(34)

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                                priyaahh
                                wrote on last edited by
                                #23

                                Hi Dave, Yes I have noticed that and changed...but why the function is not returning anything. Regards, Priya.

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                                • P priyaahh

                                  Hi Dave, Yes I have noticed that and changed...but why the function is not returning anything. Regards, Priya.

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                                  DaveAuld
                                  wrote on last edited by
                                  #24

                                  Because you haven't returned a value yet! remember you need to set the function name to the value you want to return;

                                  Function getNodeAttributes(node As String) As String

                                  'Do whatever you need

                                  'Return the output to the caller
                                  getNodeAttributes = str_att

                                  End Function

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                                  • D DaveAuld

                                    It looks like you are missing quotes from the output string. As you already know, you have to increase the number of quotes if you want to add quotes to the output, you are only doing this in some of your code.

                                    priyaahh wrote:

                                    str_att = "Attribute=" & "1,1,0,1,16711680,2,0,0,1,16711680,0,0,0,0,0,0.5,10,Arial,1"" Attribute2="""

                                    Look at the code after "Attribute=" the opening value only has a single double quote, which will result in Attribute=1,1,....etc. and not Attribute="1,1,...etc. yet at the end you correctly add the extra quotes. you can always consider user Char(34) in you string generator so you can see where you want to add the quote to the output e.g. (34 is the ASCII value for a double quote, look at asciitable[^]) str_Att = "Attribute1=" & chr(34) & "1,1,0,1,16711680,2,0,0,1,16711680,0,0,0,0,0,0.5,10,Arial,1" & chr(34) & " Attribute2=" & chr(34) & "some value" & chr(34)

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                                    priyaahh
                                    wrote on last edited by
                                    #25

                                    Hi Dave, Thank you so much for ur kind and immediate reply...it worked. :-) Regards, Priya.

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