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BUG in Windows Calc [modified]

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  • H Hiren solanki

    Follow the procedure click '4' click 'sqrt' click '-'(Minus sign) click '2' Answer should be 0 But It comes back with '-8.1648465955514287168521180122928e-39' answer ;P [Edit] Tested with XP and Seven _[/More Edit] Windows Server 2008 R2 comes same with yet another answer '-1.068281969439142e-19' _[/More Edit] [/Edit]

    Rating is Always appreciated.
    Regards,
    Hiren Solanki.
    Indian Forum | My Articles | My Profile


    "You will always find me near 127.0.0.1"

    modified on Monday, November 1, 2010 7:00 AM

    E Offline
    E Offline
    ErikKnowles
    wrote on last edited by
    #39

    Oh geez, this is *not* a bug. Do you have *any* idea of how floating point math is performed? Internal vs. reported precision? You're a programmer??? I'm gobsmacked that this got posted to a code developer site. Oh, and you made CodeProject's daily e-mail, so your ignorance has been transmitted worldwide. Epic fail.

    modified on Tuesday, November 2, 2010 4:35 PM

    D 1 Reply Last reply
    0
    • K Keith Barrow

      Sheesh, it's about right, whaddaya want, accuracy :-)

      Sort of a cross between Lawrence of Arabia and Dilbert.[^]

      O Offline
      O Offline
      oconnellc
      wrote on last edited by
      #40

      Actually, it is accurate. Its problem is that it is *too* precise. If it was a little less precise, it would have decided that it was close enough to zero to just display zero.

      J 1 Reply Last reply
      0
      • H Hiren solanki

        Follow the procedure click '4' click 'sqrt' click '-'(Minus sign) click '2' Answer should be 0 But It comes back with '-8.1648465955514287168521180122928e-39' answer ;P [Edit] Tested with XP and Seven _[/More Edit] Windows Server 2008 R2 comes same with yet another answer '-1.068281969439142e-19' _[/More Edit] [/Edit]

        Rating is Always appreciated.
        Regards,
        Hiren Solanki.
        Indian Forum | My Articles | My Profile


        "You will always find me near 127.0.0.1"

        modified on Monday, November 1, 2010 7:00 AM

        B Offline
        B Offline
        bwallan
        wrote on last edited by
        #41

        Interesting BUT the Scientific view doesn't have a "sqrt" key; however, the x^y gives the same BUG... bwa

        1 Reply Last reply
        0
        • H Hiren solanki

          Follow the procedure click '4' click 'sqrt' click '-'(Minus sign) click '2' Answer should be 0 But It comes back with '-8.1648465955514287168521180122928e-39' answer ;P [Edit] Tested with XP and Seven _[/More Edit] Windows Server 2008 R2 comes same with yet another answer '-1.068281969439142e-19' _[/More Edit] [/Edit]

          Rating is Always appreciated.
          Regards,
          Hiren Solanki.
          Indian Forum | My Articles | My Profile


          "You will always find me near 127.0.0.1"

          modified on Monday, November 1, 2010 7:00 AM

          P Offline
          P Offline
          Plamen Dragiyski
          wrote on last edited by
          #42

          Woooow, I always use scientific calc in XP and I didn't know it is support sqrt... it seems that they forget to add that button into scientific dialog :laugh:

          1 Reply Last reply
          0
          • O oconnellc

            Actually, it is accurate. Its problem is that it is *too* precise. If it was a little less precise, it would have decided that it was close enough to zero to just display zero.

            J Offline
            J Offline
            Jake Barney
            wrote on last edited by
            #43

            In this particular instance any answer other than -4 or 0 is inaccurate. Doesn't matter that most of us understand that anything ^-39 power is so small as to be considered zero by most, it's still not zero. Understandably the answer they factored was 1.9999...8164whatever but its funny that the calculator rounded up, then 'forgot' that it did so. Sounds like sloppy programming. What's really funny is change it to the scientific calculator, do 4^.5 power then -2 and it gives a different answer.

            1 Reply Last reply
            0
            • H Hiren solanki

              Follow the procedure click '4' click 'sqrt' click '-'(Minus sign) click '2' Answer should be 0 But It comes back with '-8.1648465955514287168521180122928e-39' answer ;P [Edit] Tested with XP and Seven _[/More Edit] Windows Server 2008 R2 comes same with yet another answer '-1.068281969439142e-19' _[/More Edit] [/Edit]

              Rating is Always appreciated.
              Regards,
              Hiren Solanki.
              Indian Forum | My Articles | My Profile


              "You will always find me near 127.0.0.1"

              modified on Monday, November 1, 2010 7:00 AM

              S Offline
              S Offline
              Sasa Cetkovic
              wrote on last edited by
              #44

              On Windows Server 2008 R2 it gives the first answer in scientific mode, and the second in standard mode.

              1 Reply Last reply
              0
              • H Hiren solanki

                Follow the procedure click '4' click 'sqrt' click '-'(Minus sign) click '2' Answer should be 0 But It comes back with '-8.1648465955514287168521180122928e-39' answer ;P [Edit] Tested with XP and Seven _[/More Edit] Windows Server 2008 R2 comes same with yet another answer '-1.068281969439142e-19' _[/More Edit] [/Edit]

                Rating is Always appreciated.
                Regards,
                Hiren Solanki.
                Indian Forum | My Articles | My Profile


                "You will always find me near 127.0.0.1"

                modified on Monday, November 1, 2010 7:00 AM

                D Offline
                D Offline
                David C Thompson
                wrote on last edited by
                #45

                It works (well, the bug works) with any number. I tried sqrt(25) - 5 and sqrt(9) - :^)

                1 Reply Last reply
                0
                • E ErikKnowles

                  Oh geez, this is *not* a bug. Do you have *any* idea of how floating point math is performed? Internal vs. reported precision? You're a programmer??? I'm gobsmacked that this got posted to a code developer site. Oh, and you made CodeProject's daily e-mail, so your ignorance has been transmitted worldwide. Epic fail.

                  modified on Tuesday, November 2, 2010 4:35 PM

                  D Offline
                  D Offline
                  David C Thompson
                  wrote on last edited by
                  #46

                  Can you enlighten those of us who may not be as well-informed as you?

                  1 Reply Last reply
                  0
                  • H Hiren solanki

                    Follow the procedure click '4' click 'sqrt' click '-'(Minus sign) click '2' Answer should be 0 But It comes back with '-8.1648465955514287168521180122928e-39' answer ;P [Edit] Tested with XP and Seven _[/More Edit] Windows Server 2008 R2 comes same with yet another answer '-1.068281969439142e-19' _[/More Edit] [/Edit]

                    Rating is Always appreciated.
                    Regards,
                    Hiren Solanki.
                    Indian Forum | My Articles | My Profile


                    "You will always find me near 127.0.0.1"

                    modified on Monday, November 1, 2010 7:00 AM

                    C Offline
                    C Offline
                    Caslen
                    wrote on last edited by
                    #47

                    For all you Numptys who this this is a bug - you can easily prove that it isn't, follow these simple steps:- 1. Convert the number 4 to a binary floating point representation and write it down. 2. Continue with your pen and paper and using a suitably selected algorithm to calculate the square root of a number presented in binary floating point form work out the square root of the binary floating point representation of the number 4 found in step 1. 3. Convert the number 2 into a binary floating point form (preferably the same form as that used in step 1) 4. Perform a floating point binary subtract on the result of step 3 from the result of step 4. 5. Do you have zero? No you do not!

                    N T 2 Replies Last reply
                    0
                    • P peterchen

                      Actually, Calc internals have been replaced (around XP) with a long numbers library, so it is somehow noteworthy that this isn't enough. OTOH, the OP failed to notice tha 8e-39 is zero enough when playing around with square roots of 2.

                      Agh! Reality! My Archnemesis![^]
                      | FoldWithUs! | sighist | WhoIncludes - Analyzing C++ include file hierarchy

                      M Offline
                      M Offline
                      Michael Kingsford Gray
                      wrote on last edited by
                      #48

                      It needs to do it like HP calculators have always done.

                      P 1 Reply Last reply
                      0
                      • M Michael Kingsford Gray

                        It needs to do it like HP calculators have always done.

                        P Offline
                        P Offline
                        peterchen
                        wrote on last edited by
                        #49

                        How did they?

                        Agh! Reality! My Archnemesis![^]
                        | FoldWithUs! | sighist | WhoIncludes - Analyzing C++ include file hierarchy

                        M 1 Reply Last reply
                        0
                        • C Caslen

                          For all you Numptys who this this is a bug - you can easily prove that it isn't, follow these simple steps:- 1. Convert the number 4 to a binary floating point representation and write it down. 2. Continue with your pen and paper and using a suitably selected algorithm to calculate the square root of a number presented in binary floating point form work out the square root of the binary floating point representation of the number 4 found in step 1. 3. Convert the number 2 into a binary floating point form (preferably the same form as that used in step 1) 4. Perform a floating point binary subtract on the result of step 3 from the result of step 4. 5. Do you have zero? No you do not!

                          N Offline
                          N Offline
                          NPowDev
                          wrote on last edited by
                          #50

                          However, I thing it hould work in Calc, and fp-precision is not an excuse! I don't have the time to write a .NET application, but... Just a litle test in PowerShell:

                          PS > write-host ([Math]::Sqrt(4) - 2)
                          0
                          PS > write-host ([Math]::Sqrt(4.0) - 2.0)
                          0
                          PS > write-host ([Math]::Sqrt([double]4.0) - [double]2.0)
                          0
                          PS > write-host ([Math]::Sqrt([single]4.0) - [single]2.0)
                          0
                          PS > write-host ([Math]::Sqrt([decimal]4.0) - [decimal]2.0)
                          0

                          also to get sure that it is not a convertion issue:

                          PS > write-host ([Math]::Sqrt([decimal]4.0) - [decimal]2.0).toString("g")
                          0
                          PS > write-host ([Math]::Sqrt([decimal]4.0) - [decimal]2.0).toString("n")
                          0.00
                          PS > write-host ([Math]::Sqrt([decimal]4.0) - [decimal]2.0).toString("E")
                          0.000000E+000
                          PS > write-host ([Math]::Sqrt([decimal]4.0) - [decimal]2.0).toString("G17")
                          0
                          PS > write-host ([Math]::Sqrt([decimal]4.0) - [decimal]2.0).toString("G")
                          0
                          PS > write-host ([Math]::Sqrt([decimal]4.0) - [decimal]2.0).toString("n")
                          0.00
                          PS > write-host ([Math]::Sqrt([decimal]4.0) - [decimal]2.0).toString("n5")
                          0.00000
                          PS > write-host ([Math]::Sqrt([decimal]4.0) - [decimal]2.0).toString("n17")
                          0.00000000000000000
                          PS > write-host ([Math]::Sqrt([decimal]4.0) - [decimal]2.0).toString("n57")
                          0.000000000000000000000000000000000000000000000000000000000
                          PS > write-host ([Math]::Sqrt([decimal]4.0) - [decimal]2.0).toString("f57")
                          0.000000000000000000000000000000000000000000000000000000000
                          PS > write-host ([Math]::Sqrt([single]4.0) - [single]2.0).toString("f55")
                          0,0000000000000000000000000000000000000000000000000000000
                          PS > write-host ([Math]::Sqrt([single]4.0) - [single]2.0).toString("f155")
                          f155
                          PS > write-host ([Math]::Sqrt([single]4.0) - [single]2.0).toString("f95")
                          0.00000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000
                          PS > write-host ([Math]::Sqrt([single]4.0) - [single]2.0).toString("f99")
                          0.000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000
                          PS > write-host ([Math]::Sqrt([single]4.0) - [single]2.0).toString("n99")
                          0.000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000
                          PS > write-host ([Math]::Sqrt([single]4.0) - [single]2.0).toString("e99")
                          0.00000000000000000000000000000000000000000000000000000000000

                          Well... it's a M$ Numpyts! :-D

                          C 1 Reply Last reply
                          0
                          • N NPowDev

                            However, I thing it hould work in Calc, and fp-precision is not an excuse! I don't have the time to write a .NET application, but... Just a litle test in PowerShell:

                            PS > write-host ([Math]::Sqrt(4) - 2)
                            0
                            PS > write-host ([Math]::Sqrt(4.0) - 2.0)
                            0
                            PS > write-host ([Math]::Sqrt([double]4.0) - [double]2.0)
                            0
                            PS > write-host ([Math]::Sqrt([single]4.0) - [single]2.0)
                            0
                            PS > write-host ([Math]::Sqrt([decimal]4.0) - [decimal]2.0)
                            0

                            also to get sure that it is not a convertion issue:

                            PS > write-host ([Math]::Sqrt([decimal]4.0) - [decimal]2.0).toString("g")
                            0
                            PS > write-host ([Math]::Sqrt([decimal]4.0) - [decimal]2.0).toString("n")
                            0.00
                            PS > write-host ([Math]::Sqrt([decimal]4.0) - [decimal]2.0).toString("E")
                            0.000000E+000
                            PS > write-host ([Math]::Sqrt([decimal]4.0) - [decimal]2.0).toString("G17")
                            0
                            PS > write-host ([Math]::Sqrt([decimal]4.0) - [decimal]2.0).toString("G")
                            0
                            PS > write-host ([Math]::Sqrt([decimal]4.0) - [decimal]2.0).toString("n")
                            0.00
                            PS > write-host ([Math]::Sqrt([decimal]4.0) - [decimal]2.0).toString("n5")
                            0.00000
                            PS > write-host ([Math]::Sqrt([decimal]4.0) - [decimal]2.0).toString("n17")
                            0.00000000000000000
                            PS > write-host ([Math]::Sqrt([decimal]4.0) - [decimal]2.0).toString("n57")
                            0.000000000000000000000000000000000000000000000000000000000
                            PS > write-host ([Math]::Sqrt([decimal]4.0) - [decimal]2.0).toString("f57")
                            0.000000000000000000000000000000000000000000000000000000000
                            PS > write-host ([Math]::Sqrt([single]4.0) - [single]2.0).toString("f55")
                            0,0000000000000000000000000000000000000000000000000000000
                            PS > write-host ([Math]::Sqrt([single]4.0) - [single]2.0).toString("f155")
                            f155
                            PS > write-host ([Math]::Sqrt([single]4.0) - [single]2.0).toString("f95")
                            0.00000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000
                            PS > write-host ([Math]::Sqrt([single]4.0) - [single]2.0).toString("f99")
                            0.000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000
                            PS > write-host ([Math]::Sqrt([single]4.0) - [single]2.0).toString("n99")
                            0.000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000
                            PS > write-host ([Math]::Sqrt([single]4.0) - [single]2.0).toString("e99")
                            0.00000000000000000000000000000000000000000000000000000000000

                            Well... it's a M$ Numpyts! :-D

                            C Offline
                            C Offline
                            Caslen
                            wrote on last edited by
                            #51

                            Not quite sure what this proves but I hope you had fun doing it! :laugh:

                            N 1 Reply Last reply
                            0
                            • A Abhinav S

                              Yup confirmed - happening on Windows 7.

                              The funniest thing about this particular signature is that by the time you realise it doesn't say anything it's too late to stop reading it. My latest tip/trick Visit the Hindi forum here.

                              J Offline
                              J Offline
                              Juan Pablo G C
                              wrote on last edited by
                              #52

                              Ja ja, in W2K8 the same -8,1648465955514287168521180122928e-39 :) I think someone forgot clear the stack

                              Juan Pablo G.C. Overrider Blog

                              1 Reply Last reply
                              0
                              • C Caslen

                                For all you Numptys who this this is a bug - you can easily prove that it isn't, follow these simple steps:- 1. Convert the number 4 to a binary floating point representation and write it down. 2. Continue with your pen and paper and using a suitably selected algorithm to calculate the square root of a number presented in binary floating point form work out the square root of the binary floating point representation of the number 4 found in step 1. 3. Convert the number 2 into a binary floating point form (preferably the same form as that used in step 1) 4. Perform a floating point binary subtract on the result of step 3 from the result of step 4. 5. Do you have zero? No you do not!

                                T Offline
                                T Offline
                                Trajan McGill
                                wrote on last edited by
                                #53

                                I think you miss the point. A user calculator working in decimal shouldn't be wrong in decimal. And it certainly shouldn't be "right" and then become "wrong" again. If sqrt(4) is not actually calculated to be 2, then it shouldn't be shown as that. "2-2 != 0" is mathematically false, even when converted to binary representation. If the internal representation of "braking" in your electric car's computer worked by subtracting integer amounts from your velocity, and thus you could never (unless you were really, really lucky about when you hit the brake) actually come to a stop, but your car instead slowed way down and then vibrated intensely forward and backward as long as you held the brake pedal, you would not conclude "this is not a bug, it happens because of the way braking is represented internally". You would conclude that the internal representation was inappropriate for the task-- that we should make the car work with the human meaning of "braking", not conform ourselves to the sloppy approximation.

                                C 1 Reply Last reply
                                0
                                • T Trajan McGill

                                  I think you miss the point. A user calculator working in decimal shouldn't be wrong in decimal. And it certainly shouldn't be "right" and then become "wrong" again. If sqrt(4) is not actually calculated to be 2, then it shouldn't be shown as that. "2-2 != 0" is mathematically false, even when converted to binary representation. If the internal representation of "braking" in your electric car's computer worked by subtracting integer amounts from your velocity, and thus you could never (unless you were really, really lucky about when you hit the brake) actually come to a stop, but your car instead slowed way down and then vibrated intensely forward and backward as long as you held the brake pedal, you would not conclude "this is not a bug, it happens because of the way braking is represented internally". You would conclude that the internal representation was inappropriate for the task-- that we should make the car work with the human meaning of "braking", not conform ourselves to the sloppy approximation.

                                  C Offline
                                  C Offline
                                  Caslen
                                  wrote on last edited by
                                  #54

                                  I think maybe you missed the point:- 1. Did you not get the sarcasm? Oh hang on your American you wouldn't. 2. I don't really care whether it's logically right or wrong the fact is its wrong but because of a rounding error NOT a bug and that error is so small that here in the real world where I live it will never matter. But apart from that I did enjoy your little story even if it did have no bearing whatsover on the point in hand :)

                                  T J 2 Replies Last reply
                                  0
                                  • C Caslen

                                    I think maybe you missed the point:- 1. Did you not get the sarcasm? Oh hang on your American you wouldn't. 2. I don't really care whether it's logically right or wrong the fact is its wrong but because of a rounding error NOT a bug and that error is so small that here in the real world where I live it will never matter. But apart from that I did enjoy your little story even if it did have no bearing whatsover on the point in hand :)

                                    T Offline
                                    T Offline
                                    Trajan McGill
                                    wrote on last edited by
                                    #55

                                    I see. So you're saying: 1. This was sarcasm, but you took me seriously. Haha stupid American. 2. I was serious. Are you sure you have a proper definition of what "sarcasm" means? Because I'm pretty sure points 1 and 2 are mutually exclusive. Furthermore, "this is a rounding error, not a bug?" Well, at least now I know where all those amazing and beautiful "this is by design" bug responses come from. If a thing presents itself as a decimal calculator, and the responses it gives to decimal calculations are mathematically incorrect, then there is a bug. You can't say it isn't a bug just because the bug happens to be "we relied on an underlying implementation that doesn't work for the task". And by the way, in the real world, the difference between zero and nonzero is often very, very important to computer programs.

                                    C 1 Reply Last reply
                                    0
                                    • L leppie

                                      Another fails the knowledge about floating point.... When will they ever learn????? Edit: It seems to happen with any rounding around 0. If your result is not 0, the result is correctly rounded, but with values very near 0, it simply 'forgets'.... Edit 2: Press = again, the answer will be -2 as expected confirming the previous value is not rounded correctly, but still good enough due to its 'smallness' (e-39 is very small).

                                      ((λ (x) `(,x ',x)) '(λ (x) `(,x ',x)))

                                      modified on Monday, November 1, 2010 7:07 AM

                                      E Offline
                                      E Offline
                                      Earl Truss
                                      wrote on last edited by
                                      #56

                                      Exactly ... The following works correctly in XP. click '4' click x^y click .5 click = click Int click '-'(Minus sign) click '2' Without using the Int function the result is the same as for the original poster.

                                      1 Reply Last reply
                                      0
                                      • P peterchen

                                        How did they?

                                        Agh! Reality! My Archnemesis![^]
                                        | FoldWithUs! | sighist | WhoIncludes - Analyzing C++ include file hierarchy

                                        M Offline
                                        M Offline
                                        Michael Kingsford Gray
                                        wrote on last edited by
                                        #57

                                        Do everything in high precision normalised BCD instead of IEEE binary floating point types.

                                        1 Reply Last reply
                                        0
                                        • C Caslen

                                          I think maybe you missed the point:- 1. Did you not get the sarcasm? Oh hang on your American you wouldn't. 2. I don't really care whether it's logically right or wrong the fact is its wrong but because of a rounding error NOT a bug and that error is so small that here in the real world where I live it will never matter. But apart from that I did enjoy your little story even if it did have no bearing whatsover on the point in hand :)

                                          J Offline
                                          J Offline
                                          Jake Barney
                                          wrote on last edited by
                                          #58

                                          "I don't really care whether it's logically right or wrong the fact is its wrong but because of a rounding error NOT a bug and that error is so small that here in the real world where I live it will never matter." So if it isn't a bug, (the code being correct), where does the rounding error come from? Must be those damn wood elves fiddling with my computer again. Sounds like a pre-scripted response you came up with to throw off clients questioning your shoddy coding.

                                          C 1 Reply Last reply
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