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Job Application Test from Hell

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  • B Brady Kelly

    I'm not looking for an answer here, I found my own, but this is quite a hard question. Given the table from Fig.1, write an SQL Select statement that would re-organize the results to look like Fig.2 Fig. 1

    Region

    Contact

    Cape Town

    Fred

    CapeTown

    Joe

    Cape Town

    Anna

    Durban

    John

    Durban

    Mary

    Johannesburg

    Frank

    Fig. 2

    Region

    Contact

    Durban

    John

    Durban

    Mary

    Johannesburg

    Frank

    Cape Town

    Anna

    CapeTown

    Fred

    Cape Town

    Joe

    M Offline
    M Offline
    Member 96
    wrote on last edited by
    #55

    A job application test that doesn't reflect a real world problem is an utter waste of time and whoever devised this should be kicked in the balls and repeatedly told to "get real".


    “If you want to build a ship, don't drum up people together to collect wood and don't assign them tasks and work, but rather teach them to long for the endless immensity of the sea” - Antoine de Saint-Exupery

    B 1 Reply Last reply
    0
    • B Brady Kelly

      I'm not looking for an answer here, I found my own, but this is quite a hard question. Given the table from Fig.1, write an SQL Select statement that would re-organize the results to look like Fig.2 Fig. 1

      Region

      Contact

      Cape Town

      Fred

      CapeTown

      Joe

      Cape Town

      Anna

      Durban

      John

      Durban

      Mary

      Johannesburg

      Frank

      Fig. 2

      Region

      Contact

      Durban

      John

      Durban

      Mary

      Johannesburg

      Frank

      Cape Town

      Anna

      CapeTown

      Fred

      Cape Town

      Joe

      K Offline
      K Offline
      Kirk Wood
      wrote on last edited by
      #56

      SELECT 'look for different job' FROM 'places not full of self serving jerks who wish to prove their supposed superiority' Personally, my experience is that places that serve up such a test are full of jerks who think too highly of themselves. They find great pride in their ability to find questions few can answer, and probably can't produce anything worth having anyway. The number of people who think they are great far exceeds the number who really are great.

      1 Reply Last reply
      0
      • M Member 96

        A job application test that doesn't reflect a real world problem is an utter waste of time and whoever devised this should be kicked in the balls and repeatedly told to "get real".


        “If you want to build a ship, don't drum up people together to collect wood and don't assign them tasks and work, but rather teach them to long for the endless immensity of the sea” - Antoine de Saint-Exupery

        B Offline
        B Offline
        Brady Kelly
        wrote on last edited by
        #57

        Well, the one that did reflect a real world problem, probably the only one, was: Given a list of names, identify duplicate names as well as possible misspellings of the same name. I scrawled something about soundex in my answer. This was a written test taken after hours. I had nobody to raise issues with, but plenty of time to really think things through.

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        • C Christian Graus

          Yeah, I expect that's the main thing he was to glean from the question.

          Christian Graus Driven to the arms of OSX by Vista. Read my blog to find out how I've worked around bugs in Microsoft tools and frameworks.

          T Offline
          T Offline
          TraceyTiethoff
          wrote on last edited by
          #58

          That's a good point Christian. My answer would be in the form of a question asked with the general idea of "What exactly are you trying to accomplish?". I can't imagine a reason for this sort order, as someone else mentioned. Either the order is insignificant, the significance is merely that some user likes it, or the data provided isn't complete and therefore doesn't reveal any logical reason for this order. I know programmers are often stuck with "just do it", but if the customer is open to it, I would prefer to have a discussion of the cost(both present and future) versus the benefit of having it this way (assuming it isn't an incomplete data issue).

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          • C Christian Graus

            Is there any sense to that order ?

            Christian Graus Driven to the arms of OSX by Vista. Read my blog to find out how I've worked around bugs in Microsoft tools and frameworks.

            Z Offline
            Z Offline
            ZRonZ28
            wrote on last edited by
            #59

            Fig. 2 Region Contact Durban John Durban Mary Johannesburg Frank Cape Town Anna CapeTown Fred Cape Town Joe The pattern seems pretty simple: 1. Region is reverse alphabetized using the second letter of the word (or maybe 2,3 and 4?), 2. Contact is alphabetized within the Region.

            modified on Friday, November 26, 2010 10:50 AM

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            0
            • B Brady Kelly

              I'm not looking for an answer here, I found my own, but this is quite a hard question. Given the table from Fig.1, write an SQL Select statement that would re-organize the results to look like Fig.2 Fig. 1

              Region

              Contact

              Cape Town

              Fred

              CapeTown

              Joe

              Cape Town

              Anna

              Durban

              John

              Durban

              Mary

              Johannesburg

              Frank

              Fig. 2

              Region

              Contact

              Durban

              John

              Durban

              Mary

              Johannesburg

              Frank

              Cape Town

              Anna

              CapeTown

              Fred

              Cape Town

              Joe

              D Offline
              D Offline
              dada2010
              wrote on last edited by
              #60

              Haha, i think i found the hidden order... Region are simply ordered by descending their longitude, contacts by the length of their name (descending) then by their fourth letter (ascending). As we know commonly longitudes of theses cities/regions are Cape Town : 18.45° Durban : 30.6° Johannesburg : 27° For the understanding, we suppose we have a table containing longitudes (while in real life we would need -of course- the request to connect to googlemap api to find it) (googlemap find CapeTown and Cape Town same longitude): wtf_region_longitude region longitude Cape Town 18 CapeTown 18 Durban 31 Johannesburg 27 and the table of fig 1: wtf_region_contacts Region Contact Cape Town Fred Cape Town Joe Cape Town Anna Durban John Durban Mary Johannesburg Frank Doing permutation between Joe and Fred, the request is :

              select s.region, contact from
              (
              select c.region,
              contact = case contact when 'Joe' then 'Fred' when 'Fred' then 'Joe' else contact end
              ,contact as ocontact
              from wtf_region_contacts c
              ) s, wtf_region_longitude l
              where s.region=l.region
              order by longitude desc, LEN(contact) desc, SUBSTRING(contact,4,1) asc

              --> region contact Durban John Durban Mary Johannesburg Frank Cape Town Anna CapeTown Fred Cape Town Joe Am I right ?

              modified on Friday, November 26, 2010 4:30 AM

              B 1 Reply Last reply
              0
              • D dada2010

                Haha, i think i found the hidden order... Region are simply ordered by descending their longitude, contacts by the length of their name (descending) then by their fourth letter (ascending). As we know commonly longitudes of theses cities/regions are Cape Town : 18.45° Durban : 30.6° Johannesburg : 27° For the understanding, we suppose we have a table containing longitudes (while in real life we would need -of course- the request to connect to googlemap api to find it) (googlemap find CapeTown and Cape Town same longitude): wtf_region_longitude region longitude Cape Town 18 CapeTown 18 Durban 31 Johannesburg 27 and the table of fig 1: wtf_region_contacts Region Contact Cape Town Fred Cape Town Joe Cape Town Anna Durban John Durban Mary Johannesburg Frank Doing permutation between Joe and Fred, the request is :

                select s.region, contact from
                (
                select c.region,
                contact = case contact when 'Joe' then 'Fred' when 'Fred' then 'Joe' else contact end
                ,contact as ocontact
                from wtf_region_contacts c
                ) s, wtf_region_longitude l
                where s.region=l.region
                order by longitude desc, LEN(contact) desc, SUBSTRING(contact,4,1) asc

                --> region contact Durban John Durban Mary Johannesburg Frank Cape Town Anna CapeTown Fred Cape Town Joe Am I right ?

                modified on Friday, November 26, 2010 4:30 AM

                B Offline
                B Offline
                Brady Kelly
                wrote on last edited by
                #61

                I think your scenario is actually more likely than the real pattern being sorting by the second char of region.

                1 Reply Last reply
                0
                • B Brady Kelly

                  I'm not looking for an answer here, I found my own, but this is quite a hard question. Given the table from Fig.1, write an SQL Select statement that would re-organize the results to look like Fig.2 Fig. 1

                  Region

                  Contact

                  Cape Town

                  Fred

                  CapeTown

                  Joe

                  Cape Town

                  Anna

                  Durban

                  John

                  Durban

                  Mary

                  Johannesburg

                  Frank

                  Fig. 2

                  Region

                  Contact

                  Durban

                  John

                  Durban

                  Mary

                  Johannesburg

                  Frank

                  Cape Town

                  Anna

                  CapeTown

                  Fred

                  Cape Town

                  Joe

                  C Offline
                  C Offline
                  CodeNaked
                  wrote on last edited by
                  #62

                  Durban and Johannesburg are both divisible by 6.

                  SELECT * FROM Regions
                  ORDER BY
                  CASE LEN(Region) % 6
                  WHEN 0 THEN 0
                  ELSE ASCII(SUBSTRING(Contact,1,1)) END,
                  Region, Contact

                  Darwin

                  1 Reply Last reply
                  0
                  • B Brady Kelly

                    I'm not looking for an answer here, I found my own, but this is quite a hard question. Given the table from Fig.1, write an SQL Select statement that would re-organize the results to look like Fig.2 Fig. 1

                    Region

                    Contact

                    Cape Town

                    Fred

                    CapeTown

                    Joe

                    Cape Town

                    Anna

                    Durban

                    John

                    Durban

                    Mary

                    Johannesburg

                    Frank

                    Fig. 2

                    Region

                    Contact

                    Durban

                    John

                    Durban

                    Mary

                    Johannesburg

                    Frank

                    Cape Town

                    Anna

                    CapeTown

                    Fred

                    Cape Town

                    Joe

                    N Offline
                    N Offline
                    narfnarf13206
                    wrote on last edited by
                    #63

                    --There is no obvious sort in fig 2l; we have no specific req saying to order using a particular approach...so brute force order it. Obviously this solution wouldn't scale..then again any solution that makes an assumption that there is a scalable way to order it would only be correct by pure luck. Note - pseudocode, might have syntax errors but the basic methodology works select * from fig1 a into #temp01 --dump data into a temp table alter table #temp01 add orderr integer --add a new column update #temp01 set orderr = 1 where region = 'Durban' and Contact = 'John' --populate order info update #temp01 set orderr = 2 where region = 'Durban' and Contact = 'Mary' --populate order info --TODO update orderr for 4 remaining rows select region, contact from #temp01 order by orderr

                    1 Reply Last reply
                    0
                    • B Brady Kelly

                      I'm not looking for an answer here, I found my own, but this is quite a hard question. Given the table from Fig.1, write an SQL Select statement that would re-organize the results to look like Fig.2 Fig. 1

                      Region

                      Contact

                      Cape Town

                      Fred

                      CapeTown

                      Joe

                      Cape Town

                      Anna

                      Durban

                      John

                      Durban

                      Mary

                      Johannesburg

                      Frank

                      Fig. 2

                      Region

                      Contact

                      Durban

                      John

                      Durban

                      Mary

                      Johannesburg

                      Frank

                      Cape Town

                      Anna

                      CapeTown

                      Fred

                      Cape Town

                      Joe

                      R Offline
                      R Offline
                      redbones
                      wrote on last edited by
                      #64

                      in oracle sql i could do select region, contact from select region, contact, decode(substr(region,1,1),'D',1,'J',2, 'C',3) ord from ) order by ord

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