Observing Schrodinger's cat [modified]
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As the cat is an active observer inside the box, isn't the whole premise of the thought experiment flawed? On a related topic, in a QM collapsing-the-waveform sense, what does an "observation" mean? Does it mean an observation by an intelligence or just an interaction with another system? If the latter, then wouldn't "interaction" be a better description than "observation"? If the former, then how does the QM system being measured know that the interaction it is experiencing is an observation by an intelligence and not just a random interaction with a passing particle/wave? And finally, how much Scotch does it take to make yourself believe you understand this stuff? Edit: An interesting blog entry on this topic is here[^].
modified on Friday, July 22, 2011 10:52 AM
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As the cat is an active observer inside the box, isn't the whole premise of the thought experiment flawed? On a related topic, in a QM collapsing-the-waveform sense, what does an "observation" mean? Does it mean an observation by an intelligence or just an interaction with another system? If the latter, then wouldn't "interaction" be a better description than "observation"? If the former, then how does the QM system being measured know that the interaction it is experiencing is an observation by an intelligence and not just a random interaction with a passing particle/wave? And finally, how much Scotch does it take to make yourself believe you understand this stuff? Edit: An interesting blog entry on this topic is here[^].
modified on Friday, July 22, 2011 10:52 AM
Interactive always requires observation at one level or another. Therefore, interaction = observation. Beyond that, i think even casual use of
CListCtrlwill reveal the answer you seek.".45 ACP - because shooting twice is just silly" - JSOP, 2010
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You can never have too much ammo - unless you're swimming, or on fire. - JSOP, 2010
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"Why don't you tie a kerosene-soaked rag around your ankles so the ants won't climb up and eat your candy ass." - Dale Earnhardt, 1997 -
Interactive always requires observation at one level or another. Therefore, interaction = observation. Beyond that, i think even casual use of
CListCtrlwill reveal the answer you seek.".45 ACP - because shooting twice is just silly" - JSOP, 2010
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You can never have too much ammo - unless you're swimming, or on fire. - JSOP, 2010
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"Why don't you tie a kerosene-soaked rag around your ankles so the ants won't climb up and eat your candy ass." - Dale Earnhardt, 1997So if it wasn't observed, it never happed? That is so "tree falls..." if I never heard it.
It was broke, so I fixed it.
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As the cat is an active observer inside the box, isn't the whole premise of the thought experiment flawed? On a related topic, in a QM collapsing-the-waveform sense, what does an "observation" mean? Does it mean an observation by an intelligence or just an interaction with another system? If the latter, then wouldn't "interaction" be a better description than "observation"? If the former, then how does the QM system being measured know that the interaction it is experiencing is an observation by an intelligence and not just a random interaction with a passing particle/wave? And finally, how much Scotch does it take to make yourself believe you understand this stuff? Edit: An interesting blog entry on this topic is here[^].
modified on Friday, July 22, 2011 10:52 AM
Had another problem yesterday, that was slightly less obvious than this mornings. They had passed in 3 records, all of which had failed for no reason I could see. I turned on full monitoring and asked them to try again. It worked each time from then on. The e-mail I sent to the provider of the bought in system (we had both been trying to work out why things were failing) included the following; "At the moment I am completely stumped and the best I can come up with is that these are Schrodinger’s Work Orders and they exist in both a state of succeeded and failed until they are observed at which point they settle on one or the other. That may be a long shot though."
Every man can tell how many goats or sheep he possesses, but not how many friends.
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Interactive always requires observation at one level or another. Therefore, interaction = observation. Beyond that, i think even casual use of
CListCtrlwill reveal the answer you seek.".45 ACP - because shooting twice is just silly" - JSOP, 2010
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You can never have too much ammo - unless you're swimming, or on fire. - JSOP, 2010
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"Why don't you tie a kerosene-soaked rag around your ankles so the ants won't climb up and eat your candy ass." - Dale Earnhardt, 1997Two hydrogen atoms in the Oort cloud could interact without being observed (by an intelligence), but they cannot be observed without interacting with something (e.g. photons). If two
CListCtrls interact but no-one...no, I'm not going down that route. -
So if it wasn't observed, it never happed? That is so "tree falls..." if I never heard it.
It was broke, so I fixed it.
Based on what we know of trees, a tree does not grow wihtout a root system and pretty much any tree we see laying on its side has - of course - fallen. We don't have to see it fall to know that it fell. The question is whether or not the tree has fallen until we have observed that it has. If the tree falls and crushes you, even with your back to it, the tree has interacted with you in a number of ways before your untimely demise, via sound, the rush of forest animals trying to run past you to get out of the way of the falling tree, and finally the tree contacting your person. You have, in the end, interacted with the tree without observing it in the classical sense of "observation".
".45 ACP - because shooting twice is just silly" - JSOP, 2010
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You can never have too much ammo - unless you're swimming, or on fire. - JSOP, 2010
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"Why don't you tie a kerosene-soaked rag around your ankles so the ants won't climb up and eat your candy ass." - Dale Earnhardt, 1997modified on Friday, July 22, 2011 8:43 AM
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Based on what we know of trees, a tree does not grow wihtout a root system and pretty much any tree we see laying on its side has - of course - fallen. We don't have to see it fall to know that it fell. The question is whether or not the tree has fallen until we have observed that it has. If the tree falls and crushes you, even with your back to it, the tree has interacted with you in a number of ways before your untimely demise, via sound, the rush of forest animals trying to run past you to get out of the way of the falling tree, and finally the tree contacting your person. You have, in the end, interacted with the tree without observing it in the classical sense of "observation".
".45 ACP - because shooting twice is just silly" - JSOP, 2010
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You can never have too much ammo - unless you're swimming, or on fire. - JSOP, 2010
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"Why don't you tie a kerosene-soaked rag around your ankles so the ants won't climb up and eat your candy ass." - Dale Earnhardt, 1997modified on Friday, July 22, 2011 8:43 AM
Hang on. You hear the tree [observation], see the fleeing animals [observation] and finally feel it on your head [observation]. Three classic observations - hearing, seeing and touching. All you needed was the smell of leaf mold and the taste of dirt to get the set.
Panic, Chaos, Destruction. My work here is done. Drink. Get drunk. Fall over - P O'H OK, I will win to day or my name isn't Ethel Crudacre! - DD Ethel Crudacre I cannot live by bread alone. Bacon and ketchup are needed as well. - Trollslayer Have a bit more patience with newbies. Of course some of them act dumb - they're often *students*, for heaven's sake - Terry Pratchett
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Based on what we know of trees, a tree does not grow wihtout a root system and pretty much any tree we see laying on its side has - of course - fallen. We don't have to see it fall to know that it fell. The question is whether or not the tree has fallen until we have observed that it has. If the tree falls and crushes you, even with your back to it, the tree has interacted with you in a number of ways before your untimely demise, via sound, the rush of forest animals trying to run past you to get out of the way of the falling tree, and finally the tree contacting your person. You have, in the end, interacted with the tree without observing it in the classical sense of "observation".
".45 ACP - because shooting twice is just silly" - JSOP, 2010
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You can never have too much ammo - unless you're swimming, or on fire. - JSOP, 2010
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"Why don't you tie a kerosene-soaked rag around your ankles so the ants won't climb up and eat your candy ass." - Dale Earnhardt, 1997modified on Friday, July 22, 2011 8:43 AM
Your explaination is well put. :) My point exaclty! :thumbsup: Just because it wasn't observed, doesn't mean it didn't happen. Things happen all the time without being observed. Observation proves that stuff does happen and that observed reactions can be reasonably expected to occur again.
It was broke, so I fixed it.
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As the cat is an active observer inside the box, isn't the whole premise of the thought experiment flawed? On a related topic, in a QM collapsing-the-waveform sense, what does an "observation" mean? Does it mean an observation by an intelligence or just an interaction with another system? If the latter, then wouldn't "interaction" be a better description than "observation"? If the former, then how does the QM system being measured know that the interaction it is experiencing is an observation by an intelligence and not just a random interaction with a passing particle/wave? And finally, how much Scotch does it take to make yourself believe you understand this stuff? Edit: An interesting blog entry on this topic is here[^].
modified on Friday, July 22, 2011 10:52 AM
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As the cat is an active observer inside the box, isn't the whole premise of the thought experiment flawed? On a related topic, in a QM collapsing-the-waveform sense, what does an "observation" mean? Does it mean an observation by an intelligence or just an interaction with another system? If the latter, then wouldn't "interaction" be a better description than "observation"? If the former, then how does the QM system being measured know that the interaction it is experiencing is an observation by an intelligence and not just a random interaction with a passing particle/wave? And finally, how much Scotch does it take to make yourself believe you understand this stuff? Edit: An interesting blog entry on this topic is here[^].
modified on Friday, July 22, 2011 10:52 AM
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Based on what we know of trees, a tree does not grow wihtout a root system and pretty much any tree we see laying on its side has - of course - fallen. We don't have to see it fall to know that it fell. The question is whether or not the tree has fallen until we have observed that it has. If the tree falls and crushes you, even with your back to it, the tree has interacted with you in a number of ways before your untimely demise, via sound, the rush of forest animals trying to run past you to get out of the way of the falling tree, and finally the tree contacting your person. You have, in the end, interacted with the tree without observing it in the classical sense of "observation".
".45 ACP - because shooting twice is just silly" - JSOP, 2010
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You can never have too much ammo - unless you're swimming, or on fire. - JSOP, 2010
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"Why don't you tie a kerosene-soaked rag around your ankles so the ants won't climb up and eat your candy ass." - Dale Earnhardt, 1997modified on Friday, July 22, 2011 8:43 AM
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"Help I've fallen and I can't get up!" http://en.wikipedia.org/wiki/I've_fallen_and_I_can't_get_up![^]
It was broke, so I fixed it.
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As the cat is an active observer inside the box, isn't the whole premise of the thought experiment flawed? On a related topic, in a QM collapsing-the-waveform sense, what does an "observation" mean? Does it mean an observation by an intelligence or just an interaction with another system? If the latter, then wouldn't "interaction" be a better description than "observation"? If the former, then how does the QM system being measured know that the interaction it is experiencing is an observation by an intelligence and not just a random interaction with a passing particle/wave? And finally, how much Scotch does it take to make yourself believe you understand this stuff? Edit: An interesting blog entry on this topic is here[^].
modified on Friday, July 22, 2011 10:52 AM
viaducting wrote:
As the cat is an active observer inside the box, isn't the whole premise of the thought experiment flawed?
Your premise of Schroedinger's Cat experiment being flawed is in itself flawed. Schroedinger came up with the cat in the box idea to illustrate the incompleteness of - at the time - quantum mechanics theory. It was only through the act of observation upon the cat that would cause its state to be revealed; until the box was opened, the cat could either be: dead, alive or any state in between. The fact that the cat could observe itself wouldn't make any difference to its state or the outcome. In fact, if you read up on QM, it is the act of measurement that changes the state of what is being observed. This from wikipedia: "The best known is the "paradox" of the Schrödinger's cat: a cat is apparently evolving into a linear superposition of basis vectors that can be characterized as an "alive cat" and states that can be described as a "dead cat". Each of these possibilities is associated with a specific nonzero probability amplitude; the cat seems to be in a "mixed" state. However, a single, particular observation of the cat does not measure the probabilities: it always finds either a living cat, or a dead cat. After the measurement the cat is definitively alive or dead. The question is: How are the probabilities converted into an actual, sharply well-defined outcome?"
You do trust me, don't you? IF EVERY nation gets the leaders it deserves, what in God's name have we done to deserve Francis Urquhart?
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As the cat is an active observer inside the box, isn't the whole premise of the thought experiment flawed? On a related topic, in a QM collapsing-the-waveform sense, what does an "observation" mean? Does it mean an observation by an intelligence or just an interaction with another system? If the latter, then wouldn't "interaction" be a better description than "observation"? If the former, then how does the QM system being measured know that the interaction it is experiencing is an observation by an intelligence and not just a random interaction with a passing particle/wave? And finally, how much Scotch does it take to make yourself believe you understand this stuff? Edit: An interesting blog entry on this topic is here[^].
modified on Friday, July 22, 2011 10:52 AM
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As the cat is an active observer inside the box, isn't the whole premise of the thought experiment flawed? On a related topic, in a QM collapsing-the-waveform sense, what does an "observation" mean? Does it mean an observation by an intelligence or just an interaction with another system? If the latter, then wouldn't "interaction" be a better description than "observation"? If the former, then how does the QM system being measured know that the interaction it is experiencing is an observation by an intelligence and not just a random interaction with a passing particle/wave? And finally, how much Scotch does it take to make yourself believe you understand this stuff? Edit: An interesting blog entry on this topic is here[^].
modified on Friday, July 22, 2011 10:52 AM
As it is impossible for information to move from within the box, the fact that the cat knows whether it is dead or not is immaterial (to all but the cat). I think an observation can be classed as the exchange of information. So it doesn't matter if it is an intelligence or not - because if something is measurable it is measurable - whether is measured or not. The cat's state of health CANNOT (by definition) be determined by any observation from outside the box - because there is no transfer of information between the two systems. Anything inside the box "doesn't count" in this case, because we are talking about transfer of information specifically from within to outside of the box. Within the box, the state of health of the feline is known - whether the box contains only the cat, some decaying radioactivity and some poison, or contains the cat, a marching band and a pile of bell-bottom trousers.
viaducting wrote:
how much Scotch does it take to make yourself believe you understand this stuff?
Looking at the bottle (most of which is within my system, and therefore measurable by me), I'd say about a third of a 750ml bottle, plus a couple of pints of Guinness.
MVVM# - See how I did MVVM my way ___________________________________________ Man, you're a god. - walterhevedeich 26/05/2011 .\\axxx (That's an 'M')
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Based on what we know of trees, a tree does not grow wihtout a root system and pretty much any tree we see laying on its side has - of course - fallen. We don't have to see it fall to know that it fell. The question is whether or not the tree has fallen until we have observed that it has. If the tree falls and crushes you, even with your back to it, the tree has interacted with you in a number of ways before your untimely demise, via sound, the rush of forest animals trying to run past you to get out of the way of the falling tree, and finally the tree contacting your person. You have, in the end, interacted with the tree without observing it in the classical sense of "observation".
".45 ACP - because shooting twice is just silly" - JSOP, 2010
-----
You can never have too much ammo - unless you're swimming, or on fire. - JSOP, 2010
-----
"Why don't you tie a kerosene-soaked rag around your ankles so the ants won't climb up and eat your candy ass." - Dale Earnhardt, 1997modified on Friday, July 22, 2011 8:43 AM
One word: chainsaw.
Software Zen:
delete this; -
As the cat is an active observer inside the box, isn't the whole premise of the thought experiment flawed? On a related topic, in a QM collapsing-the-waveform sense, what does an "observation" mean? Does it mean an observation by an intelligence or just an interaction with another system? If the latter, then wouldn't "interaction" be a better description than "observation"? If the former, then how does the QM system being measured know that the interaction it is experiencing is an observation by an intelligence and not just a random interaction with a passing particle/wave? And finally, how much Scotch does it take to make yourself believe you understand this stuff? Edit: An interesting blog entry on this topic is here[^].
modified on Friday, July 22, 2011 10:52 AM
Schrodinger was an idiot. No self-respecting cat would have allowed itself to be placed in a box, so his reasoning is obviously flawed.
Software Zen:
delete this; -
As it is impossible for information to move from within the box, the fact that the cat knows whether it is dead or not is immaterial (to all but the cat). I think an observation can be classed as the exchange of information. So it doesn't matter if it is an intelligence or not - because if something is measurable it is measurable - whether is measured or not. The cat's state of health CANNOT (by definition) be determined by any observation from outside the box - because there is no transfer of information between the two systems. Anything inside the box "doesn't count" in this case, because we are talking about transfer of information specifically from within to outside of the box. Within the box, the state of health of the feline is known - whether the box contains only the cat, some decaying radioactivity and some poison, or contains the cat, a marching band and a pile of bell-bottom trousers.
viaducting wrote:
how much Scotch does it take to make yourself believe you understand this stuff?
Looking at the bottle (most of which is within my system, and therefore measurable by me), I'd say about a third of a 750ml bottle, plus a couple of pints of Guinness.
MVVM# - See how I did MVVM my way ___________________________________________ Man, you're a god. - walterhevedeich 26/05/2011 .\\axxx (That's an 'M')
_Maxxx_ wrote:
the fact that the cat knows whether it is dead or not
Can something know it is dead? Surely it can only know it is not dead. Or at least suspect that it is not dead. That's my problem with death, not knowing. I'd hate to die and not be aware of the fact.
Every man can tell how many goats or sheep he possesses, but not how many friends.
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How many times did you observe that outcome, and was it statistically significant?
Pete
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As it is impossible for information to move from within the box, the fact that the cat knows whether it is dead or not is immaterial (to all but the cat). I think an observation can be classed as the exchange of information. So it doesn't matter if it is an intelligence or not - because if something is measurable it is measurable - whether is measured or not. The cat's state of health CANNOT (by definition) be determined by any observation from outside the box - because there is no transfer of information between the two systems. Anything inside the box "doesn't count" in this case, because we are talking about transfer of information specifically from within to outside of the box. Within the box, the state of health of the feline is known - whether the box contains only the cat, some decaying radioactivity and some poison, or contains the cat, a marching band and a pile of bell-bottom trousers.
viaducting wrote:
how much Scotch does it take to make yourself believe you understand this stuff?
Looking at the bottle (most of which is within my system, and therefore measurable by me), I'd say about a third of a 750ml bottle, plus a couple of pints of Guinness.
MVVM# - See how I did MVVM my way ___________________________________________ Man, you're a god. - walterhevedeich 26/05/2011 .\\axxx (That's an 'M')
_Maxxx_ wrote:
As it is impossible for information to move from within the box, the fact that the cat knows whether it is dead or not is immaterial
I disagree. The waveform collapses upon being observed, it doesn't matter whether or not the observer is outside or inside the box. The cat "observed" the radioactive decay by inhaling the poison and dying, therefore the waveform has collapsed to a definite state of dead. Whether or not the external observer knows which state the cat is in doesn't mean that the cat itself is in an indefinite state, it is the observer who is uncertain.