Coding Challenge
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Hey Chris, may I post my own programming issue labeling it with 'Coding Challenge' or 'Fun For Everyone'? Just Kidding! Sorry for my poor understanding of English, with
Chris Maunder wrote:
from either end
Do you mean the output string should be:
" monkey dog horse "
?
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke
[My articles] -
You can think it means whatever you want, but in correct English usage either can mean both 'one of two' or 'each of two.
Every man can tell how many goats or sheep he possesses, but not how many friends.
Schrodinger's cat was either alive or dead, but not both. ;)
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Back in the Days of Yore we had a couple of small coding challenges such as the Lean and Mean comp. I was thinking that there are a ton of small, well defined problems that can be tackled a zillion ways in a zillion languages and that it would be cool to see what you guys can come up with. I'd like to start the ball rolling with the following simple task: Problem: Given a string of text, trim from each end of the text each all occurrences of a given set of strings Sample input: Input string: "dog cat monkey dog horse dog" Strings that need to be trimmed from each end: { "dog", "cat" } Final output should be: " monkey dog horse" Final output should be " cat monkey dog horse " [Edit: My final sample output was incorrect, so to be fair I'll accept either answer] It's up to you whether you worry about case sensitivity. Let's see who can provide the smallest, neatest most elegant, most unique and/or fastest code. For those who feel like jumping on the "No Programming questions" bandwagon, please re-read the lounge guidelines. The point of this is to have fun, not to solve each other's programming issues.
cheers, Chris Maunder The Code Project | Co-founder Microsoft C++ MVP
Hmmmm, 2 KISS algorithms A two pass algorithm might be: 1.) Tokenize the string using white space characters. 2.) Moving from left to right, push the string into a deque if the string is not in the excluded list. If we encounter a string that is included, all proceeding tags are pushed into the deque. 3.) Then do the same from right to left. A single pass algorithm might be: 1.) Tokenize the string using white space characters. 2.) Push all tags into a pair of string:index 3.) For each pair of string and index, if the string is excluded... if the index value of all other string:index pairs before me are also excluded... My index is the beginning of the string. 4.) For each pair of string and index, if the string is excluded... if the index value of all other string:index pairs after me are also excluded... My index is the end of the string. :) I'm too lazy to write the code. Btw, I think the single pass algorithm could be implemented in a single lambda line of code. Best Wishes, -David Delaune
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Schrodinger's cat was either alive or dead, but not both. ;)
It thought it was both alive and dead until you had a look in the box at which point it became alive or dead. A bit late but still; Erwin Schrödinger has sent us a Christmas present. The kids are going to be delighted or distraught on Christmas Day.
Every man can tell how many goats or sheep he possesses, but not how many friends.
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Back in the Days of Yore we had a couple of small coding challenges such as the Lean and Mean comp. I was thinking that there are a ton of small, well defined problems that can be tackled a zillion ways in a zillion languages and that it would be cool to see what you guys can come up with. I'd like to start the ball rolling with the following simple task: Problem: Given a string of text, trim from each end of the text each all occurrences of a given set of strings Sample input: Input string: "dog cat monkey dog horse dog" Strings that need to be trimmed from each end: { "dog", "cat" } Final output should be: " monkey dog horse" Final output should be " cat monkey dog horse " [Edit: My final sample output was incorrect, so to be fair I'll accept either answer] It's up to you whether you worry about case sensitivity. Let's see who can provide the smallest, neatest most elegant, most unique and/or fastest code. For those who feel like jumping on the "No Programming questions" bandwagon, please re-read the lounge guidelines. The point of this is to have fun, not to solve each other's programming issues.
cheers, Chris Maunder The Code Project | Co-founder Microsoft C++ MVP
// Well, this is my piece (C#): static void main(string[] args) { string Input = "doc cat monkey dog horse dog"; List listDeleteStart = new List(); List ListDeleteEnd = new List (); //Output = " monkey dog horse " string[] toTrim = new string[] {"dog", "cat"}; string[] InputStrip = Input.Split(new char[] {' '}); int iCounter = 0; //Going forwards foreach(string strSingle in InputString) { if(toTrim.Contains(strSingle)) ListDeleteStart.Add(iCounter); else break; iCounter++; } //Going backwards InputString = InputString.Reverse().ToArray(); iCounter = InputString.Length-1; foreach(string strSingleRev in InputString) { if(toTrim.Contains(strSingleRev)) ListDeleteStart.Add(iCounter); else break; iCounter--; } //Putting it back again for analysis InputString = InputString.Reverse().ToArray(); string Output = ""; iCounter = 0; foreach (string strResult in InputString) { if(!listDeleteStart.Contains(iCounter) && !listDeletedEnd.Contains(iCounter)) Output+= " " + strResult + " "; iCounter++; } Console.WriteLine(Output); Console.ReadKey(); }
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Hmmmm, 2 KISS algorithms A two pass algorithm might be: 1.) Tokenize the string using white space characters. 2.) Moving from left to right, push the string into a deque if the string is not in the excluded list. If we encounter a string that is included, all proceeding tags are pushed into the deque. 3.) Then do the same from right to left. A single pass algorithm might be: 1.) Tokenize the string using white space characters. 2.) Push all tags into a pair of string:index 3.) For each pair of string and index, if the string is excluded... if the index value of all other string:index pairs before me are also excluded... My index is the beginning of the string. 4.) For each pair of string and index, if the string is excluded... if the index value of all other string:index pairs after me are also excluded... My index is the end of the string. :) I'm too lazy to write the code. Btw, I think the single pass algorithm could be implemented in a single lambda line of code. Best Wishes, -David Delaune
Randor wrote:
Tokenize the string using white space characters.
is that a valid assumption? dogcathorsefoodcat
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It thought it was both alive and dead until you had a look in the box at which point it became alive or dead. A bit late but still; Erwin Schrödinger has sent us a Christmas present. The kids are going to be delighted or distraught on Christmas Day.
Every man can tell how many goats or sheep he possesses, but not how many friends.
Not "either alive and dead"? ;) In any case, the cat is itself an observer, so the waveform is always collapsed to a known state or "alive" or "dead", so it's a silly thought experiment (IMHO).
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Hmmmm, 2 KISS algorithms A two pass algorithm might be: 1.) Tokenize the string using white space characters. 2.) Moving from left to right, push the string into a deque if the string is not in the excluded list. If we encounter a string that is included, all proceeding tags are pushed into the deque. 3.) Then do the same from right to left. A single pass algorithm might be: 1.) Tokenize the string using white space characters. 2.) Push all tags into a pair of string:index 3.) For each pair of string and index, if the string is excluded... if the index value of all other string:index pairs before me are also excluded... My index is the beginning of the string. 4.) For each pair of string and index, if the string is excluded... if the index value of all other string:index pairs after me are also excluded... My index is the end of the string. :) I'm too lazy to write the code. Btw, I think the single pass algorithm could be implemented in a single lambda line of code. Best Wishes, -David Delaune
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Back in the Days of Yore we had a couple of small coding challenges such as the Lean and Mean comp. I was thinking that there are a ton of small, well defined problems that can be tackled a zillion ways in a zillion languages and that it would be cool to see what you guys can come up with. I'd like to start the ball rolling with the following simple task: Problem: Given a string of text, trim from each end of the text each all occurrences of a given set of strings Sample input: Input string: "dog cat monkey dog horse dog" Strings that need to be trimmed from each end: { "dog", "cat" } Final output should be: " monkey dog horse" Final output should be " cat monkey dog horse " [Edit: My final sample output was incorrect, so to be fair I'll accept either answer] It's up to you whether you worry about case sensitivity. Let's see who can provide the smallest, neatest most elegant, most unique and/or fastest code. For those who feel like jumping on the "No Programming questions" bandwagon, please re-read the lounge guidelines. The point of this is to have fun, not to solve each other's programming issues.
cheers, Chris Maunder The Code Project | Co-founder Microsoft C++ MVP
Quote:
Quote:text each all occurrences of a given set of strings
I think final output should be "Final output should be: " monkey horse ".
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Hmmmm, 2 KISS algorithms A two pass algorithm might be: 1.) Tokenize the string using white space characters. 2.) Moving from left to right, push the string into a deque if the string is not in the excluded list. If we encounter a string that is included, all proceeding tags are pushed into the deque. 3.) Then do the same from right to left. A single pass algorithm might be: 1.) Tokenize the string using white space characters. 2.) Push all tags into a pair of string:index 3.) For each pair of string and index, if the string is excluded... if the index value of all other string:index pairs before me are also excluded... My index is the beginning of the string. 4.) For each pair of string and index, if the string is excluded... if the index value of all other string:index pairs after me are also excluded... My index is the end of the string. :) I'm too lazy to write the code. Btw, I think the single pass algorithm could be implemented in a single lambda line of code. Best Wishes, -David Delaune
Randor wrote:
I think the single pass algorithm could be implemented in a single lambda line of code.
The Not-So-KISS solution.
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Quote:
Quote:text each all occurrences of a given set of strings
I think final output should be "Final output should be: " monkey horse ".
No, Chris said only the ends of the string were to be trimmed, not the centre.
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Back in the Days of Yore we had a couple of small coding challenges such as the Lean and Mean comp. I was thinking that there are a ton of small, well defined problems that can be tackled a zillion ways in a zillion languages and that it would be cool to see what you guys can come up with. I'd like to start the ball rolling with the following simple task: Problem: Given a string of text, trim from each end of the text each all occurrences of a given set of strings Sample input: Input string: "dog cat monkey dog horse dog" Strings that need to be trimmed from each end: { "dog", "cat" } Final output should be: " monkey dog horse" Final output should be " cat monkey dog horse " [Edit: My final sample output was incorrect, so to be fair I'll accept either answer] It's up to you whether you worry about case sensitivity. Let's see who can provide the smallest, neatest most elegant, most unique and/or fastest code. For those who feel like jumping on the "No Programming questions" bandwagon, please re-read the lounge guidelines. The point of this is to have fun, not to solve each other's programming issues.
cheers, Chris Maunder The Code Project | Co-founder Microsoft C++ MVP
Just out of fun as this is fun I created this in VB.NET
Private Sub Button2_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button2.Click
Dim Input As String = "dog cat monkey dog horse dog"
Dim ToRemove As String() = New String() {"dog", "cat"}
Dim Start As Integer = 0
Dim EndPointer As Integer = 0For Each Value As String In ToRemove If Start < Input.IndexOf(Value) Then Start = Input.IndexOf(Value) + Value.Length If EndPointer < Input.LastIndexOf(Value) Then EndPointer = Input.LastIndexOf(Value) Next MessageBox.Show(Input.Substring(Start, (EndPointer - Start))) End SubLobster Thermidor aux crevettes with a Mornay sauce, served in a Provençale manner with shallots and aubergines, garnished with truffle pate, brandy and a fried egg on top and Spam - Monty Python Spam Sketch
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Back in the Days of Yore we had a couple of small coding challenges such as the Lean and Mean comp. I was thinking that there are a ton of small, well defined problems that can be tackled a zillion ways in a zillion languages and that it would be cool to see what you guys can come up with. I'd like to start the ball rolling with the following simple task: Problem: Given a string of text, trim from each end of the text each all occurrences of a given set of strings Sample input: Input string: "dog cat monkey dog horse dog" Strings that need to be trimmed from each end: { "dog", "cat" } Final output should be: " monkey dog horse" Final output should be " cat monkey dog horse " [Edit: My final sample output was incorrect, so to be fair I'll accept either answer] It's up to you whether you worry about case sensitivity. Let's see who can provide the smallest, neatest most elegant, most unique and/or fastest code. For those who feel like jumping on the "No Programming questions" bandwagon, please re-read the lounge guidelines. The point of this is to have fun, not to solve each other's programming issues.
cheers, Chris Maunder The Code Project | Co-founder Microsoft C++ MVP
I have discovered a truly marvellous solution of this, which the margin of this website is too narrow to contain.
Ideological Purity is no substitute for being able to stick your thumb down a pipe to stop the water
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Quote:
Quote:text each all occurrences of a given set of strings
I think final output should be "Final output should be: " monkey horse ".
No as you are removing all instances of dog and cat from the string and not from either end of the string
Lobster Thermidor aux crevettes with a Mornay sauce, served in a Provençale manner with shallots and aubergines, garnished with truffle pate, brandy and a fried egg on top and Spam - Monty Python Spam Sketch
-
Back in the Days of Yore we had a couple of small coding challenges such as the Lean and Mean comp. I was thinking that there are a ton of small, well defined problems that can be tackled a zillion ways in a zillion languages and that it would be cool to see what you guys can come up with. I'd like to start the ball rolling with the following simple task: Problem: Given a string of text, trim from each end of the text each all occurrences of a given set of strings Sample input: Input string: "dog cat monkey dog horse dog" Strings that need to be trimmed from each end: { "dog", "cat" } Final output should be: " monkey dog horse" Final output should be " cat monkey dog horse " [Edit: My final sample output was incorrect, so to be fair I'll accept either answer] It's up to you whether you worry about case sensitivity. Let's see who can provide the smallest, neatest most elegant, most unique and/or fastest code. For those who feel like jumping on the "No Programming questions" bandwagon, please re-read the lounge guidelines. The point of this is to have fun, not to solve each other's programming issues.
cheers, Chris Maunder The Code Project | Co-founder Microsoft C++ MVP
Perl, perhaps. One line, maybe two.
Just along for the ride. "the meat from that butcher is just the dogs danglies, absolutely amazing cuts of beef." - DaveAuld (2011)
"No, that is just the earthly manifestation of the Great God Retardon." - Nagy Vilmos (2011) "It is the celestial scrotum of good luck!" - Nagy Vilmos (2011) -
How can anything be described as "Most Unique"? Unique is an absolute, it either is or isn't. Perhaps "Most Elegant" would be a more apposite epithet?
------------------------------------ I will never again mention that I was the poster of the One Millionth Lounge Post, nor that it was complete drivel. Dalek Dave CCC Link[^] Trolls[^]
You going to code or are you going to nitpick? ;)
cheers, Chris Maunder The Code Project | Co-founder Microsoft C++ MVP
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Back in the Days of Yore we had a couple of small coding challenges such as the Lean and Mean comp. I was thinking that there are a ton of small, well defined problems that can be tackled a zillion ways in a zillion languages and that it would be cool to see what you guys can come up with. I'd like to start the ball rolling with the following simple task: Problem: Given a string of text, trim from each end of the text each all occurrences of a given set of strings Sample input: Input string: "dog cat monkey dog horse dog" Strings that need to be trimmed from each end: { "dog", "cat" } Final output should be: " monkey dog horse" Final output should be " cat monkey dog horse " [Edit: My final sample output was incorrect, so to be fair I'll accept either answer] It's up to you whether you worry about case sensitivity. Let's see who can provide the smallest, neatest most elegant, most unique and/or fastest code. For those who feel like jumping on the "No Programming questions" bandwagon, please re-read the lounge guidelines. The point of this is to have fun, not to solve each other's programming issues.
cheers, Chris Maunder The Code Project | Co-founder Microsoft C++ MVP
No to be pedantic about things, bit if you're tokenizing based on "dog" and "cat", your final answer should be " monkey dog horse " (begins with 2 spaces) or "monkey dog horse " (begins with no space). Otherwise, the requirement on what to do with spaces is incomplete. :)
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Back in the Days of Yore we had a couple of small coding challenges such as the Lean and Mean comp. I was thinking that there are a ton of small, well defined problems that can be tackled a zillion ways in a zillion languages and that it would be cool to see what you guys can come up with. I'd like to start the ball rolling with the following simple task: Problem: Given a string of text, trim from each end of the text each all occurrences of a given set of strings Sample input: Input string: "dog cat monkey dog horse dog" Strings that need to be trimmed from each end: { "dog", "cat" } Final output should be: " monkey dog horse" Final output should be " cat monkey dog horse " [Edit: My final sample output was incorrect, so to be fair I'll accept either answer] It's up to you whether you worry about case sensitivity. Let's see who can provide the smallest, neatest most elegant, most unique and/or fastest code. For those who feel like jumping on the "No Programming questions" bandwagon, please re-read the lounge guidelines. The point of this is to have fun, not to solve each other's programming issues.
cheers, Chris Maunder The Code Project | Co-founder Microsoft C++ MVP
static void Main(string[] args)
{
string testString = "dog cat monkey dog horse dog";
List splitString = new List(testString.Trim().Split(new char[]{' '}));
for (int index = 0; index < splitString.Count; index++)
{
if (splitString[0].Trim().Equals("dog") || splitString[0].Trim().Equals("cat"))
splitString.RemoveAt(0);
else if (splitString[splitString.Count - 1].Trim().Equals("dog") || splitString[splitString.Count - 1].Trim().Equals("cat"))
splitString.RemoveAt(splitString.Count - 1);
else
break;
index = 0;
}
string final = "";
foreach (var entry in splitString)
final += entry + " ";
Console.WriteLine(final.Trim());
Console.ReadKey();
}No matter how long he who laughs last laughs, he who laughs first has a head start!
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How should whitespace at the ends of the input string be treated - does " cat dog " match or only "cat dog"?
The challenge is to remove the strings that are provided. Nothing is said about removing (or, indeed, caring about, whitespace)
cheers, Chris Maunder The Code Project | Co-founder Microsoft C++ MVP
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// Well, this is my piece (C#): static void main(string[] args) { string Input = "doc cat monkey dog horse dog"; List listDeleteStart = new List(); List ListDeleteEnd = new List (); //Output = " monkey dog horse " string[] toTrim = new string[] {"dog", "cat"}; string[] InputStrip = Input.Split(new char[] {' '}); int iCounter = 0; //Going forwards foreach(string strSingle in InputString) { if(toTrim.Contains(strSingle)) ListDeleteStart.Add(iCounter); else break; iCounter++; } //Going backwards InputString = InputString.Reverse().ToArray(); iCounter = InputString.Length-1; foreach(string strSingleRev in InputString) { if(toTrim.Contains(strSingleRev)) ListDeleteStart.Add(iCounter); else break; iCounter--; } //Putting it back again for analysis InputString = InputString.Reverse().ToArray(); string Output = ""; iCounter = 0; foreach (string strResult in InputString) { if(!listDeleteStart.Contains(iCounter) && !listDeletedEnd.Contains(iCounter)) Output+= " " + strResult + " "; iCounter++; } Console.WriteLine(Output); Console.ReadKey(); }
