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LoMaPuz

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  • K killabyte

    378

    A Offline
    A Offline
    AspDotNetDev
    wrote on last edited by
    #9

    It's neither 378 nor 379.

    Thou mewling ill-breeding pignut!

    K 1 Reply Last reply
    0
    • A AspDotNetDev

      Nope. Somebody is going to get the answer by chance at this rate. :rolleyes:

      Thou mewling ill-breeding pignut!

      L Offline
      L Offline
      Lost User
      wrote on last edited by
      #10

      But I can justify my answer Your numbers 1,1,3,8,55,... Fibonacci - with yours marked by X

      0,
      1, X First pair of numbers
      1, X <-- next number
      2, < Gap of one number
      3, X Second pair of numbers
      5,
      8, X <-- next number +1
      13,
      21, < Gap of three numbers
      34,
      55, X Third pair of numbers
      89,
      144,
      233, Z <-- next number plus 2
      377,
      610,
      987

      So the sequence is pairs from the Fibonacci series, the gap between successive pairs increasing (1,3... presumably 5, 7, 9) while the gaps between each number in the pair increases by 1)

      MVVM# - See how I did MVVM my way ___________________________________________ Man, you're a god. - walterhevedeich 26/05/2011 .\\axxx (That's an 'M')

      A 1 Reply Last reply
      0
      • A AspDotNetDev

        It's neither 378 nor 379.

        Thou mewling ill-breeding pignut!

        K Offline
        K Offline
        killabyte
        wrote on last edited by
        #11

        must be 2584 then

        1 Reply Last reply
        0
        • A AspDotNetDev

          Logic / Math Puzzle... 1=1 2=1 3=3 4=8 5=55 6=? This is the first puzzle I've devised myself. I hope you don't solve it too fast. :)

          Thou mewling ill-breeding pignut!

          S Offline
          S Offline
          Samuel Cragg
          wrote on last edited by
          #12

          Excel says the formula is y = 1.5833x4 - 15.667x3 + 55.417x2 - 80.333x + 40 so I get 221 for 6!?

          S A 2 Replies Last reply
          0
          • A AspDotNetDev

            Logic / Math Puzzle... 1=1 2=1 3=3 4=8 5=55 6=? This is the first puzzle I've devised myself. I hope you don't solve it too fast. :)

            Thou mewling ill-breeding pignut!

            K Offline
            K Offline
            killabyte
            wrote on last edited by
            #13

            must be 2584 then what is the prize good sir?

            1 Reply Last reply
            0
            • L Lost User

              But I can justify my answer Your numbers 1,1,3,8,55,... Fibonacci - with yours marked by X

              0,
              1, X First pair of numbers
              1, X <-- next number
              2, < Gap of one number
              3, X Second pair of numbers
              5,
              8, X <-- next number +1
              13,
              21, < Gap of three numbers
              34,
              55, X Third pair of numbers
              89,
              144,
              233, Z <-- next number plus 2
              377,
              610,
              987

              So the sequence is pairs from the Fibonacci series, the gap between successive pairs increasing (1,3... presumably 5, 7, 9) while the gaps between each number in the pair increases by 1)

              MVVM# - See how I did MVVM my way ___________________________________________ Man, you're a god. - walterhevedeich 26/05/2011 .\\axxx (That's an 'M')

              A Offline
              A Offline
              AspDotNetDev
              wrote on last edited by
              #14

              You are on the right track, but still not correct. I can tell you the answer if you want the pain to end. ;P

              Thou mewling ill-breeding pignut!

              1 Reply Last reply
              0
              • S Samuel Cragg

                Excel says the formula is y = 1.5833x4 - 15.667x3 + 55.417x2 - 80.333x + 40 so I get 221 for 6!?

                S Offline
                S Offline
                SCraw2855
                wrote on last edited by
                #15

                I got another beer....still haven't figured it out on my end. ;P

                Something worth reading, albeit it's invincible!

                1 Reply Last reply
                0
                • S Samuel Cragg

                  Excel says the formula is y = 1.5833x4 - 15.667x3 + 55.417x2 - 80.333x + 40 so I get 221 for 6!?

                  A Offline
                  A Offline
                  AspDotNetDev
                  wrote on last edited by
                  #16

                  Nice try, but you did not excel at getting the correct answer.

                  Thou mewling ill-breeding pignut!

                  1 Reply Last reply
                  0
                  • A AspDotNetDev

                    Logic / Math Puzzle... 1=1 2=1 3=3 4=8 5=55 6=? This is the first puzzle I've devised myself. I hope you don't solve it too fast. :)

                    Thou mewling ill-breeding pignut!

                    A Offline
                    A Offline
                    AspDotNetDev
                    wrote on last edited by
                    #17

                    144 Points to anybody who can describe the pattern.

                    Thou mewling ill-breeding pignut!

                    1 Reply Last reply
                    0
                    • A AspDotNetDev

                      Logic / Math Puzzle... 1=1 2=1 3=3 4=8 5=55 6=? This is the first puzzle I've devised myself. I hope you don't solve it too fast. :)

                      Thou mewling ill-breeding pignut!

                      P Offline
                      P Offline
                      Peter_in_2780
                      wrote on last edited by
                      #18

                      Two shots: a. 144 b. 987 If one of these is right, I'll tell you where they came from! ;P Cheers, Peter [edit] should have refreshed! Didn't see your answer just above. [/edit]

                      Software rusts. Simon Stephenson, ca 1994.

                      A 1 Reply Last reply
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                      • P Peter_in_2780

                        Two shots: a. 144 b. 987 If one of these is right, I'll tell you where they came from! ;P Cheers, Peter [edit] should have refreshed! Didn't see your answer just above. [/edit]

                        Software rusts. Simon Stephenson, ca 1994.

                        A Offline
                        A Offline
                        AspDotNetDev
                        wrote on last edited by
                        #19

                        Both of those are correct. I think you have the solution. What is it?

                        Thou mewling ill-breeding pignut!

                        P L 2 Replies Last reply
                        0
                        • A AspDotNetDev

                          Both of those are correct. I think you have the solution. What is it?

                          Thou mewling ill-breeding pignut!

                          P Offline
                          P Offline
                          Peter_in_2780
                          wrote on last edited by
                          #20

                          a. Prime-indexed terms of the standard Fibonacci sequence b. Knuth's Fibonacci (or circle) product or, (where they came from) sequences A121567 and A101361 from the Online Encyclopedia of Integer Sequences[^] Just type "1,1,3,8,55" into the search box. That URL is a wonderful timewaster (and might even impress those who peek over your shoulder! :-D ) Cheers, Peter

                          Software rusts. Simon Stephenson, ca 1994.

                          A B 2 Replies Last reply
                          0
                          • P Peter_in_2780

                            a. Prime-indexed terms of the standard Fibonacci sequence b. Knuth's Fibonacci (or circle) product or, (where they came from) sequences A121567 and A101361 from the Online Encyclopedia of Integer Sequences[^] Just type "1,1,3,8,55" into the search box. That URL is a wonderful timewaster (and might even impress those who peek over your shoulder! :-D ) Cheers, Peter

                            Software rusts. Simon Stephenson, ca 1994.

                            A Offline
                            A Offline
                            AspDotNetDev
                            wrote on last edited by
                            #21

                            You have just been awarded more points than I have ever awarded anybody! Sure, they're virtual points, but still. That's crazy that there's a website that actually lists that sequence. You are correct. This is how I would represent the sequence: f(n) = NthFibonacci(NthPrime(n)) Assuming the 1st Fibonacci number is 0 and the first prime is 2.

                            Thou mewling ill-breeding pignut!

                            1 Reply Last reply
                            0
                            • A AspDotNetDev

                              Both of those are correct. I think you have the solution. What is it?

                              Thou mewling ill-breeding pignut!

                              L Offline
                              L Offline
                              leppie
                              wrote on last edited by
                              #22

                              AspDotNetDev wrote:

                              Both of those are correct.

                              That's BS!

                              IronScheme
                              ((λ (x) `(,x ',x)) '(λ (x) `(,x ',x)))

                              A 1 Reply Last reply
                              0
                              • L leppie

                                AspDotNetDev wrote:

                                Both of those are correct.

                                That's BS!

                                IronScheme
                                ((λ (x) `(,x ',x)) '(λ (x) `(,x ',x)))

                                A Offline
                                A Offline
                                AspDotNetDev
                                wrote on last edited by
                                #23

                                They are the 6th and 7th elements of the sequence. Upset you didn't figure it out? ;P

                                Thou mewling ill-breeding pignut!

                                L 1 Reply Last reply
                                0
                                • A AspDotNetDev

                                  They are the 6th and 7th elements of the sequence. Upset you didn't figure it out? ;P

                                  Thou mewling ill-breeding pignut!

                                  L Offline
                                  L Offline
                                  leppie
                                  wrote on last edited by
                                  #24

                                  AspDotNetDev wrote:

                                  Upset you didn't figure it out?

                                  No, upset at you for being ambiguous! ;p Thought it was both correct for 6 :(

                                  IronScheme
                                  ((λ (x) `(,x ',x)) '(λ (x) `(,x ',x)))

                                  1 Reply Last reply
                                  0
                                  • Richard Andrew x64R Richard Andrew x64

                                    42

                                    The difficult we do right away... ...the impossible takes slightly longer.

                                    V Offline
                                    V Offline
                                    V 0
                                    wrote on last edited by
                                    #25

                                    You're cheating ! That's ALWAYS a correct answer. And moreover, it's my cheat, my own, my precious :-D .

                                    V.

                                    1 Reply Last reply
                                    0
                                    • A AspDotNetDev

                                      Logic / Math Puzzle... 1=1 2=1 3=3 4=8 5=55 6=? This is the first puzzle I've devised myself. I hope you don't solve it too fast. :)

                                      Thou mewling ill-breeding pignut!

                                      B Offline
                                      B Offline
                                      Brisingr Aerowing
                                      wrote on last edited by
                                      #26

                                      How about the 'Eban' numbers? 2, 4, 6, 30, 32, 34, 36, 40, 42, 44, 46, ... [EDIT] Or the 'emirps'? 13, 17, 31, 37, 71, 73, 79, 97, 107, 113, ... Get it? Or not?

                                      Public Sub GetOffTheComputer() Throw New NotImplementedException() End Sub

                                      1 Reply Last reply
                                      0
                                      • P Peter_in_2780

                                        a. Prime-indexed terms of the standard Fibonacci sequence b. Knuth's Fibonacci (or circle) product or, (where they came from) sequences A121567 and A101361 from the Online Encyclopedia of Integer Sequences[^] Just type "1,1,3,8,55" into the search box. That URL is a wonderful timewaster (and might even impress those who peek over your shoulder! :-D ) Cheers, Peter

                                        Software rusts. Simon Stephenson, ca 1994.

                                        B Offline
                                        B Offline
                                        Brisingr Aerowing
                                        wrote on last edited by
                                        #27

                                        Peter_in_2780 wrote:

                                        That URL is a wonderful timewaster

                                        I am now officially addicted to that site. It is a browser narcotic for nerds (sorry if I offended anyone!) -Z a.k.a. 'The Nerdinator' (don't ask...)

                                        Public Sub GetOffTheComputer() Throw New NotImplementedException() End Sub

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