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  4. Alternative to Application.StartupPath

Alternative to Application.StartupPath

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  • M MichCl

    I have a class that gets it's startup path using the following:

    String myPath = Application.StartupPath;

    This worked fine with it's own test form, but once I was referring to this class from another class in a different directory, it returns the wrong directory. Is there a c# way to get the directory of the class and not the class that calls it? Thanks for any help!

    B Offline
    B Offline
    BobJanova
    wrote on last edited by
    #5

    Assembly.GetExecutingAssembly().Location.

    L 1 Reply Last reply
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    • B BobJanova

      Uh, surely that will tell you where mscorlib is?

      L Offline
      L Offline
      Lost User
      wrote on last edited by
      #6

      Yes. Do you think I should have said that I used "string" as an example type?

      Bastard Programmer from Hell :suss:

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      • B BobJanova

        Assembly.GetExecutingAssembly().Location.

        L Offline
        L Offline
        Lost User
        wrote on last edited by
        #7

        Surely, that returns the location of the executing assembly? :-D

        TopicStarter wrote:

        Is there a c# way to get the directory of the class and not the class that calls it?"

        Bastard Programmer from Hell :suss:

        B 1 Reply Last reply
        0
        • L Lost User

          Surely, that returns the location of the executing assembly? :-D

          TopicStarter wrote:

          Is there a c# way to get the directory of the class and not the class that calls it?"

          Bastard Programmer from Hell :suss:

          B Offline
          B Offline
          BobJanova
          wrote on last edited by
          #8

          Yes, but 'the class' surely refers to the current class, which will be in the executing assembly. That's how I read it, anyway.

          L M 2 Replies Last reply
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          • B BobJanova

            Yes, but 'the class' surely refers to the current class, which will be in the executing assembly. That's how I read it, anyway.

            L Offline
            L Offline
            Lost User
            wrote on last edited by
            #9

            Yup, sounds logical too. It must be either time for coffee, or for some sleep :)

            Bastard Programmer from Hell :suss:

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            • M MichCl

              I have a class that gets it's startup path using the following:

              String myPath = Application.StartupPath;

              This worked fine with it's own test form, but once I was referring to this class from another class in a different directory, it returns the wrong directory. Is there a c# way to get the directory of the class and not the class that calls it? Thanks for any help!

              M Offline
              M Offline
              MichCl
              wrote on last edited by
              #10

              To clarify: main program is in directory A main program uses sub-program in directory B I need to get the directory of B programatically. Wouldn't anything referring to executing assembly refer to the location of main program in directory A? Since I am referring to program B in program A, the dll or exe is copied to program A's directory, so getting that location would return program A's location, not program B. I have a file I need to use/get in dir B. A->B and B is trying to open a file in it's directory but I'm getting the location of A because A is the application startup path (and executing assembly,no?). Sorry for the confusion! I hope that this makes it more clear!

              C L 2 Replies Last reply
              0
              • B BobJanova

                Yes, but 'the class' surely refers to the current class, which will be in the executing assembly. That's how I read it, anyway.

                M Offline
                M Offline
                MichCl
                wrote on last edited by
                #11

                Thanks for the input, guys. See my clarification at the end here. :)

                1 Reply Last reply
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                • M MichCl

                  To clarify: main program is in directory A main program uses sub-program in directory B I need to get the directory of B programatically. Wouldn't anything referring to executing assembly refer to the location of main program in directory A? Since I am referring to program B in program A, the dll or exe is copied to program A's directory, so getting that location would return program A's location, not program B. I have a file I need to use/get in dir B. A->B and B is trying to open a file in it's directory but I'm getting the location of A because A is the application startup path (and executing assembly,no?). Sorry for the confusion! I hope that this makes it more clear!

                  C Offline
                  C Offline
                  Cracked Down
                  wrote on last edited by
                  #12

                  Is directory of the B is relative to the A's directory then you can calculate the path for B's directory get the App path and then add directories or remove directories depending on the B's location... Assuming that B's directory does not change with respect to A's Happy Coding :)

                  M 1 Reply Last reply
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                  • M MichCl

                    To clarify: main program is in directory A main program uses sub-program in directory B I need to get the directory of B programatically. Wouldn't anything referring to executing assembly refer to the location of main program in directory A? Since I am referring to program B in program A, the dll or exe is copied to program A's directory, so getting that location would return program A's location, not program B. I have a file I need to use/get in dir B. A->B and B is trying to open a file in it's directory but I'm getting the location of A because A is the application startup path (and executing assembly,no?). Sorry for the confusion! I hope that this makes it more clear!

                    L Offline
                    L Offline
                    Lost User
                    wrote on last edited by
                    #13

                    As I pointed out earlier this command returns the path of the executable program. It does not matter where the various components used to build that executable are stored.

                    speaking as ...

                    M 1 Reply Last reply
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                    • C Cracked Down

                      Is directory of the B is relative to the A's directory then you can calculate the path for B's directory get the App path and then add directories or remove directories depending on the B's location... Assuming that B's directory does not change with respect to A's Happy Coding :)

                      M Offline
                      M Offline
                      MichCl
                      wrote on last edited by
                      #14

                      That's a good idea. A's directory is blah/blah1/blah2/tool/tool/bin/Debug and then B's directory could be found by appending it's location onto blah/blah1/blah2.

                      1 Reply Last reply
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                      • L Lost User

                        As I pointed out earlier this command returns the path of the executable program. It does not matter where the various components used to build that executable are stored.

                        speaking as ...

                        M Offline
                        M Offline
                        MichCl
                        wrote on last edited by
                        #15

                        But B's exe file is referenced by program A, so A copies the exe file to A's Debug directory. So getting the exe location would return A's dir and not B's.

                        L 1 Reply Last reply
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                        • M MichCl

                          But B's exe file is referenced by program A, so A copies the exe file to A's Debug directory. So getting the exe location would return A's dir and not B's.

                          L Offline
                          L Offline
                          Lost User
                          wrote on last edited by
                          #16

                          Exactly, and that is why it does not work. When you start an executable program Windows makes a note of its location and it is that location that will be returned. Program A can only ever find program A's directory. Maybe if you explain what problem you are actually trying to solve people will be able to give some better suggestions.

                          speaking as ...

                          M 1 Reply Last reply
                          0
                          • M MichCl

                            I have a class that gets it's startup path using the following:

                            String myPath = Application.StartupPath;

                            This worked fine with it's own test form, but once I was referring to this class from another class in a different directory, it returns the wrong directory. Is there a c# way to get the directory of the class and not the class that calls it? Thanks for any help!

                            M Offline
                            M Offline
                            MichCl
                            wrote on last edited by
                            #17

                            Hi guys. I'm going to call this since I decided what I'm going to do. For anyone looking at this post in the future, this is what I figured out. I'm new to c# programming (3 months experience), so this is my first program (in this language and with visual studio). Apparently, once this is released, all of the executables will be put in the same directory as the calling application directory, so the debug subdirectories will be gone. So I need to put my file referenced by B into A's directory. Thanks for all the help!! :) :^) Have a great Memorial Day weekend and enjoy!

                            1 Reply Last reply
                            0
                            • L Lost User

                              Exactly, and that is why it does not work. When you start an executable program Windows makes a note of its location and it is that location that will be returned. Program A can only ever find program A's directory. Maybe if you explain what problem you are actually trying to solve people will be able to give some better suggestions.

                              speaking as ...

                              M Offline
                              M Offline
                              MichCl
                              wrote on last edited by
                              #18

                              Right. It does not work. Thanks for helping!

                              1 Reply Last reply
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