how to get date difference

[User 9106259]

hi i have 4 fields like as bellow 1.start date 2.start time 3.end date 4.end time by using above fields how can i get difference in hours in php project any body can help me. thank you.

[Peter_in_2780]

A little RTFM goes a long way. Open up the PHP manual (online if you were too stupid or lazy to download a free copy) and type "date difference" into the search box. Work with DateTime and DateInterval objects. Peter

Software rusts. Simon Stephenson, ca 1994. So does this signature. me, 2012

[User 9106259]

that is not happening so that only posted.

[Peter_in_2780]

?????? Try this link[^] then.

Software rusts. Simon Stephenson, ca 1994. So does this signature. me, 2012

[Deepthi 21456]

<?php
$date1 = "2012-10-04 22:45:00";
$date2 = "2013-12-05 13:44:01";
$diff = abs(strtotime($date2) - strtotime($date1));
$years = floor($diff / (365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
$hours = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24)/ (60*60));
$minuts = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24 - $hours*60*60)/ 60);
$seconds = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24 - $hours*60*60 - $minuts*60));
printf("%d years, %d months, %d days, %d hours, %d minuts\n, %d seconds\n", $years, $months, $days, $hours, $minuts, $seconds);
die;
?>

[Anilannu]

What is your project... how you help me if i help u

@n!L

[Mohibur Rashid]

If you searched on google you would find 1000's of solutions. this is copied from PHP site

<?php
$td = time_diff($timestamp1-$timestamp2); // has to be a positive result
$td .= ($td=="now")? "":" ago"; // in this example "ago"
echo $td;

function time_diff($s){

$time = get\_post\_time('G', true, $post);
$s = time() - $time;

if($s>=1) {
$td = "$s sec";
}  

if($s>59) {
    $m = (int)($s/60);
    $s = $s-($m\*60); // sec left over
    $td = "$m min"; if($s>1) $td .="s";
}
if($m>59){
    $hr = (int)($m/60);
    $m = $m-($hr\*60); // min left over
    $td = "$hr hr"; if($hr>1) $td .= "s";
    if($m>0) $td .= ", $m min";
}
if($hr>23){
    $d = (int)($hr/24);
    $hr = $hr-($d\*24); // hr left over
    $td = "$d day"; if($d>1) $td .= "s";
    if($d<3){
        if($hr>0) $td .= ", $hr hr"; if($hr>1) $td .= "s";
    }
}
return $td;

}
?>

I wish I could believe there is an after life.