Question of a dusy_dex
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Anlamadığınız şey nedir?
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I am living in turkey.. You are older than me 1 year :) I'm 39 years old. Me hakan and Glad to meet you Thankyou for everything... and issue is not computer literature word.
Hello. :-D I am a bit older than 40. the greater than symbol (>) was a clue. :) Benim kod tamam mı? Have a go with Bing translator www.bing.com/translator Proje kodu Yöneticiler üzgün değil deneyin. :wtf:
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.
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Are you trying to copy the numbers so that you start another week's draw? You can't use delete that way for arrays elements. But your code still doesn't make any sense. There are no shortcuts to comparing *all* elements of one array using one command. You need to compare each element of arrIns one by one, with oel[i] then copy *that element* to arr
var arr = []; // You do *not* need to use new Array
var c = 0;for (var i=0; i < oel.length; i++) {
var e = 0;
while (e < arrIns.length) {
if (oel[i] != arrIns[e]) {
arr[c] = oel[i];
c++;
}
e++;
} // while-loop} // for-loop
oel.length = 0; // reset oel array length to zero, so that you can use the array again"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.
I just got a 39, in march 02 :).. I think there is a little misunderstanding here. 1 ... 49 number of the remaining elements of the numbers array of the last 3 weeks trying to get the lucky numbers, I was try to do, just as.
if(oel[i] != arrIns[11])
{ oel[i]; }; // When i wrote document.write(oel[i] code in this line I can archive these numbers.delete oel[i];
Quote:
that is exactly the last 3 weeks I wanted to get back remaining array of numbers. The number that is 49 - 18 = 31
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I just got a 39, in march 02 :).. I think there is a little misunderstanding here. 1 ... 49 number of the remaining elements of the numbers array of the last 3 weeks trying to get the lucky numbers, I was try to do, just as.
if(oel[i] != arrIns[11])
{ oel[i]; }; // When i wrote document.write(oel[i] code in this line I can archive these numbers.delete oel[i];
Quote:
that is exactly the last 3 weeks I wanted to get back remaining array of numbers. The number that is 49 - 18 = 31
[ I am mostly working from my memory, and it is getting difficult. ] Ben çok benim hafızasından çalışıyorum ve bu zor gidiyor. Yani, bu ekler:
// add this after the line } // while-loop
document.write(arr.toString());[ Let me know if that output is what you expected. If not you will have to try posting your current code, so that I can see it all in one go, and not have to try an put this all together in my head ] Bu çıktı beklediğiniz ise bizi. Aksi takdirde, geçerli deftere nakil ki ben her tek seferde görmek ve bir yerine hep birlikte kafamın içinde denemek zorunda değil denemek gerekecek. :sigh:
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.
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I just got a 39, in march 02 :).. I think there is a little misunderstanding here. 1 ... 49 number of the remaining elements of the numbers array of the last 3 weeks trying to get the lucky numbers, I was try to do, just as.
if(oel[i] != arrIns[11])
{ oel[i]; }; // When i wrote document.write(oel[i] code in this line I can archive these numbers.delete oel[i];
Quote:
that is exactly the last 3 weeks I wanted to get back remaining array of numbers. The number that is 49 - 18 = 31
[ I originally asked you (in your earlier posts) ] Başlangıçta (önceki mesaj) sordum Q1. nasıl ne zaman rasgele şanslı numaraları öncekilerin yerine üretilen karar veriyorsunuz? S2. Yeni piyango numarası + şanslı numaraları (otomatik olarak) geçerli tarihi & zamanında üretilmektedir? [ The problem as I see it, is that you need some *automatic* method to keep track of the current week's lucky numbers, and discard the oldest. Week-2 I did it that way with my BASIC program 20+ years ago so that I wouldn't need to keep adjusting the code for extra 6 numbers every week. ] Sorun görüyorum, bazı ihtiyacınız olduğunu * otomatik * yöntem geçerli haftaki şanslı numaralar izlemenize ve en eski atmak için. Hafta-2 Ben fazladan 6 sayı kodunu ayarlama tutmak gerek olmaz bu şekilde temel programım ile 20 + yıl önce her hafta yaptım. [ is the translator good? ] Çevirmen iyi mi?
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.
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[ I originally asked you (in your earlier posts) ] Başlangıçta (önceki mesaj) sordum Q1. nasıl ne zaman rasgele şanslı numaraları öncekilerin yerine üretilen karar veriyorsunuz? S2. Yeni piyango numarası + şanslı numaraları (otomatik olarak) geçerli tarihi & zamanında üretilmektedir? [ The problem as I see it, is that you need some *automatic* method to keep track of the current week's lucky numbers, and discard the oldest. Week-2 I did it that way with my BASIC program 20+ years ago so that I wouldn't need to keep adjusting the code for extra 6 numbers every week. ] Sorun görüyorum, bazı ihtiyacınız olduğunu * otomatik * yöntem geçerli haftaki şanslı numaralar izlemenize ve en eski atmak için. Hafta-2 Ben fazladan 6 sayı kodunu ayarlama tutmak gerek olmaz bu şekilde temel programım ile 20 + yıl önce her hafta yaptım. [ is the translator good? ] Çevirmen iyi mi?
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.
You were right .. has no need to use new delete method to do this.
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You were right .. has no need to use new delete method to do this.
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[ I am mostly working from my memory, and it is getting difficult. ] Ben çok benim hafızasından çalışıyorum ve bu zor gidiyor. Yani, bu ekler:
// add this after the line } // while-loop
document.write(arr.toString());[ Let me know if that output is what you expected. If not you will have to try posting your current code, so that I can see it all in one go, and not have to try an put this all together in my head ] Bu çıktı beklediğiniz ise bizi. Aksi takdirde, geçerli deftere nakil ki ben her tek seferde görmek ve bir yerine hep birlikte kafamın içinde denemek zorunda değil denemek gerekecek. :sigh:
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.
// add this after the line } // while-loop
document.write(arr.toString());
//instead of arr[add++] method is better useful in this line.I have just wanted to do this.
var arrIns = [ "1","21","24","28","42","48",
"12","23","34","36","37","46",
"3","18","19","25","44","45" ];var arrLot = [];
var arr = [];
var add = 0;for(var i=1; i<50; i++)
{
arrLot[i] = i;
if(arrLot[i] != arrIns[0])
if(arrLot[i] != arrIns[1])
if(arrLot[i] != arrIns[2])
if(arrLot[i] != arrIns[3])
if(arrLot[i] != arrIns[4])
if(arrLot[i] != arrIns[5])
if(arrLot[i] != arrIns[6])
if(arrLot[i] != arrIns[7])
if(arrLot[i] != arrIns[8])
if(arrLot[i] != arrIns[9])
if(arrLot[i] != arrIns[10])
if(arrLot[i] != arrIns[11])
if(arrLot[i] != arrIns[12])
if(arrLot[i] != arrIns[13])
if(arrLot[i] != arrIns[14])
if(arrLot[i] != arrIns[15])
if(arrLot[i] != arrIns[16])
if(arrLot[i] != arrIns[17])
if(arrLot[i] != arrIns[18])
if(arrLot[i] != arrIns[19])
{ arr[add++] = arrLot[i];}
}// create and initialise - array to keep track of any number taken
var taken = new Array(49);
for (var i=49; i>0; i--) taken[i]=false;var lucky = \[\]; var z = 0; do{ var q = Math.round(31 \* Math.random()); if(!taken\[arr\[q\]\]) { lucky\[z\] = arr\[q\]; taken\[arr\[q\]\] = true; document.write(lucky\[z\] + " "); z++; } }while(z<6); -
// add this after the line } // while-loop
document.write(arr.toString());
//instead of arr[add++] method is better useful in this line.I have just wanted to do this.
var arrIns = [ "1","21","24","28","42","48",
"12","23","34","36","37","46",
"3","18","19","25","44","45" ];var arrLot = [];
var arr = [];
var add = 0;for(var i=1; i<50; i++)
{
arrLot[i] = i;
if(arrLot[i] != arrIns[0])
if(arrLot[i] != arrIns[1])
if(arrLot[i] != arrIns[2])
if(arrLot[i] != arrIns[3])
if(arrLot[i] != arrIns[4])
if(arrLot[i] != arrIns[5])
if(arrLot[i] != arrIns[6])
if(arrLot[i] != arrIns[7])
if(arrLot[i] != arrIns[8])
if(arrLot[i] != arrIns[9])
if(arrLot[i] != arrIns[10])
if(arrLot[i] != arrIns[11])
if(arrLot[i] != arrIns[12])
if(arrLot[i] != arrIns[13])
if(arrLot[i] != arrIns[14])
if(arrLot[i] != arrIns[15])
if(arrLot[i] != arrIns[16])
if(arrLot[i] != arrIns[17])
if(arrLot[i] != arrIns[18])
if(arrLot[i] != arrIns[19])
{ arr[add++] = arrLot[i];}
}// create and initialise - array to keep track of any number taken
var taken = new Array(49);
for (var i=49; i>0; i--) taken[i]=false;var lucky = \[\]; var z = 0; do{ var q = Math.round(31 \* Math.random()); if(!taken\[arr\[q\]\]) { lucky\[z\] = arr\[q\]; taken\[arr\[q\]\] = true; document.write(lucky\[z\] + " "); z++; } }while(z<6);[ But, isn't arrIns just going to keep getting longer every week? ] Ama arrIns sadece her hafta uzun elde tutmak için gitmiyor? [ Can you please explain what purpose is of the arrLot array, does it replace oel from last code you gave?.] Lütfen arrLot dizi oel verdiği son kodundan yerine yok amaç ne olduğunu açıklayabilir misiniz? [ One thing I am not understanding, and I have kept asking you information about, is the carry over from one week to another. That's what your code appears to be doing, but without a clear understanding, I cannot begin to grasp the way you intend manage this code any length of time. Please use the translator and give me an over view of the whole lotto process you are trying to achieve. And the methods you are using to develop with. ] :| Bir şey ben değil anlamak, ve hakkında bilgi isteyen tutmuş, taşıma üzerinden bir hafta başka olduğunu. Bu ne yapıyor olması kodunuzu görünür, ama net bir anlayış olmadan, ben uzun süre bu kodu yönetmek istediğiniz şekilde kavramak başlar olamaz. Çevirmen ve vermek beni bir yere görüntülemek tüm Loto süreci size ulaşmak için çalışıyoruz kullanın lütfen. Ve ile geliştirmek için kullandığınız yöntemleri. :)
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.
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You were right .. has no need to use new delete method to do this.
I have left the arrLot array alone for now. But this is my guess
= i// **NEW** add leading zero to numbers < 10
function zeroAdjust(n) {
var t = "0"+n;
return t.substring(t.length-2,t.length);
}// these also need leading zero if < 10
var arrIns = [ "01","21","24","28","42","48",
"12","23","34","36","37","46",
"03","18","19","25","44","45" ];var allLucky = arrIns.toString();
var arrLot = [];
var arr = [];
var count = 0;
var t;
for(var i=1; i<50; i++)
{
// force i to string then
// compare i with all lucky numbers
if (allLucky.indexOf(zeroAdjust(i)) == -1 ) {
arr[count] = i; // add +""
count++;
}
} // for-loopdocument.write("length of arr[] ="+ count +"
");I have provided this just to help you move forward (if my guess was correct) here are some more bits of code for you to look at. csv = comma,separated,values which is what you get with an array.toString() call. :)
//========== EXAMPLE ===============
// Save & Restore an array
var arrIns = [ "01","21","24","28","42","48",
"12","23","34","36","37","46",
"03","18","19","25","44","45" ];var arr_to_csv = arrIns.toString();
document.write(arr_to_csv);var arr_from_csv = [];
var tmp = arr_to_csv.split(",");for (var i=0; i < tmp.length; i++) {
arr_from_csv[i] = parseInt( tmp[i]);
document.write(arr_from_csv[i]);
}
//====================================The following code has arrIns as a N-dimensional array (3x6) of numbers, but it would complicate the code for comparisons, like the allLucky string compare above.
//========== EXAMPLE ===============
// arrIns array of 3 x 6 (not "strings")
var arrIns = [ [ 1,21,24,28,42,48],
[12,23,34,36,37,46],
[ 3,18,19,25,44,45]
];document.write("lucky numbers, one week at a time
");
for (var week=1; week < 4; week++) {
document.write("week no: "+ week +"
");for (var i=0; i < 6; i++) {
document.write(arrIns[week-1][i]);
}
}
//====================================:-D
"It's true that hard work never killed anyone. But I figure, why take the chance." - R
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You were right .. has no need to use new delete method to do this.
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Check the code project website for code changes. :)
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.
Ok... Good coding and good idea.. I will try these codes right now. :)
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[ I am mostly working from my memory, and it is getting difficult. ] Ben çok benim hafızasından çalışıyorum ve bu zor gidiyor. Yani, bu ekler:
// add this after the line } // while-loop
document.write(arr.toString());[ Let me know if that output is what you expected. If not you will have to try posting your current code, so that I can see it all in one go, and not have to try an put this all together in my head ] Bu çıktı beklediğiniz ise bizi. Aksi takdirde, geçerli deftere nakil ki ben her tek seferde görmek ve bir yerine hep birlikte kafamın içinde denemek zorunda değil denemek gerekecek. :sigh:
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.
Yes.. You are working really hard issue on!.. This is really hard to comes true in JavaScript language.
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Yes.. You are working really hard issue on!.. This is really hard to comes true in JavaScript language.
[ I was thinking back to my first reply to this thread of yours: ] Iyi, ben bu konuyu senin ilk zaman cevap geri düşünüyordum: Reading-a-text-file-in-JS [ and thought that maybe you intend to use external file with previous week's data, using string data. Yes?] ve düşündüğünüz hafta önceki verileri, dış dosya kullanılacak dize verileri kullanarak belki düşündüm. Evet? [ Anyhow, keep me informed of any problems. ] Her neyse, bana herhangi bir sorunları haberdar tutmak. :)
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.